a x 3,5 + a x 6,9 + a x 8,6 = 66,5

a x ( 3,5 + 6,9 + 8,6 ) = 66,5

a x 19 = 66,5

==> a = 3,5          Tk mk,mk k lại !!!!!!!!!!!!!!!

a x 3,5 + a x 6,9 + a x 8,6 = 66,5

a x ( 3,5 + 6,9 + 8,6 ) = 66,5

a x 19 = 66,5

        a = 66,5 : 19

        a = 3,5 .

a x 3,5 + a x 6,9 + a x 8,6 = 66,5

a x (3,5 + 6,9 + 8,6 ) = 66,5

a x 19 = 66,5

a = 66,5 : 19

a =3,5

Kick mình nha              Cảm ơn bạn trước

\(a,\left(x-1\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)

\(b,\left(x-2\right)\left(x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

\(c,\left(x+3\right)\left(x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=5\end{matrix}\right.\)

\(d,\left(x+\dfrac{1}{2}\right)\left(4x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\4x+4=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\4\left(x+1\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=-1\end{matrix}\right.\)

\(e,\left(x-4\right)\left(5x-10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\5x-10=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)

\(f,\left(2x-1\right)\left(3x+6\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=0\\3x+6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-2\end{matrix}\right.\)

`a,(x-1)(x+2)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-2\end{matrix}\right.\)

`b,(x -2)(x -5)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

`c,(x +3)(x -5)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x-5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=5\end{matrix}\right.\)

`d,(x + 1/2)(4x + 4)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\4x+4=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\4x=-4\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=-1\end{matrix}\right.\)

`e,(x -4)(5x -10)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-4=0\\5x-10=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\5x=10\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)

`f,(2x -1)(3x +6)=0`

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=0\\3x+6=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=1\\3x=-6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-2\end{matrix}\right.\)

`g,(2,3x -6,9)(0,1x -2)=0`

\(\Leftrightarrow\left[{}\begin{matrix}2,3x-6,9=0\\0,1x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2,3x=6,9\\0,1x=2\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=20\end{matrix}\right.\)

a.(x - 1)(x + 2)= 0

<=> x-1=0 hoặc x+2=0

<=> x=1 hoặc x=-2

b.(x -2)(x -5)=0

<=> x-2=0 hoặc x-5=0

<=> x=2 hoặc x=5

c.(x +3)(x -5)=0

<=> x+3=0 hoặc x-5=0

<=> x=-3 hoặc x=5

d.(x + 1/2)(4x + 4)=0

<=> x+1/2=0 hoặc 4x+4=0

<=> x=-1/2 hoặc x=-1

e.(x -4)(5x -10)=0

<=> x-4=0 hoặc 5x-10=0

<=> x=4 hoặc x=2

f.(2x -1)(3x +6)=0

<=> 2x-1=0 hoặc 3x+6=0

<=> x=1/2 hoặc x=-2

g.(2,3x -6,9)(0,1x -2)=0

<=> 2,3x-6,9=0 hoặc 0,1x-2=0

<=> x=3 hoặc x=20

\(a.1,25\times5\times6,3\div0,125\times2\\ =\left(5\times2\right)\times\left(1,25\div0,125\right)\times6,3\\ =10\times10\times6,3=630\)

\(b.12,5\times6,9+0,1\times6,9\times865\times6,9\\ =6,9\times\left(12,5+86,5+1\right)\\ =6,9\times100=690\)

6,9 x 135 - 6,9 x 65 + 6,9 x 30

= 6,9 x ( 135 - 65 + 30 )

= 6,9 x 100

= 690

/HT\

\(x:\frac{13}{10}+\frac{42}{5}.\frac{6}{7}.\left(6-\frac{\left(2,3+0,8\right).7}{0,1+6,9}\right)=\frac{39}{7}:\frac{15}{14}=\frac{37}{7}.\frac{14}{15}=\frac{74}{15}\)

\(x.\frac{10}{13}+\frac{36}{7}\left(6-\frac{3,1.7}{7}\right)=\frac{74}{15}\)

\(x.\frac{10}{13}+\frac{36}{7}\left(6-3,1\right)=\frac{74}{15}\)

\(x.\frac{10}{13}+\frac{36}{7}.\frac{29}{10}=\frac{74}{15}\)

\(x.\frac{10}{13}+\frac{522}{35}=\frac{74}{15}\)

\(x.\frac{10}{13}=\frac{74}{15}-\frac{522}{35}=-9\frac{103}{105}\)

\(x=-9\frac{103}{105}:\frac{10}{13}=-12\frac{512}{525}\)

Ngan Nguyen

nhấn "Shift" rồi "\"

x=-12\(\frac{512}{525}\)

X x (9,9 + 0,1) = 6,9
X x       10        = 6,9
X                       = 6,9 : 10
X                       = 69

\(=>x=30,4:\left(3,1+6,9\right)=30,4:10=3,04\)

X x 3,1 + X x 6,9 = 30,4

X x ( 3,1 + 6,9 ) = 30,4

X x 10 = 30,4

X = 30,4 : 10

X = 3,04

X x 3,1 + X x 6,9 = 30,4

X x ( 3,1 + 6,9 ) = 30,4

Xx 10 = 30,4 

X       = 30,4 : 10 

X        = 3,04