- C4H8 + Br2 -> C4H8Br2

- CH2=CH-CH2-CH3 + Br-Br -> CH2Br-CH2Br-CH3

\(CH_2=CH-CH_2-CH_3+Br_2\rightarrow CH_2Br-CHBr-CH_2-CH_3\)

\(CH_2=CH-CH_2-CH_3+Br_2\rightarrow CH_2Br-CHBr-CH_2-CH_3\)

\(CH_2=CH-CH_2-CH_2+Br_2\rightarrow CH_2Br-CHBr-CH_2-CH_3\)

1. \(NaCl+H_2SO_4\rightarrow NaHSO_4+HCl\)

2. Khí HCl thu được trong quá trình điều chế axit HCl

3. \(2NaCl+2H_2O\rightarrow H_2O+2NaOH+Cl_2\)

\(2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O\)

4. \(Ca\left(OH\right)_2+Cl_2\rightarrow CaOCl_2+H_2O\)

5. \(6KOH+3Cl_2\rightarrow KClO_3+5KCl+3H_2O\)

6. \(MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O\)

7.\(2NaCl+2H_2O\rightarrow2NaOH+Cl_2+H_2O\)

8.\(H_2SO_4+CaF_2\rightarrow CaSO_4+HF\)

9. \(NaBr\rightarrow Na+\frac{1}{2}Br_2\)

10.\(NaI\underrightarrow{^{đpnc}}Na+\frac{1}{2}I_2\)

\(n_{Br_2}=0,5.2=1\left(mol\right)\\ C_2H_2+2AgNO_3+2NH_3\rightarrow Ag_2C_2+2NH_4NO_3\\ n_{Ag_2C_2}=\dfrac{96}{240}=0,4\left(mol\right)\\ n_{C_2H_2}=n_{Ag_2C_2}=0,4\left(mol\right)\Rightarrow m_{C_2H_2}=0,4.26=10,4\left(g\right)\\ \Rightarrow m_{hh\left(C_2H_4,C_2H_6\right)}=28-10,4=17,6\left(g\right)\\ C_2H_2+2Br_2\rightarrow C_2H_2Br_4\left(1\right)\\ C_2H_4+Br_2\rightarrow C_2H_4Br_2\left(2\right)\\ n_{Br_2\left(2\right)}=1-2.0,4=0,2\left(mol\right)\\ n_{C_2H_4}=n_{Br_2\left(2\right)}=0,2\left(mol\right)\\ m_{C_2H_4}=0,2.28=5,6\left(g\right)\\ m_{C_2H_6}=17,6-5,6=12\left(g\right)\\ hhA:\left\{{}\begin{matrix}C_2H_4:5,6\left(g\right)\\C_2H_6:12\left(g\right)\\C_2H_2:10,4\left(g\right)\end{matrix}\right.\)

Không biết đề có cho m_X không bạn nhỉ?

KBrO₃ +5KBr + 3H₂SO₄ → 3K₂SO₄ + 3Br₂ + 3H₂O

a, \(nC_6H_5CHCH_2\rightarrow\left(-CH\left(C_6H_5\right)-CH_2-\right)_n\)

b, Không hiểu đề

c,\(Br_2+C_6H_5CHCH_2\rightarrow C_6H_5-CH\left(Br\right)-CH_2Br\)

d,\(HCl+C_6H_5CHCH_2\rightarrow C_6H_5-CHCl-CH_3\)