(x+34):25=11
tính bằng 2 cách
a, 25 x (4 + 6)
b, 34 x 11 - 34 x 5
a. 25 x 10 =250
C2: 25 x4 + 25 x 6 = 250
b. 374 - 170 =204
C2 : 34 x ( 11 -5 ) = 34 x 6 = 204
25 - ( 11+x ) = x-(34-18)
25 -(11+x ) =x-( 34- 18 )
=>25-11-x=x-34+18(quy tắc mở dấu ngoặc)
=>25-11+34-18=x+x(quy tắc chuyển vế)
=> 30=2x
=>15
\(25-\left(11+x\right)=x-\left(34-18\right)\)
\(25-11-x=x-16\)
\(14-x=x-16\)
\(14+16=x+x\)
\(30=2x\)
\(\Rightarrow x=30:2\)
\(\Rightarrow x=15\)
Vậy \(x=15\)
25 - ( 11 + x ) = x - ( 34 - 18 )
<=> 25-11-x=x-34+18(quy tắc đổi dấu)
<=>25-11+34-8=x+x(phương trình)
<=>40=2x
<=>x=20
25-(11.x)bằng x-(34-18)
25-(11.x)bằng x-(34-18)
<=> 25 - 11x = x - 34 + 18
<=> -11x - x = -34 + 18 - 25
<=> -12x = -41
<=> x = -41 : (-12)
<=> x = 41/12
17/25 x 11/28 + 34/50 x 17/28
17/25 x 11/28 + 34/50 x 17/28 = ?
\(\frac{17}{25}\times\frac{11}{28}+\frac{34}{50}\times\frac{17}{28}=\frac{187}{700}+\frac{289}{700}=\frac{17}{25}\)
\(\frac{17}{25}\cdot\frac{11}{28}+\frac{34}{50}\cdot\frac{17}{28}\)
\(=\frac{187}{700}+\frac{578}{1400}\)
=\(\frac{952}{1400}\)
=\(\frac{119}{175}\)
Tìm x :
c , 25 - ( 11 + x ) = x - ( 34 - 18 )
d , 2 - x = 17 - ( - 5 )
bài 1:
a) 25 - 18 + ( -43 )
b) (-34) + 11 + |-34|+ (-11)+105
c) 64 + 125 x 147 -47 x 125
d ) 360 : 12 x 2 + [ (11 - 4)3 -343 ] x 20172018
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