Tính :
\(P=\dfrac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
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P = \(\dfrac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
tính P = \(\dfrac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
\(P=\dfrac{\left(17.005-4.505\right)^2+93.75}{\left[\left(0.22+3.53\right)^2-\left(2.75\right)^2\right]:0,52}\)
\(=\dfrac{156.25+93.75}{6.5:0.52}=\dfrac{250}{12.5}=20\)
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tính :\(P=\frac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^{^2}-\left(2,75\right)^2\right\}:0,52}\)
Tính:
\(P=\dfrac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:052}\)
\(=\dfrac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{250}{\left(14,0625-75625\right):0,52}\)
\(=\dfrac{250}{6,5:0,52}\)
\(=\dfrac{250}{12,5}=20\)
Vây P = 20
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Tính :
\(P=\dfrac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left\{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]\right\}:0,52}\)
\(=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{156,25+93.75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{250}{\left(14,0625-7,5625\right):0,52}\)
\(=\dfrac{250}{6,5:0,52}=\dfrac{250}{12,5}=20\)
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Tính \(A=\frac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
Mấy anh chị giúp em với bài này em tính hoa mắt mà không ra 
\(A=\frac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
= \(\frac{\left(17,005-4,005\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
= \(\frac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
= \(\frac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
= \(\frac{250}{\left(14,0625-7,5625\right):0,52}\)
= \(\frac{250}{12,5}=20\)
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Tính:
\(P=\frac{\left(81,624:4,8-4,505\right)^2+125\cdot0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
Tính:
\(P=\frac{\left(81,624;4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
Giải:
\(P=\frac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(=\frac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(=\frac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\frac{250}{\left(14,0625-7,5625\right):0,52}\)
\(=\frac{250}{6,5:0,52}\)
\(=\frac{250}{12,5}\)
\(=20\)
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\(=\frac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(=\frac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\frac{250}{\left(14,0625-7,5625\right):0,52}\)
\(=\frac{250}{6,5:0,52}\)\(=\frac{250}{12,5}=20\)
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Tinh:
\(A=\dfrac{(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}).203\dfrac{1}{25}+46\dfrac{3}{4}}{(1\dfrac{3}{7}+\dfrac{10}{3}):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(B=\dfrac{\left(81,624:4,8-4.505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
hơi sai sai tki pGiang Thủy Tiên
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