a)

\(4\left(x-1\right)-\left(3x+2\right)=16\)

=> 4x - 4 - 3x - 2 = 16

=> x - 6 = 16

=> x = 22

Vậy .......

b)

\(7\left(x-5\right)+5\left(15-x\right)=130\)

=> 7x - 35 + 75 - 5x = 130

=> 2x + 40 = 130

=> 2x = 90

=> x = 45

Vậy........

c)

\(30\left(x-2\right)-6\left(x-5\right)-22x=100\)

=> 30x - 60 - 6x + 30 - 22x = 100

=> 2x - 30 = 100

=> 2x = 130

=> x = 65

Vậy.....

d) \(x-17+x=x-23\)

=> 2x - 17 = x - 23

=> x = -6

Vậy .......

a) 4(x-1)-(3x+2)=16 b)7(x-5)+5(15-x)=130

<=>4x-4-3x-2=16 <=>7x-35+75-5x=130

<=>x-6=16 <=>2x+40=130

<=>x=22 <=>2x=90

<=>x=45

c) 30(x- 2 ) - 6( x - 5 ) - 22x = 100 d) x-17+x=x-23

<=>30x-60-6x+30-22x=100 <=>2x-x=-23+17

<=>2x-30=100 <=>x=-6

<=>2x=130

<=>x=65

a) 4(x-1)-(3x+2)=16

<=>4x-4-3x-2=16

<=>x-6=16

<=>x=22

c) 30(x- 2 ) - 6( x - 5 ) - 22x = 100

<=>30x-60-6x+30-22x=100

<=>2x-30=100

<=>2x=130

<=>x=65

b)7(x-5)+5(15-x)=130

<=>7x-35+75-5x=130

<=>2x+40=130

<=>2x=90

<=>x=45

d) x-17+x=x-23

<=>2x-x=-23+17

<=>x=-6

<=>2x=130

<=>x=65

5 ( x - 7 ) = 5

x - 7 = 1

=> x = 8

\(5.\left(x-7\right)=130-125=5\)

\(x-7=1,x=8\)

=>5(x-7)=5

=>x-7=1

hay x=8

|5+6+9+7+3+8+5+4+72+569+45555+535+45555+78982+45|*|123+(7-130)|

=|5+6+9+7+3+8+5+4+72+569+45555+535+45555+78982+45|*|123-123|

=0

**************nha

a , 3^x - 4 = 5⁷ : 5⁶

    3^x - 4 = 5^7-6

     3^x -4 = 5

      3^x = 9 

      3^x = 3²

  suy ra x = 2 

Vậy x =2 

b , 3^x-1 = 27

     3^x-1 = 3³

suy ra x - 1 =3 suy ra x = 3-1 =2 

Vậy x =2 

c , (x-1)³ = 4(x-1)

( x - 1)³ : ( x-1 ) = 4

  (x-1)^3-1 = 4

   (x-1)² = 2²

suy ra x-1 =2 suy ra x = 2+1 =3

Vậy x =3

d , 5^x . 5^x-2 = 130

 5^x . 5^x : 5² = 130 

5^2x       = 130 x 25

5^2s      = 3250

suy ra x thuộc rỗng

Vậy x thuộc rỗng

a) 3^x -4 =5^7  : 5^6 

3^x -4 =5

3^x=9

x=2

 b ) 3^x-1=26

 3^x=27

x=3

\(3^x-4=5^7:5^6\)

\(3^x-4=5\)

\(3^x=5+4\)

\(3^x=9\)

\(\Rightarrow x=2\)

\(3^x-1=26\)

\(3^x=26+1\)

\(3^x=27\)

\(\Rightarrow x=3\)

mk sẽ gửi câu hỏi tiếp nha

(x + 1) + (x + 3) + (x + 5) + (x + 7) + (x + 9) = 130

=> x + 1 + x + 3 + x + 5 + x + 7 + x + 9 = 130

=> (x + x + x + x + x) + (1 + 3 + 5 + 7 + 9) = 130

=> 5x + \(\frac{\left(1+9\right)\cdot5}{2}\)= 130

=> 5x + 25 = 130

=> 5x = 105

=> x = 105 : 5 = 21

( x + 1 ) + ( x + 3 ) + ( x + 5 ) + ( x + 7 ) + ( x + 9 ) = 130 

x + 1 + x + 3 + x + 5 + x + 7 + x + 9 = 130 

5x + 25 = 130 

5x = 130 - 125 

5x = 105 

x = 21

(x+1)+(x+3)+(x+5)+(x+7)+(x+9)=130

(x+x+x+x+x)+(1+3+5+7+9)=130

5x+25=130

5x=130-25

5x=105

x=105:5

x=21

Hok tốt !!!!!!!!!!!!!!!!!!!!!

\(12\left(x+5\right)+2x=130\\\Leftrightarrow 12x+60+2x=130\\ \Leftrightarrow14x=70\\ \Leftrightarrow x=5\\ ----\\ 23\left(x-5\right)-12x=138\\ \Leftrightarrow23x-115-12x=138\\ \Leftrightarrow23x-12x=138+115\\ \Leftrightarrow11x=253\\ \Leftrightarrow x=\dfrac{253}{11}=23\\ ----\\ 360-12x+23\left(x-5\right)=278\\ \Leftrightarrow360-12x+23x-115=278\\ \Leftrightarrow-12x+23x=278+115-360\\ \Leftrightarrow11x=33\\ \Leftrightarrow x=\dfrac{33}{11}=3\)

\(6\left(x+3\right)+3\left(x-5\right)=278\\ \Leftrightarrow6x+18-3x-15=278\\ \Leftrightarrow6x-3x=278+15-18\\ \Leftrightarrow3x=275\\ \Leftrightarrow x=\dfrac{275}{3}\\ ---\\ \left(7-x\right)\left(3x-90\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}7-x=0\\3x-90=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=30\end{matrix}\right.\)

\(\left(x-2\right)\left(4x-2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\4x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\4x=2\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{2}\end{matrix}\right.\\ ---\\ \left(2x-18\right)\left(3x-9\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-18=0\\3x-9=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=18\\3x=9\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=9\\x=3\end{matrix}\right.\)

bài 1

a, X/Y x 1/5=3/10

X/Y=3/10:1/5

X/Y=3/2

b, 3/4 x X/Y= 6/5

X/Y=3/4:6/5

X/Y=5/8

Bài 2:

a, >     b, <       c,=        d,<

a.1+3+5+7+...+2x+1=225

[(2x+1-1):2+1]x(2x+1+1):2=225

(x+1)x(2x+2):2=225

(x+1)x(x+1)=225

(x+1)²=225

(x+1)²=15²

x+1=15

x=14

_______________

b. 130-[5.(9-x)+43]=47

    5.(9-x)+43=83

  5.(9-x)=40

9-x=8

x=1

_______________

c.16^x<32⁴

2^4x<2²⁰

=>x∈{0;1;2;3;4}

a: =>(x+1)^2=225

=>x+1=15

=>x=14

b: =>[5*(9-x)+43]=130-47=83

=>5(9-x)=40

=>9-x=8

=>x=1

c: =>2^4x<2^20

=>4x<20

=>0<x<5