(a x 27 + 116 x b): c

= (1368 x 27 + 116 x 54) : 108

= (36936 + 6264) : 108

= 43200 : 108

= 400

( a x 27 + 116 x b ) : c

= ( 1368 x 27 + 116 x 54 ) : 108

= ( 684 x 54 + 116 x 54 ) : 108

= [ ( 684 + 116 ) x 54 ] : 108

= ( 800 x 54 ) : 108

= 400 x 108 : 108

= 400

A = \(\dfrac{27}{512}\) \(\times\) \(\dfrac{327}{213}\) \(\times\) \(\dfrac{512}{57}\) \(\times\) \(\dfrac{213}{54}\) \(\times\) \(\dfrac{57}{327}\)

A = \(\dfrac{27\times327\times512\times213\times57}{54\times327\times512\times213\times57}\) 

A = \(\dfrac{27}{54}\)

A = \(\dfrac{1}{2}\)

\(a,123\times54+27\times123-12\times123+123\times31\)

\(=123\times\left(54+27-12+31\right)\)

\(=123\times100\)

\(=12300\)

\(b,\dfrac{121}{27}\times\dfrac{54}{11}< n< \dfrac{100}{21}:\dfrac{25}{126}\)

\(22< n< \dfrac{100}{21}\times\dfrac{126}{25}\)

\(22< n< 24\)

Vì \(23>22\) và \(23< 24\) nên \(n=23\)

a, 123x(54+27-12+31)

=123x100

=12300

a123x54+27x123-12x123+123x31

=123:54+27:123-12:123+123:31

=6642+27:123-12:123+123:31

=6642+3321-12:123+123:31

=6642+3321-1476+123:31

=6642+3321-1476+3813

=12300

b,121/27x54/11<n>100/21:25/126

=22<n>24

n=23

a) 20x4+20x3+20x3

= 20 x ( 4+3 + 3)

= 20 x10

= 200

 b) (6x9-54)x(25 +26+27+.........41+42)

= 0 x (25 +26+27+.........41+42)

= 0 

20x4+20x3+20x3

= 20 x ( 4+3 + 3)

= 20 x10

= 200

 b) (6x9-54)x(25 +26+27+.........41+42)

= 0 x (25 +26+27+.........41+42)

= 0 

a) = 20 x ( 4 + 3 + 3 )

   = 20 x 10

  = 200

b) = 0 x ( 25+26+27+....41+42)

= x

A, 27 X 45 + 45 X 74 - 45 =

     27 X 45 + 74 X 45 - 45 X 1=

     45X[ 27+74 - 1] = 

     45 X 100          = 

4500

B,[ 54 X 28+12 X 54 ] : 36 =

   [ 54 X 28 + 54 X 12] : 36=

   [ 54 X [ 28 + 12       ] :36=

  [54 X 40 ]     : 36=

2160   : 36=

60

MÌNH CÓ SAI CHỖ NÀO BẠN CỐ GẮNG TÌM CÁCH KHÁC NHÉ !

= 45x (27+74-45)

= 45x        56

=        2520

HT

Ta có: \(A=\frac{108}{27}\cdot\frac{146}{29}-\frac{54}{27}\cdot\frac{202}{29}-\frac{16}{29}\)

\(=4\cdot\frac{146}{29}-2\cdot\frac{202}{29}-\frac{16}{29}\)

\(=\frac{584}{29}-\frac{404}{29}-\frac{16}{29}\)

\(=\frac{164}{29}\)

a. 54 x 113 + 45 x 113 + 113

= 113 x (54 + 45 + 1)

= 113 x 100 = 11300

Vậy giá trị cần tìmlaf: 11300

b. 54 x 47 - 47 x 53 - 20 - 27

= 54 x 47 - 47 x 53 - (20 + 27)

= 54 x 47 - 47 x 53 - 47

= 47 x (54 - 53 - 1)

= 47 x 0 = 0

Vậy giá trị cần tìm là: 0

\(a,54\times113+45\times113+113\\ =113\times\left(54+45+1\right)\\ =113\times100=11300\)

\(b,54\times47-47\times53-20-27\\ =54\times47-47\times53-47\\ =47\times\left(54-53-1\right)\\ =47\times0=0\)

a 11300

 b  0