So sánh:
A = \(\frac{10^{2005}+1}{10^{2006}+1}\) và B = \(\frac{10^{2006+1}}{10^{2007}+1}\)
So sánh A và B. Cho A = \(\frac{10^{2004}+1}{10^{2005}+1}\)và B = \(\frac{10^{2005}+1}{10^{2006}+1}\)
10A=\(\frac{10x\left(10^{2004}+1\right)}{10^{2005}+1}\)=
15793486/64325+548662%546317787=
Cho
\(A=\frac{10^{2004}+1}{10^{2005}+1}\)
\(B=\frac{10^{2005}+1}{10^{2006}+1}\)
So sánh A và B
Ta có:10A=\(\frac{10^{2005}+10}{10^{2005}+1}\)=1+\(\frac{9}{10^{2005}+1}\)
10B=\(\frac{10^{2006}+10}{10^{2006}+1}\) =1+\(\frac{9}{10^{2006}+1}\)
Mà:\(\frac{9}{10^{2005}+1}\) >\(\frac{9}{10^{2006}+1}\)
Vậy:1+\(\frac{9}{10^{2005}+1}\) >1+\(\frac{9}{10^{2006}+1}\)
Vậy:A>B
cho
GIAI GIUP MINH DI
A=\(\frac{37^{2018}+5}{37^{2019}+5}\)
B=\(\frac{37^{2018}+1}{37^{2019}+1}\)
so sánh
A=\(\frac{10^{2006}+1}{10^{2007}+1}\)và B=\(\frac{10^{2007}+1}{10^{2008}+1}\)
HEPL ME TO
Áp dụng \(\frac{a}{b}< 1\Leftrightarrow\frac{a}{b}< \frac{a+m}{b+m}\)(\(a;b;m\in\)N*)
Ta có:
\(B=\frac{10^{2007}+1}{10^{2008}+1}< \frac{10^{2007}+1+9}{10^{2008}+1+9}\)
\(B< \frac{10^{2007}+10}{10^{2008}+10}\)
\(B< \frac{10.\left(10^{2006}+1\right)}{10.\left(10^{2007}+1\right)}\)
\(B< \frac{10^{2006}+1}{10^{2007}+1}=A\)
=> \(B< A\)
a)Tính tổng: \(B=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{2009.2012}\)
b)So sánh M và N biết: \(M=\frac{-7}{10^{2005}}+\frac{-15}{10^{2006}};N=\frac{-15}{10^{2005}}+\frac{-7}{10^{2006}}\)
so sánh A và B
\(A=\frac{10^{2006}+1}{10^{2007}+1}\) \(B=\frac{10^{2007}+1}{10^{2008}+1}\)
So sánh A và B biết
A=\(\frac{10^{2006}+1}{10^{2007}+1}\);B=\(\frac{10^{2007}+1}{10^{2008}+1}\)
Cho \(A=\frac{10^{2004}+1}{10^{2005}+1}\)và \(B=\frac{10^{2005}+1}{10^{2006}+1}\)
Hãy so sánh A và B
giúp mik giải toán ik
Ta có: \(A=\frac{10^{2004}+1}{10^{2005}+1}\)
So sánh:
A= \(\frac{10^{2004}+1}{10^{2005}+1}\)và B=\(\frac{10^{2005}+1}{10^{2006}+1}\)
\(B=\frac{10^{2005}+1}{10^{2006}+1}<\frac{10^{2005}+1+9}{10^{2006}+1+9}=\frac{10^{2005}+10}{10^{2006}+10}=\frac{10\left(10^{2004}+1\right)}{10\left(10^{2005}+1\right)}=\frac{10^{2004}+1}{10^{2005}+1}=A\)
\(\Rightarrow\)B < A
\(A=\frac{-7}{10^{2005}}+\frac{-15}{10^{2006}}B=\frac{-15}{10^{2005}}+\frac{-7}{10^{2006}}\)So sánh không quy đồng A và B
Ta có
\(A=\frac{-7}{10^{2005}}+\frac{-15}{10^{2006}}=\frac{-7}{10^{2005}}+\frac{-7}{10^{2006}}+\frac{-8}{10^{2006}}\)
\(B=\frac{-7}{10^{2005}}+\frac{-8}{10^{2005}}+\frac{-7}{10^{2006}}\)
Vì \(\frac{-8}{10^{2006}}>\frac{-8}{10^{2005}}\)
=>A>B