13058

19+24+35+76557+27+27+82+72+78+27+2+7+2+72+7+2+782+7+78+652+78+27+2+78+52+3627+8+627=83058

Chúc học tốt!

10987622

a: Ta có: \(3^{2020}=3^{2018}\cdot3^2=3^{2018}\cdot9\)

mà 9<10

nên \(3^{2020}< 10\cdot3^{2018}\)

ket qua =1/2

a: =-3/4-1/4+2/7+5/7+2023/2024

=-1+1+2023/2024=2023/2024

b: 2/3x=2/7

=>x=2/7:2/3=3/7

c; =>2/3x=1/10+1/2=1/10+5/10=6/10=3/5

=>x=3/5:2/3=3/5*3/2=9/10

74/7

74/7

=504/7+2/7=506/7

2². 3. 5.7

Phân tích số 420 ra thừa số nguyên tố thì ta được kết quả là:

2². 7. 15

2². 5 . 7

2². 3 . 7

2². 3. 5.7

2² x 3 x 5 x 7

a) -72.17+72.31 - 36 . 228

 = -72.17 + 72. 31 - 36.2.114

 = -72 .17 + 72 . 31 -72 . 114

 = -72. ( 17-31+114)

 = -72 . 100

 = -7200

b) ..........

 = -7 . ( 16-36.9) -(-125) 

 = -7 . ( 16-324) +125

 =-7 . ( -308) +125

 = 2156+125

 = 2281

$a)$

$-72.17+72.31-36.228$

$=-72.17+72.31-36.2.114$

$=-72.17+72.31-72.114$

$=72(31-17-114)$

$=72.(-100)=-7200$

$b)$$-7.[{(-2)}^4+(-36):(-3^2)]-{(-5)}^3$

$=-7.[16-36:(-9)]+125$

$=-7.[16--4]+125$

$=-7.20+125$

$=-140+125$

$=-15$

$c)$$(57-725)-(605-53)$

$=57-725-605+53$

$=(57+53)-120$

$=110-120=-10$

$a)$

$-72.17+72.31-36.228$

$=-72.17+72.31-36.2.114$

$=-72.17+72.31-72.114$

$=72(31-17-114)$

$=72.(-100)=-7200$

\(1,\)

\(a,\sqrt{6-2\sqrt{5}}=\sqrt{\sqrt{5^2}-2.\sqrt{5}.1+1}=\sqrt{\left(\sqrt{5}-1\right)^2}=\left|\sqrt{5}-1\right|=\sqrt{5}-1\)

\(b,\sqrt{8+2\sqrt{7}}=\sqrt{\sqrt{7^2}+2.\sqrt{7}.1+1}=\sqrt{\left(\sqrt{7}+1\right)^2}=\left|\sqrt{7}+1\right|=\sqrt{7}+1\)

\(2,\)

\(a,\sqrt{\left(\sqrt{10}-3\right)^2}-\sqrt{10}\)

\(=\left|\sqrt{10}-3\right|-\sqrt{10}\)

\(=\sqrt{10}-\sqrt{10}-3\)

\(=-3\)

\(b,\sqrt{\left(5+\sqrt{7}\right)^2}-\sqrt{8-2\sqrt{7}}\)

\(=\left|5+\sqrt{7}\right|-\sqrt{\left(\sqrt{7}-1\right)^2}\)

\(=5+\sqrt{7}-\left|\sqrt{7}-1\right|\)

\(=5+\sqrt{7}-\sqrt{7}+1\)

\(=6\)