A= \(\frac{19}{23}\)

\(\frac{19}{23}\)

\(\frac{8}{3}\cdot\frac{2}{5}\cdot\frac{3}{8}\cdot10\cdot\frac{19}{92}=\left(\frac{8}{3}\cdot\frac{3}{8}\right)\cdot\left(\frac{2}{5}\cdot10\right)\cdot\frac{19}{92}=1\cdot4\cdot\frac{19}{92}=4\cdot\frac{19}{92}=\frac{19}{23}\)

\(\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}\)

\(=(\frac{8}{3}.\frac{3}{8}).(\frac{2}{5}.10).\frac{19}{92}\)

\(=4.\frac{19}{92}\)

\(=\frac{19}{23}\)

Hok tôt !!!!!!!!!!!!!!!

A= \(\frac{-4}{5}+\frac{4}{3}-\frac{5}{4}+\frac{14}{5}-\frac{7}{3}\)

=\(2-1-\frac{5}{4}\)

=\(\frac{-1}{4}\)

\(\frac{8.2.3.19}{3.5.8.10.92}=\frac{19}{2300}\)

Mk sửa đề nha :

\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}+\frac{12}{7}\)

   \(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

   \(=\frac{-5}{7}.1+\frac{12}{7}\)

   \(=\frac{-5}{7}+\frac{12}{7}\)

   \(=1\)

Study well ! >_<

a) 5 . 3 ² - 3 . 2 ³

= 3 ( 5 . 3 - 2 ³ )

=  3 . ( 15 - 8 )

= 3 . 7

= 21

b) 86 + ( - 335 ) + 114 + ( - 65 )

= 86 + 114 + ( - 335 ) + ( - 65 )

= 200 + ( - 400 )

= - 200

\(a)\) \(\left(-4,125\right).0,01=-0,04125\)

\(b)\) \(\left(-28,45\right):\left(-0,01\right)=2845\)

a) -0,04125

b, 2845