Tính
B=\(\left(17\dfrac{3535}{88375}-16\dfrac{1001}{1365}\right).3\dfrac{6}{23}+3\dfrac{6}{23}:\left(5-1\dfrac{187}{253}\right)\)
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Tính:
[(17+3535/88375)-(16+1001/1365)].(3+6/23)+(3+6/23).[5-(1+187/253)]
(17 3535/88375 - 16 1001/1365) x 3 6/23 + 3 6/23 : (5 - 1 187/253)
Hỗn số đó, để mình giải thích thích cho: 3 6/23: 3 là phần nguyên, 6/23 là phần phân số nha
lộn xộn quá cậu viết lại qua kí tự " gõ công thức toán đi"
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Mk gõ lại cho
\(\left(\frac{173535}{88375}-\frac{161001}{1365}\right)x3\frac{6}{23}:\left(5-1\frac{187}{253}\right)\)
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5dfrac{5}{27}+dfrac{7}{23}-0,5.dfrac{5}{27}+dfrac{16}{23}
45dfrac{1}{6}:left(dfrac{-4}{5}right)-35dfrac{1}{6}:left(dfrac{-4}{5}right)
25.left(dfrac{-1}{5}right)^3+dfrac{1}{5}-2.left(dfrac{-1}{2}right)^2-dfrac{1}{2}
left(3,1-2,5right)-left(-2,5-3,1right)
dfrac{3}{8}.dfrac{7}{5}-dfrac{7}{5}.dfrac{1}{8}+dfrac{13}{20}
CẦN GẤP NGAY VÀ LUÔN :)))))
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\(5\dfrac{5}{27}+\dfrac{7}{23}-0,5.\dfrac{5}{27}+\dfrac{16}{23}=\)
\(45\dfrac{1}{6}:\left(\dfrac{-4}{5}\right)-35\dfrac{1}{6}:\left(\dfrac{-4}{5}\right)=\)
\(25.\left(\dfrac{-1}{5}\right)^3+\dfrac{1}{5}-2.\left(\dfrac{-1}{2}\right)^2-\dfrac{1}{2}=\)
\(\left(3,1-2,5\right)-\left(-2,5-3,1\right)=\)
\(\dfrac{3}{8}.\dfrac{7}{5}-\dfrac{7}{5}.\dfrac{1}{8}+\dfrac{13}{20}=\)
CẦN GẤP NGAY VÀ LUÔN :)))))
a) \(\sqrt{\dfrac{81}{16}}\)- \(\left(\dfrac{-3}{2}\right)^2\) + \(\left|-\dfrac{5}{6}\right|\)
b) \(\left|3-\dfrac{23}{9}\right|\) + \(\left(\dfrac{4}{3}\right)^3\) : \(\left(\dfrac{4}{3}\right)^3\)
\(a,=\dfrac{9}{4}-\dfrac{9}{4}+\dfrac{5}{6}=\dfrac{5}{6}\\ b,=\dfrac{4}{9}+1=\dfrac{13}{9}\)
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\(A=\dfrac{\left(17\dfrac{1}{4}-4\dfrac{3}{16}-13\dfrac{5}{6}\right).\left(\dfrac{-4}{7}\right)+6\dfrac{3}{4}}{\left(5\dfrac{2}{7}-\dfrac{16}{3}\right):\left(6\dfrac{2}{3}-4\dfrac{1}{2}\right)}\)
\(A=\dfrac{\left(17+\dfrac{1}{4}-4-\dfrac{3}{16}-13-\dfrac{5}{6}\right)\cdot\left(-\dfrac{4}{7}\right)+\dfrac{27}{4}}{\left(5+\dfrac{2}{7}-5-\dfrac{1}{3}\right):\left(6+\dfrac{2}{3}-4-\dfrac{1}{2}\right)}\)
\(=\dfrac{\dfrac{37}{84}+\dfrac{27}{4}}{-\dfrac{1}{21}:\dfrac{13}{6}}=\dfrac{-1963}{6}\)
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dfrac{4}{9}.19dfrac{1}{3}+dfrac{-4}{9}.39dfrac{1}{3}+dfrac{-3^2}{5}:left(-0,2right)
dfrac{left(-5^3right)^2}{27}.dfrac{3}{23}.dfrac{6^2}{-5^6}
1dfrac{4}{23}+dfrac{5}{21}-dfrac{4}{23}+0,5+dfrac{16}{21}
dfrac{3}{7}.19dfrac{1}{3}-dfrac{3}{7}:33dfrac{1}{3}
dfrac{3}{4}-left(x+dfrac{1}{2}right)dfrac{4}{5}
x:(-2,14)(-3,12):1,2
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\(\dfrac{4}{9}.19\dfrac{1}{3}+\dfrac{-4}{9}.39\dfrac{1}{3}+\dfrac{-3^2}{5}:\left(-0,2\right)\)
\(\dfrac{\left(-5^3\right)^2}{27}.\dfrac{3}{23}.\dfrac{6^2}{-5^6}\)
\(1\dfrac{4}{23}+\dfrac{5}{21}-\dfrac{4}{23}+0,5+\dfrac{16}{21}\)
\(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}:33\dfrac{1}{3}\)
\(\dfrac{3}{4}-\left(x+\dfrac{1}{2}\right)=\dfrac{4}{5}\)
x:(-2,14)=(-3,12):1,2
Tính 1 câu thoy nhé !
\(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}.33\dfrac{1}{3}\)
= \(\dfrac{3}{7}.\left(19\dfrac{1}{3}-33\dfrac{1}{3}\right)\)
=\(\dfrac{3}{7}.-14=-6\)
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Tính :
a) -dfrac{3}{4}.31dfrac{11}{23}-0.75.8dfrac{12}{23}
b) left(2dfrac{1}{3}+3dfrac{1}{2}right):left(-4dfrac{1}{6}+3dfrac{1}{7}right)+7dfrac{1}{2}
c) 4dfrac{5}{9}:left(dfrac{-5}{7}right)+5dfrac{4}{9}:left(dfrac{-5}{7}right)
d) 4dfrac{25}{16}+25left(dfrac{9}{16}:dfrac{125}{64}:dfrac{-27}{8}right)
e) dfrac{2}{3}-4left(dfrac{1}{2}+dfrac{3}{4}right)
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Tính :
a) \(-\dfrac{3}{4}.31\dfrac{11}{23}-0.75.8\dfrac{12}{23}\)
b) \(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right):\left(-4\dfrac{1}{6}+3\dfrac{1}{7}\right)+7\dfrac{1}{2}\)
c) \(4\dfrac{5}{9}:\left(\dfrac{-5}{7}\right)+5\dfrac{4}{9}:\left(\dfrac{-5}{7}\right)\)
d) \(4\dfrac{25}{16}+25\left(\dfrac{9}{16}:\dfrac{125}{64}:\dfrac{-27}{8}\right)\)
e) \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)\)
a: \(=\dfrac{-3}{4}\left(31+\dfrac{11}{23}+8+\dfrac{12}{23}\right)=\dfrac{-3}{4}\cdot40=-30\)
b: \(=\left(\dfrac{7}{3}+\dfrac{7}{2}\right):\left(-\dfrac{25}{6}+\dfrac{22}{7}\right)+\dfrac{15}{2}\)
\(=\dfrac{35}{6}:\dfrac{-175+132}{42}+\dfrac{15}{2}\)
\(=\dfrac{35}{6}\cdot\dfrac{42}{-43}+\dfrac{15}{2}\)
\(=\dfrac{35\cdot7}{-43}+\dfrac{15}{2}\)
\(=\dfrac{-70\cdot7+15\cdot43}{86}=\dfrac{155}{86}\)
c: \(=\dfrac{-7}{5}\left(4+\dfrac{5}{9}+5+\dfrac{4}{9}\right)=\dfrac{-7}{5}\cdot10=-14\)
d: \(=4+\dfrac{25}{16}+25\cdot\left(\dfrac{9}{16}\cdot\dfrac{64}{125}\cdot\dfrac{-8}{27}\right)\)
\(=\dfrac{89}{16}+25\cdot\dfrac{-32}{375}\)
\(=\dfrac{89}{16}-\dfrac{32}{15}=\dfrac{823}{240}\)
e: \(=\dfrac{2}{3}-4\cdot\left(\dfrac{2}{4}+\dfrac{3}{4}\right)=\dfrac{2}{3}-5=-\dfrac{13}{3}\)
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Bài 1.( 2 điểm)Tính bằng cách hợp lí:a) dfrac{1}{2}+dfrac{9}{10}+dfrac{5}{6}-dfrac{11}{14}-dfrac{1}{3}+dfrac{-4}{35}b) left(dfrac{18}{23}+dfrac{7}{12}right)+left(dfrac{-13}{19}-dfrac{3}{4}right)+left(dfrac{-6}{19}+dfrac{5}{23}right)c) dfrac{4}{3}+dfrac{-5}{6}+dfrac{-1}{4}d) dfrac{5}{6}-dfrac{7}{5}+dfrac{17}{30}
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Bài 1.( 2 điểm)Tính bằng cách hợp lí:
a) \(\dfrac{1}{2}+\dfrac{9}{10}+\dfrac{5}{6}-\dfrac{11}{14}-\dfrac{1}{3}+\dfrac{-4}{35}\)
b) \(\left(\dfrac{18}{23}+\dfrac{7}{12}\right)+\left(\dfrac{-13}{19}-\dfrac{3}{4}\right)+\left(\dfrac{-6}{19}+\dfrac{5}{23}\right)\)
c) \(\dfrac{4}{3}+\dfrac{-5}{6}+\dfrac{-1}{4}\)
d) \(\dfrac{5}{6}-\dfrac{7}{5}+\dfrac{17}{30}\)
1: \(\dfrac{1}{2}+\dfrac{9}{10}+\dfrac{5}{6}-\dfrac{11}{14}-\dfrac{1}{3}+\dfrac{-4}{35}\)
\(=\left(\dfrac{1}{2}+\dfrac{5}{6}-\dfrac{1}{3}\right)+\dfrac{9}{10}-\left(\dfrac{11}{14}+\dfrac{4}{35}\right)\)
\(=\dfrac{3+5-2}{6}+\dfrac{9}{10}-\dfrac{55+8}{70}\)
\(=1+\dfrac{9}{10}-\dfrac{9}{10}\)
=1
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Tính:
a) A= \(\left(\dfrac{5}{6}-\dfrac{4}{5}\right).1\dfrac{1}{5}+\dfrac{3}{16}:\left(\dfrac{-1}{2}\right)^3\)
b) B= \(\dfrac{4}{17}.\left(7\dfrac{3}{4}-6\dfrac{1}{3}\right)+\left(5\dfrac{3}{4}-6.95\right):\left(-1\dfrac{3}{5}\right)\)
A = (\(\dfrac{5}{6}\) - \(\dfrac{4}{5}\)) . 1\(\dfrac{1}{5}\) + \(\dfrac{3}{16}\) : (\(\dfrac{-1}{2}\))3
A = \(\dfrac{1}{30}\) . \(\dfrac{6}{5}\) + \(\dfrac{3}{16}\) : \(\dfrac{-1}{8}\)
A = \(\dfrac{1}{25}\) + \(\dfrac{3}{16}\) . \(\dfrac{-8}{1}\)
A = \(\dfrac{1}{25}\) + \(\dfrac{-3}{2}\)
A = \(\dfrac{-73}{50}\)
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B = \(\dfrac{4}{17}\) . (7\(\dfrac{3}{4}\) - 6\(\dfrac{1}{3}\)) + (5\(\dfrac{3}{4}\) - 6.95) : (-1\(\dfrac{3}{5}\))
B = \(\dfrac{4}{17}\) . \(\dfrac{17}{12}\) + (\(\dfrac{23}{4}\) - \(\dfrac{139}{20}\)) : \(\dfrac{-8}{5}\)
B = \(\dfrac{1}{3}\) + \(\dfrac{-6}{5}\) . \(\dfrac{-5}{8}\)
B = \(\dfrac{13}{12}\)
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