so sanh
\(\frac{10^9}{10^9-3}\)
va
\(\frac{10^9+2}{10^9-1}\)
giai chi tiet dum minh nhoa
Những câu hỏi liên quan
So sanh cac phan so sau:
A=\(\frac{3^{10}+1}{3^9+1}\)va B=\(\frac{3^9+1}{3^8+1}\)
bn vào /h7.net/hoi-dap/toan-6/so-sanh-a-3-10-1-3-9-1-va-b-3-9-1-3-8-1--faq205231.html
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Trả lời:
A = \(\frac{3^{10}+1}{3^9+1}=\frac{3.3^9+1}{3.3^8+1}=\frac{3^9+1}{3^8+1}\)= B
_Học tốt bạn nha_
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(2^11+2^10+2^9+...+2^3+2^2+2+1):(2^8+2^4+1)
(nho trinh bay chi tiet do, ai nhanh nhat va giai chi tiet de hieu thi to tick cho)
ca ban lam on nhanh len vi chieu minh phai nop cho cho giao
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Xem thêm câu trả lời
So sanh A va B, biet :
a)\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8};B=\frac{1+3+3^2+...+3^9}{1+3+3^2+...+3^8}\)
b)\(A=\frac{7^{10}}{1+7+7^2+...+7^9};B=\frac{5^{10}}{1+5+5^2+...+5^9}\)
\(A=\frac{1+5+5^2+...+5^9}{1+5+5^2+...+5^8}=\frac{1+5\left(1 +5+5^2+...+5^8\right)}{1+5+5^2+...+5^8}=5+\frac{1}{1+5+5^2+...+5^8} \)
\(B=\frac{1+3+3^2+....+3^9}{1+3+3^2+....+3^8}=\frac{1+3\left(1+3+3^2+....+3^8\right)}{1+3+3^2+....+3^8}=3+\frac{1}{1+3+3^2+....+3^8}\)
\(=5+\frac{1}{1+3+3^2+....+3^8}-2\)
Có: \(\frac{1}{1+5+5^2+...+5^8}>0\) và \(\frac{1}{1+3+3^2+....+3^8}-2< 0\)
\(\Rightarrow A>B\)
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A=\(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)
B=\(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
So sanh A va B
A =9^9+1/9^10+1
B=10^9+1/10^10+1
so sanh a va b
A = 387420490 ; B = 1000000001
vậy B lớn hơn A
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CHO B=(1/4-1).(1/9-10....(1/100-1)
GIAI NHANH LEN MINH DANG CAN GAP
AI GIAI DUNG CHI TIET MINH K CHO 2 LIKE
\(B=\left(\frac{1}{4}-1\right)\cdot\left(\frac{1}{9}-1\right).....\left(\frac{1}{81}-1\right)\cdot\left(\frac{1}{100}-1\right)\)
\(B=\frac{-3}{4}\cdot\frac{-8}{9}....\frac{-80}{81}\cdot\frac{-99}{100}\)
\(B=-\left(\frac{3}{4}\cdot\frac{8}{9}\cdot\cdot\cdot\cdot\frac{99}{100}\right)\)
\(B=-\left(\frac{3\cdot8\cdot15\cdot24\cdot....\cdot63\cdot80\cdot99}{2^2\cdot3^2\cdot4^2\cdot\cdot\cdot\cdot\cdot9^2\cdot10^2}\right)\)
\(B=-\left(\frac{1\cdot3\cdot2\cdot4\cdot3\cdot5\cdot\cdot\cdot\cdot8\cdot10\cdot9\cdot11}{2^2\cdot3^2\cdot4^2\cdot\cdot\cdot\cdot9^2\cdot10^2}\right)\)
\(B=-\frac{11}{2\cdot10}\)
\(B=\frac{-11}{20}\)
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\(B=\left(\frac{1}{4}-1\right).\left(\frac{1}{9}-1\right)...\left(\frac{1}{100}-1\right)\)
\(B=\frac{-3}{2^2}.\frac{-8}{3^2}...\frac{-99}{10^2}\)
\(B=-\left(\frac{3}{2^2}.\frac{8}{3^2}...\frac{99}{10^2}\right)\)(có 9 thừa số, mỗi thừa số là âm nên kết quả là âm)
\(B=-\left(\frac{1.3}{2.2}.\frac{2.4}{3.3}...\frac{9.11}{10.10}\right)\)
\(B=-\left(\frac{1.2...9}{2.3...10}.\frac{3.4...11}{2.3...10}\right)\)
\(B=-\left(\frac{1}{10}.\frac{11}{2}\right)\)
\(B=-\frac{11}{20}\)
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KO QUY DONG MAU HAY SO SANH
\(A=\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}\)
\(B=\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
hay so sanh m voi 1
M=\(\frac{1}{2!}+\frac{2}{3!}++......+\frac{9}{10!}\)
\(M=\frac{1}{1.2}+\frac{2}{1.2.3}+.....+\frac{9}{1.2.3.....10}\)
\(M=\frac{2-1}{1.2}+\frac{3-1}{1.2.3}+....+\frac{10-1}{1.2......10}\)
\(M=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{6}+....+\frac{10}{1.2.....10}-\frac{1}{1.2.....10}\)
\(M=1-\frac{1}{1.2.3......10}\)
\(M=1-\frac{1}{3628800}\)
Vì \(1=1\)mà \(\frac{1}{3628800}< 1\)nên \(1-\frac{1}{3628800}< 1\)
Vậy \(M< 1\)
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So sanh 3^10+1 / 3^9+1 va 3^9+1 / 3^8+1