=-15+27-27+15-31=-31

Đây là bài lớp 6?

`15.x + 27 - 15.x + 27 = 45`

`x*(15-15)+(27+27)=45`

`x*0+54=45`

`0+54=45`

`54=45`

Bạn xem lại đề! 

vô lý

vì bn kia là 54=45

-->bạn có đề sai

Phân số \(\frac{15}{27}=\frac{5}{9}\)vì \(\frac{15}{27}=\frac{15\div3}{27\div3}=\frac{5}{9}.\)

=27.15-27.12-15.27+15.12

=-27.12+15.12

=12.(-27+15)

=12.(-12)

=-144

Cách 2

=27.3-15.15

=81-225

=-144

'x' là nhân hay là tìm x zậy bạn

>.<

-27/5 . -4/15 + -4/15 . ( 2021 - 27/5)

=-4/15.[(-27/5)+2021-27/5]

=-4/15.2012,2

= -40244/75

 -27/5 . -4/15 + -4/15 . ( 2021 - 27/5)

=-4/15.[(-27/5)+2021-27/5]

=-4/15.2012,2

= -40244/75

\(\frac{-27}{5}.\frac{-4}{15}+\frac{-4}{15}.\left(2010+\frac{27}{5}\right)\)

\(=\frac{-4}{15}.\left(\frac{-27}{5}+2010+\frac{27}{5}\right)\)

\(=\frac{-4}{15}.2010\)

\(=-536\)

Học tốt

\(-\frac{27}{5}.\left(-\frac{4}{15}\right)+\left(-\frac{4}{15}\right).\left(2010-\frac{-27}{5}\right)\)

\(=\left(-\frac{4}{15}\right)\left(2010-\frac{-27}{5}+\frac{-27}{5}\right)\)

\(=-\frac{4}{15}.\left(2010+\frac{27}{15}-\frac{27}{15}\right)\)

\(=-\frac{4}{15}.2010=-536\)

Tính

\(-\frac{27}{5}.\frac{-4}{15}+\frac{-4}{15}\left(2010-\frac{-27}{5}\right)\)

\(=-\frac{27}{5}.\frac{-4}{15}+\frac{-4}{15}\left(\frac{10050}{5}+\frac{27}{5}\right)\)

\(=-\frac{27}{5}.\frac{-4}{15}+\frac{-4}{15}.\frac{10077}{5}\)

\(=-\frac{4}{15}\left(-\frac{27}{5}+\frac{10077}{5}\right)\)

\(=-\frac{4}{15}.2010=-536\)