\(a,\Leftrightarrow x-1=4\Leftrightarrow x=5\\ b,\Leftrightarrow\left\{{}\begin{matrix}x\ge\dfrac{3}{4}\\3x+1=4x-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ge\dfrac{3}{4}\\x=4\left(tm\right)\end{matrix}\right.\Leftrightarrow x=4\\ c,ĐK:x\ge-5\\ PT\Leftrightarrow2\sqrt{x+5}-3\sqrt{x+5}+4\sqrt{x+5}=6\\ \Leftrightarrow3\sqrt{x+5}=6\\ \Leftrightarrow\sqrt{x+5}=3\\ \Leftrightarrow x+5=9\\ \Leftrightarrow x=4\left(tm\right)\)

\(d,\Leftrightarrow\sqrt{\left(x-2\right)^2}=\sqrt{\left(\sqrt{5}+1\right)^2}\\ \Leftrightarrow\left|x-2\right|=\sqrt{5}+1\\ \Leftrightarrow\left[{}\begin{matrix}x-2=\sqrt{5}+1\\2-x=\sqrt{5}+1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{5}+3\\x=1-\sqrt{5}\end{matrix}\right.\)

a: =>x=3/7+3/5=15/35+21/35=36/35

b: =>x/35=4/5-5/7=28/35-25/35=3/35

=>x=3

c: =>x<3/4+8/4=11/4

=>\(x\in\left\{0;1;2;3\right\}\)

d: =>5/3<x<5/6+24/6=29/6

=>\(x\in\left\{2;3;4\right\}\)

e: =>x<10/12-9/12=1/12

=>x=0

f: =>2/3<x<12/6-5/6=7/6

=>x=1

x . ( x - \(\frac{2}{3}\)) = 0

=> x = 0 hoặc x - \(\frac{2}{3}\)= 0

=> x - \(\frac{2}{3}\)= 0

      x           = 0 + \(\frac{2}{3}\)

       x          = \(\frac{2}{3}\)

Vậy, x \(\in\){ 0, \(\frac{2}{3}\)}

~ Chúc học tốt ~

Ai ngang qua xin để lại 1 L - I - K - E

\(\frac{1}{2}+\frac{3}{4}x=\frac{1}{4}\)

\(\Leftrightarrow\frac{3}{4}x=\frac{1}{4}-\frac{1}{2}\)

\(\Leftrightarrow\frac{3}{4}x=-\frac{1}{2}\)

   \(\Leftrightarrow x=-\frac{2}{3}\)

\(\frac{5}{6}+\frac{1}{6}:x=-2\)

\(\Leftrightarrow\frac{1}{6}:x=-\frac{17}{6}\)

\(\Leftrightarrow x=-\frac{1}{17}\)

\(x\cdot\left(x-\frac{2}{3}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x-\frac{2}{3}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{2}{3}\end{cases}}\)

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Câu 6: Khôg có cau nào đúng

Câu 7: C

Câu 8: B

Câu 9: B

Câu 10: D

6Không có đáp án nào đúng x=11/4

7C

8B

9B

10D