\(2^3.17-2^3.14=2^3.\left(17-14\right)=2^3.3=8.3=24\)

làm r mà :V 

nè 

23.17−23.14=23.(17−14)=23.3=8.3=24

\(=2^3\cdot3+3\cdot5^2-8=24-8+75=91\)

=8(17-14)+3.25-16:2

=24+75-8

=91

23.17 - 23.14 = 8.17 – 8.14 = 8.(17 – 14) =8.3 = 24

`a, 3.5^2 -16:2^2`

`= 3. 25 - 16:4`

`= 75 - 4`

`=71`

_____

`b, 15.141 +59 . 15`

`= 15. (141+59)`

`=15. 200`

`=3000`

______

`c, 2^3 . 17 - 2^3 .14`

`= 2^3 . (17-14)`

`= 8 . 3`

`=24`

a: =3^7*3^15*3^12=3^34

b: =(36:18)^5=2^5=32

c: =5^7-5^5=5^5(5^2-1)=5^5*24=75000

d: =5^12:5^8=5^4=625

a: =3*25-16:4

=75-4=71

b: =15(141+59)

=15*200=3000

c: =2^3(17-14)=2^3*3=24

Bài 3:

a)3.5²-16:2²=71

b)15.141+59.15=15(141+59)=3000

c)2³.17-2³.14=2³(17-14)=8.3=24

(câu b hình như thiếu dấu "+"?)

a) 71

b) 24

c) 3000

Tick cho mình.

a)3.5²-16:2²

= 3. 25 - 16 :4

= 75 - 4

= 71

b)15.141+59.15

= 15.(141+59)

= 15. 200

= 3000

c)2³.17-2³.14

= 2³ .(17-14)

= 8 . 3

= 24

7. A = (x + y)^2 - 4y^2

= (x + y - 2y)(x + y + 2y)

= (x - y)(x + 3y)

2. x^4 + 4

= x^4 + 4x^2 + 4 - 4x^2

= (x^2 + 2)^2 - (2x)^2

= (x^2 + 2x + 2)(x^2 - 2x + 2)

3. 4x^4 + 16

= 4(x^4 + 4)

= 4(x^2 + 2x + 2)(x^2 - 2x + 2)

40: Ta có: \(A=27x^3+8y^3-3x-2y\)

\(=\left(3x+2y\right)\left(9x^2-6xy+4y^2\right)-\left(3x+2y\right)\)

\(=\left(3x+2y\right)\left(9x^2-6xy+4y^2-1\right)\)

b: \(=15\left(141+19\right)=15\cdot160=24000\)

c: \(=2^3\cdot\left(17-14\right)=8\cdot3=24\)

D(Vì 2 góc đối đỉnh mà 2 góc đối đỉnh thì = nhau)