Tìm x, biết: |x+8| = 10
\(a,\left(x+2\right)^{10}+\left(x+2\right)^8=0\\ \Leftrightarrow\left(x+2\right)^8\left[\left(x+2\right)^2+1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+2\right)^8=0\\\left(x+2\right)^2+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+2=0\\\left(x+2\right)^2=-1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-2\\x\in\varnothing\end{matrix}\right.\\ b,\left(x+3\right)^{10}-\left(x+3\right)^8=0\\ \Leftrightarrow\left(x+3\right)^8\left[\left(x+3\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x+3\right)^8=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x+3=0\\\left(x+3\right)^2=1\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-3\\x+3=1\\x+3=-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\\x=-4\end{matrix}\right.\)
Tìm x biết: (x - 8)÷3 = 10 x = ?
A. x = 32
B. x = 18
C. x = 24
D. x = 38
Tìm x biết: \(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\)
\(\dfrac{x+8}{12}+\dfrac{x+9}{11}+\dfrac{x+10}{10}+3=0\\ \Leftrightarrow\dfrac{x+8}{12}+1+\dfrac{x+9}{11}+1+\dfrac{x+10}{10}+1=0\\ \Leftrightarrow\dfrac{x+20}{12}+\dfrac{x+20}{11}+\dfrac{x+20}{10}=0\\ \Leftrightarrow\left(x+20\right)\left(\dfrac{1}{12}+\dfrac{1}{11}+\dfrac{1}{10}\right)=0\\ \Leftrightarrow x+20=0\Leftrightarrow x=-20\\ KL:...\)
`<=>((x+8)/12+1)+((x+9)/11+1)+((x+10)/10+1)=0`
`<=>(x+20)/12+(x+20)/11+(x+20)/10=0`
`<=>(x+20)(1/12+1/11+1/10)=0`
Vì `1/12+1/11+1/10 ≠ 0`
`=>x+20=0`
`=>x=0-20`
`=>x=-20`
Tìm x biết : | x+6 | + | x+8 | = 10
Tìm x, biết: | x+8 | = 10
|x+8|=10
Vì đây là giá trị tuyệt đối suy ra:
x+8=10;x=10-8=2
x+8=-10;x=-10-8=-18
Vậy x=2;-18
| x + 8 | = 10
\(\Rightarrow\)x+8=10
x =10-8
x = 2
hoặc x+8=10
x = - 10 - 8
x = - (10+8)
x = -18
Vậy x \(\in\) { 2; -18 }
Tìm x biết | 10-x| + | 8-x | =0
Tìm x biết:
\(\dfrac{x}{-8}\)\(=\dfrac{-15}{10}\)
Vậy x =???
\(\dfrac{x}{-8}=\dfrac{-15}{10}\\ \Rightarrow10x=\left(-8\right)\left(-15\right)=120\\ \Rightarrow x=12\)
Vậy x = 12
x=\(\dfrac{-15}{10}.\left(-8\right)\)=12
\(\dfrac{x}{-8}=-\dfrac{15}{10}\)
\(=>x=\dfrac{-8\cdot-15}{10}\)
\(x=12\)
Vậy x =12
Tìm x, biết:
( 3/4 + x ) x 50/100 = 8/10
` (3/4 +x) xx 50/100 = 8/10`
`( 3/4 + x) xx 1/2 = 4/5`
` 3/4 + x = 4/5 : 1/2`
` 3/4 + x = 4/5 xx2`
` 3/4 + x = 8/5`
` x = 8/5 - 3/4`
` x = 17/20`
Tìm x, biết:
( 3/4 + x ) x 50/100 = 8/10
( 3/4 + x ) = 8/10 : 50/100
( 3/4 + x ) = 8/5
x = 8/5 - 3/4
x = 17/20.
=>x+3/4=4/5:1/2=4/5x2=8/5
=>x=8/5-3/4=32/20-15/20=17/20
Bài 3 :
a) Tìm x biết: (x+2)2 +(x+8)(x+2)
b) Tính giá trị biểu thức : B= (x+y)(x2 – xy + y2) –y3, tại x =10, y = 2021
Bài 3 :
a) Tìm x biết: (x+2)2 +(x+8)(x+2)
b) Tính giá trị biểu thức : B= (x+y)(x2 – xy + y2) –y3, tại x =10, y = 2021