\(=\dfrac{2x}{x-5}+\dfrac{x}{x+5}+\dfrac{-20x}{\left(x-5\right)\left(x+5\right)}\\ =\dfrac{2x\left(x+5\right)}{\left(x-5\right)\left(x+5\right)}+\dfrac{x\left(x-5\right)}{\left(x-5\right)\left(x+5\right)}+\dfrac{-20x}{\left(x-5\right)\left(x+5\right)}\\ =\dfrac{2x^2+10x+x^2-5x-20x}{\left(x-5\right)\left(x+5\right)}\\ =\dfrac{3x^2-15x}{\left(x-5\right)\left(x+5\right)}\\ =\dfrac{3x}{x+5}\)

Tính:

a)\(\dfrac{9}{7}-\dfrac{6}{5}=\)\(\dfrac{45}{35}-\dfrac{42}{35}=\dfrac{3}{35}\)

b)\(\dfrac{21}{18}-\dfrac{10}{9}=\dfrac{21}{18}-\dfrac{20}{18}=\dfrac{1}{18}\)

a) \(\dfrac{9}{7}\)-\(\dfrac{6}{5}\)=\(\dfrac{45}{35}\)-\(\dfrac{42}{35}\)=\(\dfrac{3}{35}\)

b) \(\dfrac{21}{18}\)-\(\dfrac{10}{9}\)=\(\dfrac{21}{18}\)-\(\dfrac{20}{18}\)=\(\dfrac{1}{18}\)

\(8,=\left(2x-3\right)\left(2x+3\right)\\ 9,=\left(1-5a^2\right)\left(1+5a^2\right)\)

8) \(-9+4x^2=\left(2x\right)^2-3^2=\left(2x-3\right)\left(2x+3\right)\)

9) \(1-25a^4=1-\left(5a^2\right)^2=\left(1-5a^2\right)\left(1+5a^2\right)\)

Bỏ () Rồi tính nhé
 

a. = 0,8 x 123 + 0,8 x 2 x 2

= 0,8 x 123 + 0,8 x 4

= 0,8 x ( 123 + 4) 

 = 101,6

b. = ( 17 + 0,9) x 99 + 72 +0,9 

= 17 x 99 + 0,9 x 99 + 72 +0,9

= 17 x 99 + 72 + 0,9 x ( 99 + 1) 

= 1683 + 72 + 0,9 x 100

= 1683 + 90 + 72 

= 1845

a. = 0,8 x 123 + 0,8 x 2 x 2

= 0,8 x 123 + 0,8 x 4

= 0,8 x ( 123 + 4) 

 = 101,6

b. = ( 17 + 0,9) x 99 + 72 +0,9 

= 17 x 99 + 0,9 x 99 + 72 +0,9

= 17 x 99 + 72 + 0,9 x ( 99 + 1) 

= 1683 + 72 + 0,9 x 100

= 1683 + 90 + 72 

= 1845

\(=2\cdot\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{97}-\dfrac{1}{99}+\dfrac{1}{99}-\dfrac{1}{101}\right)\)

\(=2\cdot\left(\dfrac{1}{3}-\dfrac{1}{101}\right)=2\cdot\dfrac{98}{303}=\dfrac{196}{303}\)

= 2/3 . 2/5 + 2/5 . 2/7 + ... + 2/99 . 2/101

= 2/3 - 2/5 + 2/5 - 2/7 + ... + 2/99 - 2/101

= 2/3 - 2/101

= 196/303

2/3 - 2/5 + 2/5 - 2/7 + 2/7 - 2/9 + .... + 2/97 - 2/99 + 2/99 - 2/101

 = 2/3 - 2/101

= 196/303

hép:(

D=1/2x2/3x3/4x...x99/100=1/100

=>D=1/100

SOS