Tính A
\(A=2\frac{2}{35}^3-\frac{2^3}{63}-\frac{2}{99}^3-\frac{2}{143}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
giải cả bài nha
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Tính A
\(A=2\frac{2}{35}^3-\frac{2^3}{63}-\frac{2}{99}^3-\frac{2}{143}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
giải cả bài nha
tính A
\(A=2\frac{2}{35}^3-\frac{2}{63}^3-\frac{2}{99}^3-\frac{2}{143}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
giải cả bài nha
Tính A
\(A=2\frac{2}{35}^3-\frac{2^3}{63}-\frac{2}{99}^3-\frac{2}{143}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
giải cả bài nha
Tính A
\(A=2\frac{2}{35}^3-\frac{2^3}{63}-\frac{2}{99}^3-\frac{2}{143}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
giải cả bài nha
Tính A
\(A=2\frac{2^3}{35}-\frac{2}{63}^3-\frac{2}{99}^3-\frac{2}{143}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
giải cả bài nha
\(A=2-\frac{2^3}{35}-\frac{2}{63}^3-\frac{2}{99}^3-\frac{2}{142}^3-\frac{2}{195}^3-\frac{2}{255}^3-\frac{2}{323}^3\)
Tìm A
giải cả bài nha
\(A=2-\left(\frac{2^3}{25}+\frac{2^3}{63}+...+\frac{2^3}{255}+\frac{2^3}{323}\right)\)
\(=2-4.\left(\frac{2}{35}+\frac{2}{63}+...+\frac{2}{255}+\frac{2}{323}\right)\)
\(=2-4.\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{15.17}+\frac{2}{17.19}\right)\)
\(=2-4.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}\right)\)
\(=2-4.\left(\frac{1}{5}-\frac{1}{19}\right)\)
\(=2-4.\frac{14}{95}=2-\frac{56}{95}=\frac{134}{95}\)
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Tính:
A = 2 - \(\frac{2^3}{35}-\frac{2^3}{63}-\frac{2^3}{99}-\frac{2^3}{143}-\frac{2^3}{195}\)
\(C=\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\) Ai nhanh mk tik nha!!!!💎💎
\(C=\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\)
\(C=\frac{2}{3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\)
\(C=\frac{2}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\)
\(C=\frac{2}{3}+\frac{1}{3}-\frac{1}{13}\)
\(C=1-\frac{1}{13}\)
\(C=\frac{12}{13}\)
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\(C=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\)
\(C=\frac{1}{1}-\frac{1}{3}=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\)
\(C=\frac{1}{1}-\frac{1}{13}\)
\(C=\frac{12}{13}\)
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\(C=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\)
\(C=\left(1-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{7}\right)+...+\left(\frac{1}{11}-\frac{1}{13}\right)\)
\(C=1-\frac{1}{13}\)
\(C=\frac{12}{13}\)
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\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\)
\(A=\frac{2}{3}+\frac{2}{15}+...+\frac{2}{143}\)
\(A=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{11\cdot13}\)
\(A=\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{11}-\frac{1}{13}\)
\(A=1-\frac{1}{13}=\frac{12}{13}\)
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\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\)
\(=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\)
\(=1-\frac{1}{13}\)
\(=\frac{12}{13}\)
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\(\frac{2}{6}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\)
\(=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\)
\(=1-\frac{1}{13}\)
\(=\frac{12}{13}\)
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