a x3 + a + a + a x 4 = a x.......so nao thich hop dien vao o trong
cho hai tap hop: A = (a,b) ; B = ( b,x,y) dien ki hieu thich hop vao o trong: x....A y....B b....A
x ( không thuộc ) A
y ( thuộc ) B
b ( thuộc ) A
Mk ko biết viết kí hiệu thuộc và ko thuộc hì hì
GIup em voi chu so thich hop de dien vao o trong de 6 .......8<638 la so nao vay em gap lam
628 < 638
cho hai tap hop : A = { m,n,p} , B ={ m,x,y}
dien ki hieu thich hop vao o vuong : n ..... A ; p......B ; m e ......
n thuộc a hay còn gọi n E a
p ko thuộc B
me là j đó
Ta có A = { m,n,p) ; B = {m,x,y}
Vậy n \(\in\)A ; p \(\notin\)B ; m \(\in\)A , B
\(n\in A\)
\(p\notin B\)
\(m\in A;B\)
viet tap hop A cac so tu nhien lon hon 7 va nho hon 12, sau do dien ki hieu thich hop vao o vuong
viet tap hop a cac so tu nhieu lon hon 8 va nho hon 14 bang 2 cach , sau do dien ki hieu thich hop vao o vuong
C1 :A = ( 9;10;11;12;13)
C2 : A = ( x\(\in\) N / 8<x<14 )
lay vi du ve 1 tap hop
nguoi ta dat ten cho tap hop nhu the nao
viet tap hop A cac so tu nhien nho hon 5. chi ra cac phan tu cac tap hop tu A. so 1 co thuoc tap hop A hay ko, viet ki hieu. so 6 co thuoc tap hop A hay ko, viet ki hieu
viet tap hop B cac so tu nhien nho hon 6 bang 2 cach
viet tap hop D cac so tu nhien nho hon 7 roi dien ki hieu thich hop vao o vuong : 2.. D; 10..D
viet tap hop cac chu cai trong tu ''nha trang ''
nguyen dan tam sai rồi. tại sao lại có 2 chữ " n"
1) Rut gon cac bieu thuc sau :
a) (x-3)(x2+3x+ 9)-(54+x3)
b) (3x+y)(9x2-3xy +y2)-(3x-y)(9x2+3xy+y2)
2, Dien cac don thuc thich hop vao cho trong
a, (x+3y) (... - ... + ...) = x^3 +27y^3
b, (2x- ....) (... + 6xy + ... +...) = 8x^3 - 27y^3
\(1.\)
\(a.\)
\(\left(x-3\right)\left(x^2+3x+9\right)-\left(54+x^3\right)\)
\(=\left(x^3-3^3\right)-\left(54+x^3\right)\)
\(=x^3-27-54-x^3\)
\(=-81\)
\(b.\)
\(\left(3x+y\right)\left(9x^2-3xy+y^2\right)-\left(3x-y\right)\left(9x^2+3xy+y^2\right)\)
\(=\left(27x^3+y^3\right)-\left(27x^3-y^3\right)\)
\(=27x^3+y^3-27x^3+y^3\)
\(=2y^3\)
\(2.\)
\(a.\)
\(\left(x+3y\right)\left(x^2-3xy+9y^2\right)=x^3+27y^3\)
\(b.\)
\(\left(2x-3y\right)\left(4x^2+6xy+9y^3\right)=8x^3-27y^3\)
1) a) \(\left(x-3\right)\left(x^2+3x+9\right)-\left(54+x^3\right)\)
\(=\left(x^3-3^3\right)-\left(54+x^3\right)\\ =\left(x^3-27\right)-54-x^3\\ =-27-54\\ =-81\)
b) \(\left(3x+y\right)\left(9x^2-3xy+y^2\right)-\left(3x-y\right)\left(9x^2+3xy+y^2\right)\)
\(=\left[\left(3x\right)^3+y^3\right]-\left[\left(3x\right)^3-y^3\right]\\ =2y^3\)
2) a) \(\left(x+3y\right)\left(x^2-3xy+9y^2\right)=x^3+27y^3\)
b) \(\left(2x-3y\right)\left(4x^2+6xy+9y^2\right)=8x^3-27y^3\)
Dien tu thich hop vao o trong
1. She is ___________ engineer
2. My sister is a student , and I am a student , _____________
Dien tu thich hop vao o trong
1. She is ___an ________ engineer
2. My sister is a student , and I am a student , too
1. She is _______an_______ engineer
2. My sister is a student , and I am a student , ______too_______
Dien tu thich hop vao o trong
1. She is _____an______ engineer
2. My sister is a student , and I am a student , _____too________
viet tap ho a cac so tu nhienlon hon f7 va nho hon 12 sau do dien ki hieu vao o trong thich hop 9 a ,14 a
\(A=\left\{8;9;10;11\right\}\)
\(9\in A\)
\(14\notin A\)
C1 : A ={8 ; 9 ; 10 ; 11 }
C2 : A = { x \(\in\)N | 7 < x < 12 }
\(9\in A\)
\(14\notin A\)