Tính:
1.99+2.98+3.97+...+97.3+98.2+99.1
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Tính: 1.99+2.98+3.97+...+97.3+98.2+99.1
hic hic mai phải nộp rồi mọi người giúp kim oanh nha oaoa
=1.99+2.(99-1)+3.(99-2)+...+98.(99-97)+99(99-98)
=99.(1+2+3+4+...+98+99)-(2+2.3+3.4+...+97.98+98.99)
=99.(1+99).99/2-98.99.100/3
=99.50.99-98.33.100
=490050-323400
=166650
=1.99+2.(99-1)+3.(99-2)+...+98.(99-97)+99(99-98)
=99.(1+2+3+4+...+98+99)-(2+2.3+3.4+...+97.98+98.99)
=99.(1+99).99/2-98.99.100/3
=99.50.99-98.33.100
=490050-323400
=166650
C = 1.99 + 2.98 + 3.97 +...+ 97.3 + 98.2 + 99.1
\(C=1.99+2.98+3.97+........+97.3+98.2+99.1\)
\(\Rightarrow C=1.99+2.\left(99-1\right)+3\left(99-2\right)+..........+98.\left(99-97\right)+99.\left(99-98\right)\)
\(\Rightarrow C=1.99+2.99-1.2+3.99-2.3+........+98.99-97.98+99.99-98.99\)
\(\Rightarrow C=\left(1.99+2.99+.......+99.99\right)-\left(1.2+2.3+.........+98.99\right)\)
\(\Rightarrow C=490050-\left(1.2+2.3+....+98.99\right)\)
Đặt \(A=1.2+2.3+3.4+........+98.99\)
\(\Rightarrow3A=1.2.3+2.3.3+..........+98.99.3\)
\(\Rightarrow3A=1.2.3+2.3.\left(4-1\right)+.....+98.99\left(100-97\right)\)
\(\Rightarrow3A=1.2.3-1.2.3+2.3.4-2.3.4+......+97.97.99-97.98.99+98.99.100\)
\(\Rightarrow3A=98.99.100\)
\(\Rightarrow A=\dfrac{98.99.100}{3}=323400\)
\(\Rightarrow C=490050-323400=166650\)
Vậy \(C=166650\)
\(C=1.99+2.98+3.97+...+97.3+98.2+99.1\)
\(=1.99+2(99-1)+3(99-2)+...+97.(99-96)+98(99-97)+99(99-98)\)
\(=(1.99+2.99+3.99+...+97.99+98.99+99.99)-(1.2+2.3+...+96.97+97.98+98.99)\)
\(=99.(1+2+3+...+99)- (1.2+2.3+...+96.97+97.98+98.99)\)
\(=99.\frac{99.(99+1)}{2} - (1.2+2.3+...+96.97+97.98+98.99)\)
\(=490050 - (1.2+2.3+...+96.97+97.98+98.99)\)
Từ đây tính vế trong ngoặc ra rồi thực hiện trừ là oke
Tính : A = 1.99 + 2.98 + 3.97 + ........+ 97.3 + 98.2 + 99.1
\(A = 1.99 + 2.98 + 3.97 + ...+ 97.3 + 98.2 + 99.1\)
\(A=1.99+2.\left(99-1\right)+3.\left(99-2\right)+...+98.\left(99-97\right)+99.\left(99-98\right)\)
\(A=1.99+2.99-1.2+3.99-2.3+98.99-97.98+99.99-98.99\)
\(=\left(1.99+2.99+3.99+...+98.99+99.99\right)-\left(1.2+2.3+3.4+...+97.98+98.99\right)\)
\(=99.\left(1+2+3+...+98+99\right)-\left(1.2+2.3+3.4+...+97.98+98.99\right)\)
\(=99.4950-\left(1.2+2.3+3.4+97.98+98.99\right)\)
Mà \(1.2+2.3+3.4+...97.98+98.99\)
\(=\frac{1}{3}.\left[1.2+2.3.\left(4-1\right)+3.4.\left(5-2\right)+98.99.\left(100-97\right)\right]\)
\(=\frac{1}{3}.98.99.100=323400\)
\(\Rightarrow A=99.4950-323400=166650\)
\(B=1.99+2.98+3.97+...+97.3+98.2+99.1\)
tính tổng C=1.2+2.3+3.4+...+98.99 rồi sử dụng kết quả tính tổng:
S=1.99+2.98+3.97+...+97.3+98.2+99.1
H=1.1+2.2+3.3+...+97.97+98.98
Ô tô đi với vận tốc 50km/giờ vì :
100 : 2 = 50
đs : 50
Ta có: C = 1.2 + 2.3 + 3.4 + ..... + 98.99
=> 3C = 3.(1.2 + 2.3 + 3.4 + ..... + 98.99)
=> 3C = 1.2.(3 - 0) + 2.3.(4 - 1) + .... + 98.99.(100 - 97)
=> 3C = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 98.99.100
=> 3C = 98.99.100
=> C = \(C=\frac{98.99.100}{3}=485100\)
1.99^2+2.98^2+3.97^2+....+98.2^2+99.1^2 Giúp mình vớiiiii
tính tổng C=1.2+2.3+3.4+...+98.99
rồi sử dụng kết quả tính tổng
a, S=1.99+2.98+3.97+4.96+...97.3+98.2+99.1
b, H=1.1+2.2+3.3+4.4+...+97.97+98.98
Ô tô đi với vận tốc 50km/giờ vì :
100 : 2 = 50
đs : 50
Ta có: C = 1.2 + 2.3 + 3.4 + ..... + 98.99
=> 3C = 3.(1.2 + 2.3 + 3.4 + ..... + 98.99)
=> 3C = 1.2.(3 - 0) + 2.3.(4 - 1) + .... + 98.99.(100 - 97)
=> 3C = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 98.99.100
=> 3C = 98.99.100
=> C = $C=\frac{98.99.100}{3}=485100$
Trả lời hộ mình câu h= 1.1+2.2+ 3.3+4.4+...+98.98
Cho \(B=\frac{2.\left(1.99+2.98+3.97+...+97.3+98.2+99.1\right)}{1^2+2^2+3^2+...+97^2+98^2+99^2}\)
So sánh B với 1
Cho \(B=\frac{2.\left(1.99+2.98.+3.97+.....+97.3+98.2+99.1\right)}{\left(1^2+2^2+3^2+.....+97^2+98^2+99^2\right)}\)
So sánh B với 1.