( 2,4x - 36 ) : $\frac{15}{7}$157 = -1,4
( 2,4x - 36 ) : \(\frac{15}{7}\) = -1,4
\(\left(2,4x-36\right)=-1.\frac{12}{7}\)
\(\left(2,4x-36\right)=\frac{-12}{7}\)
\(2,4x=\frac{-12}{7}+36\)
\(2,4x=\frac{240}{7}\)
\(x=\frac{240}{7}:2,4\)
\(x=\frac{100}{7}\)
\(\left(2,4x-36\right):1\frac{5}{7}=-1\)
2,4x - 36 = -1 . \(\frac{12}{7}=\) -12/7
2,4x = -12/7 + 36 = 240/7
x = 240/7 : 2,4 = 100/7
\(\left(2,4x-36\right):1\frac{5}{7}=-1\)
\(\left(\frac{12}{5}x-36\right):\frac{12}{7}=-1\)
\(\left(\frac{12}{5}x-36\right)=-1.\frac{12}{7}\)
\(\left(\frac{12}{5}x-36\right)=-\frac{12}{7}\)
(2,4x-36):1 5/7=-1
=>2,4x-36=-12/7
=>2,4x=240/7
hay x=100/7
A) \(\frac{3}{x-5}=\frac{-4}{x+2}\)
B) \(\left(2,4x-36\right):1\frac{5}{7}=-1\)
C) \(\left(3\frac{4}{5}-2x\right).1\frac{1}{3}=5\frac{5}{7}\)
Cần gấp ạ!!!Mong moi người giúp ạ !!
a) \(\frac{3}{x-5}=\frac{-4}{x+2}\)(ĐKXĐ: \(x\ne5;x\ne-2\))
\(\Rightarrow3\left(x+2\right)=-4\left(x-5\right)\)
\(\Leftrightarrow3x+6=-4x+20\)
\(\Leftrightarrow7x=14\)
\(\Leftrightarrow x=2\)(thỏa mãn ĐKXĐ)
b) \(2,4x-36=-\frac{7}{12}\)
\(\Leftrightarrow2,4x=\frac{425}{12}\)
\(\Leftrightarrow x=\frac{2125}{144}\)
c) \(\left(\frac{19}{5}-2x\right).\frac{4}{3}=\frac{40}{7}\)
\(\Leftrightarrow\frac{19}{5}-2x=\frac{30}{7}\)
\(\Leftrightarrow2x=-\frac{17}{35}\)
\(\Leftrightarrow x=-\frac{17}{70}\)
A) \(\frac{3}{x-5}=\frac{-4}{x+2}\)
B) \(\left(2,4x-36\right):1\frac{5}{7}=-1\)
C) \(\left(3\frac{4}{5}-2x\right).1\frac{1}{3}=5\frac{5}{7}\)
Cần gấp ạ !! Mong mọi người giúp đỡ !!
b) \(\left(2,4.x-36\right)\div1\frac{5}{7}=-1\)
\(\left(2,4.x-36\right)=-1.\frac{12}{7}\)
\(2,4.x-36=-\frac{12}{7}\)
\(2,4.x=-\frac{12}{7}+36\)
\(2,4.x=\frac{240}{7}\)
\(x=\frac{240}{7}\div2,4\)
\(x=\frac{100}{7}\)
a) \(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Rightarrow3.\left(x+2\right)=-4.\left(x-5\right)\)
\(\Rightarrow3x+6=-4x+20\)
\(\Rightarrow7x=14\)
\(\Rightarrow x=2\)
a) \(\frac{7}{15}+\frac{9}{10}+\frac{8}{15}-\frac{-1}{10}-\frac{20}{10}+\frac{1}{157}\)
b) \(\frac{1}{13}+\frac{16}{7}+\frac{3}{105}-\frac{9}{7}-\frac{-12}{13}\)
a) \(\frac{7}{15}+\frac{9}{10}+\frac{8}{15}-\frac{-1}{10}-\frac{20}{10}+\frac{1}{157}\)
\(=\frac{7}{15}+\frac{9}{10}+\frac{8}{15}+\frac{1}{10}-\frac{20}{10}+\frac{1}{157}\)
\(=\left(\frac{7}{15}+\frac{8}{15}\right)+\left(\frac{9}{10}+\frac{1}{10}\right)-2+\frac{1}{157}\)
\(=1+1-2+\frac{1}{157}\)
\(=2-2+\frac{1}{157}\)
\(=0+\frac{1}{157}=\frac{1}{157}\)
b) \(\frac{1}{13}+\frac{16}{7}+\frac{3}{105}-\frac{9}{7}-\frac{-12}{13}\)
\(=\frac{1}{13}+\frac{16}{7}+\frac{1}{35}-\frac{9}{7}+\frac{12}{13}\)
\(=\left(\frac{1}{13}+\frac{12}{13}\right)+\left(\frac{16}{7}-\frac{9}{7}\right)+\frac{1}{35}\)
\(=1+1+\frac{1}{35}\)
\(=2+\frac{1}{35}\)
\(=\frac{70}{35}+\frac{1}{35}=\frac{71}{35}\)
Câu 1: Thực hiện phép tính
a, \(\dfrac{7}{9}-\dfrac{16}{9}\)
b, \(\dfrac{2}{-15}+\dfrac{7}{10}\)
c, \(\left(4\dfrac{2}{3}-4\dfrac{3}{4}\right):\dfrac{-5}{12}-\dfrac{4}{5}\)
d, \(\dfrac{-141}{157}.\dfrac{23}{59}-\dfrac{141}{157}.\dfrac{36}{59}+\dfrac{16}{-157}\)
a. 7/9 - 16/9 = -9/9 = -1
b. 2/-15 + 7/10 = 17/30
c. (4 2/3 - 4 3/4) : -5/12 - 4/5
= (14/3 - 19/4) : (-5/12) - 4/5
= -1/12 : (-5/12) - 4/5
= 1/5 - 4/5
= -3/5
\(B=\left|157\frac{13}{27}-273\frac{7}{19}\right|-96\frac{14}{27}+15\frac{12}{19}\)
Đúng / Sai
59+64=36+64+59 ..............
129+157-29=129-29+157 ............
129+157-29 = 157+ 129-29 ...........
4+16 x 25 = 16 + 4 x 25 .............
21 + 49 : 7 = 49 + 21 : .................
(36 + 45 ) : 9 = (45+36 ) :9 .............
59 + 64 = 36 + 63 + 59 _Sai_
129 + 157 - 29 =129 - 29 + 157 _Đúng_
129 + 157 - 29 = 157 + 129 - 29 _Đúng_
4 +16 x 25 = 16 + 4 x 25 _Sai_
21 + 49 : 7 = 49 + 21 : 7 _Sai_
(36 + 45 ) : 9 = (45+36 ) : 9 _Đúng_
(Cái này tính nhẩm là ra thôi bạn ạ! Đúng cho mình 1 tick nhé bạn!)