vì \(\frac{10^{2006}+1}{10^{2007}+1}\)<1
tc:B=\(\frac{10^{2006}+1}{10^{2007}+1}\)<\(\frac{10^{2006}+1+9}{10^{2007}+1+9}\)=\(\frac{10^{2006}+10}{10^{2007}+10}\)=\(\frac{10\left(10^{2005}+1\right)}{10\left(10^{2006}+1\right)}\)=\(\frac{10^{2005}+1}{10^{2006}+1}\)=A
=>B<A
A<B
quy tắc: a/b <1 thì a/b<a+m/b+m
a/b>1 thì a/b> a+m/b+m