25*4+25*3+25=
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\(\dfrac{1}{25}+\dfrac{2}{25}+\dfrac{3}{25}+\dfrac{4}{25}+\dfrac{6}{25}+\dfrac{7}{25}+\dfrac{8}{25}+\dfrac{9}{25}+\dfrac{10}{25}\)
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25 * 7 + 25 * 3 + 25 * 4 + 25 * 6 = ?
25*7+25*3+25*4+25*6
= 25*(7+3+4+6)
= 25*20
= 25*10*2
= 250*2
= 500
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25 * 7 + 25 * 3 + 25 * 4 + 25 * 6
=25x(7+3)+(4+6)
=25x(10+10)
=500
tk nha bạn
thank you bạn
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25*{7+3+4+6}
25*20
BANGBBAO NHIEU BAN TU VIET NHA
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SGK Kết nối tri thức với cuộc sống - Trang 76
24 tháng 8 2023 lúc 0:31
Tính rồi so sánh.
a) \(\dfrac{2}{9}+\dfrac{5}{9}\) và \(\dfrac{5}{9}+\dfrac{2}{9}\) b) \(\dfrac{3}{25}+\dfrac{4}{25}+\dfrac{7}{25}\) và \(\dfrac{3}{25}+\dfrac{7}{25}+\dfrac{4}{25}\)
a) \(\dfrac{2}{9}+\dfrac{5}{9}=\dfrac{7}{9};\dfrac{5}{9}+\dfrac{2}{9}=\dfrac{7}{9}\)
Vậy: \(\dfrac{2}{9}+\dfrac{5}{9}=\dfrac{5}{9}+\dfrac{2}{9}\)
b) \(\dfrac{3}{25}+\dfrac{4}{25}+\dfrac{7}{25}=\dfrac{14}{25};\dfrac{3}{25}+\dfrac{7}{25}+\dfrac{4}{25}=\dfrac{14}{25}\)
Vậy: \(\dfrac{3}{25}+\dfrac{4}{25}+\dfrac{7}{25}=\dfrac{3}{25}+\dfrac{7}{25}+\dfrac{4}{25}\)
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25 * 7 - 25 * 3 + 25 * 4 + 25 * 6 = ?
25 * 7 - 25 * 3 + 25 * 4 + 25 * 6
=25 * ( 7 -3 +4 +6 )
= 25 * 14
=350
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=25*(7-3+4+6)
=25*14
=350
2 tháng 2 2021 lúc 12:48
a)Rút gọn phân số : \(\dfrac{25^{28}+25^{24}+25^{20}+.....+25^4+1}{25^{30}+25^{28}+....+25^2+1}\)
b) Cho S = 1-3 + 32-33+.....+398-399
a) Ta có: \(\dfrac{25^{28}+25^{24}+25^{20}+...+25^4+1}{25^{30}+25^{28}+...+25^2+1}\)
\(=\dfrac{25^{24}\left(25^4+1\right)+25^{16}\left(25^4+1\right)+...+\left(25^4+1\right)}{25^{28}\left(25^2+1\right)+25^{24}\left(25^2+1\right)+...+\left(25^2+1\right)}\)
\(=\dfrac{\left(25^4+1\right)\left(25^{24}+25^{16}+25^8+1\right)}{\left(25^2+1\right)\left(25^{28}+25^{24}+...+1\right)}\)
\(=\dfrac{\left(25^4+1\right)\cdot\left[25^{16}\left(25^8+1\right)+\left(25^8+1\right)\right]}{\left(25^2+1\right)\left[25^{24}\left(25^4+1\right)+25^{16}\left(25^4+1\right)+25^8\left(25^4+1\right)+\left(25^4+1\right)\right]}\)
\(=\dfrac{\left(25^4+1\right)\left(25^8+1\right)\left(25^{16}+1\right)}{\left(25^2+1\right)\left(25^4+1\right)\left(25^{24}+25^{16}+25^8+1\right)}\)
\(=\dfrac{\left(25^8+1\right)\left(25^{16}+1\right)}{\left(25^2+1\right)\left[25^{16}\left(25^8+1\right)+\left(25^8+1\right)\right]}\)
\(=\dfrac{\left(25^8+1\right)\left(25^{16}+1\right)}{\left(25^2+1\right)\left(25^8+1\right)\left(25^{16}+1\right)}\)
\(=\dfrac{1}{25^2+1}=\dfrac{1}{626}\)
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Bài 1:Rút gọn ps
1+25^4+25^5+...+25^28/1+25^2+25^3+...+25^30
A/ 2 3/4 - ( 1/7 + 1 3/4)
B/ 7/-25 + -18/25 + 4/23 + 5/7 + 19/23
C/ -1/4 . ( 12 3/4 - 7,75 ) - 25 % . 3 1/2
e gõ latex hoặc vt r chụp lên nhé như vầy ko nhìn đc cái đề nx e
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a) \(2\dfrac{3}{4}-\left(\dfrac{1}{7}+1\dfrac{3}{4}\right)\)
\(=\dfrac{11}{4}-\dfrac{1}{7}-\dfrac{7}{4}=\left(\dfrac{11}{4}-\dfrac{7}{4}\right)-\dfrac{1}{7}=1-\dfrac{1}{7}=\dfrac{6}{7}\)
b) \(\dfrac{7}{-25}+\dfrac{-18}{25}+\dfrac{4}{23}+\dfrac{5}{7}+\dfrac{19}{23}\)
\(=\left(\dfrac{-7}{25}+\dfrac{-18}{25}\right)+\left(\dfrac{4}{23}+\dfrac{19}{23}\right)+\dfrac{5}{7}=-1+1+\dfrac{5}{7}=\dfrac{5}{7}\)
c) \(\dfrac{-1}{4}\left(12\dfrac{3}{4}-7,75\right)-25\%.3\dfrac{1}{2}\)
\(=\dfrac{-1}{4}\left(12\dfrac{3}{4}-7\dfrac{3}{4}\right)-\dfrac{1}{4}.\dfrac{7}{2}=\dfrac{-1}{4}.5-\dfrac{7}{8}\\ =-\dfrac{5}{4}-\dfrac{7}{8}=-\dfrac{17}{8}\)
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tính tổng
B= 7-7 mu 4 + 7 mu 4 -........+7 mu 301
A = 1 + 5 mũ 2 + 5 mu 4 + 5 mu 6 +.....+5 mu 200
tính
A= 1/7+1/7mu 2 + 1/7 mu 3+......+1/7mu 100
B=-4/5+4/5 mu 2 - 4/5 mu 3 + ....+4/5mu 200
tính A=25 mũ 8 + 25 mũ 4 + 25 mu 20 +......+25 mu 4 +1 / 25 mu 20 + 25 mu 28 + 25 mu 26 +.....= 25 mu 2 +1
7 × 3 mu x + 20 × 3 mu x = 3 mu 25
cho A = 4*4*4*4*4*...*4*4*4 ( 2010 số 4 ) * 25*25*25*25*.....*25*25*25 ( 1010 số 25 ) hỏi a có bao nhiêu số ?