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Ta có : \(\dfrac{2005}{2007}=1-\dfrac{2}{2007};\dfrac{2007}{2009}=1-\dfrac{2}{2009}\)

\(Do:\dfrac{2}{2007}>\dfrac{2}{2009}\Rightarrow1-\dfrac{2}{2007}< 1-\dfrac{2}{2009}\)

\(\Rightarrow\dfrac{2005}{2007}< \dfrac{2007}{2009}\)

Ta có : 

2005/2007=2007-2/2007=2007/2007 -2/2007=1 -2/2007

2007/2009 =2009-2007/2009=2009/2009 -2/2009=1-2009

vì 2007<2009 nên 2/2007>2/2009

⇒1-2/2007 <1-2/2009

⇒2005/2007 <2007/2009

Tham khảo nhé !

Ta có : \(\dfrac{2005}{2007}=2007-\dfrac{2}{2007}=\dfrac{2007}{2007}-\dfrac{2}{2007}=1-\dfrac{2}{2007}\)

\(\dfrac{2007}{2009}=2009-\dfrac{2007}{2009}=\dfrac{2009}{2009}-\dfrac{2}{2009}=1-2009\)

Vì \(2007<2009\) nên \(\dfrac{2}{2007}>\dfrac{2}{2009}\)

\(1-\dfrac{2}{2007}< 1-\dfrac{2}{2009}\)

\(\dfrac{2005}{2007}< \dfrac{2007}{2009}\)

2005/2007<2007/2009

B

`=>` `B`

Vì các phân số cồn lại thuộc dạng `(x >= 1)`

B

A

A

a

Lời giải:
Theo bài ra ta có:

$\frac{25+n}{48+n}=\frac{5}{6}$

$6\times (25+n)=5\times (48+n)$

$6\times 25+6\times n=5\times 48+5\times n$

$150+6\times n=240+5\times n$

$6\times n-5\times n=240-150$

$n\times (6-5)=90$

$n=90$

a) \(\dfrac{5}{9}< \dfrac{7}{9}\)

b) \(\dfrac{7}{6}>\dfrac{6}{6}\)

c) \(\dfrac{3}{14}< \dfrac{5}{14}\)

d) \(\dfrac{5}{8}< \dfrac{9}{8}\)

1.C

2.c

3.D

4.C

2005/2007<2007/2009