Tìm x . \(\frac{3}{5}\div\frac{7}{x}\div\frac{3}{4}=\frac{12}{105}\)
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tìm x trong tỉ lệ thức sau :
a) \(2\frac{1}{3}\div\frac{1}{3}=\frac{7}{9}\div x\) b) \(x\div\frac{1}{3}=\frac{12}{99}\div\frac{15}{90}\)
c) \(\frac{4}{9}\div x=3\frac{1}{3}\div2,25\) d ) \(\frac{3}{4}\div\frac{41}{99}=x\div\frac{75}{90}\)
Tìm x biết:
a)\(\frac{3}{5}\times x-\frac{1}{5}=\frac{4}{5}\)
b)\(\frac{4}{7}+\frac{5}{7}\div x=1\)
c)\(\frac{-12}{7}\times\left(\frac{3}{4}-x\right)\times\frac{1}{4}=-1\)
d)\(x\div\frac{17}{8}=\frac{-2}{5}\times\frac{-9}{17}+3\)
a) \(\frac{3}{5}.x-\frac{1}{5}=\frac{4}{5}\)
\(\Leftrightarrow\frac{3}{5}.x=\frac{4}{5}+\frac{1}{5}\)
\(\Leftrightarrow\frac{3}{5}.x=1\)
\(\Leftrightarrow x=1:\frac{3}{5}\)
\(\Leftrightarrow x=\frac{5}{3}\)
Vậy : \(x=\frac{5}{3}\)
b) \(\frac{4}{7}+\frac{5}{7}:x=1\)
\(\Leftrightarrow\frac{5}{7}:x=1-\frac{4}{7}\)
\(\Leftrightarrow\frac{5}{7}:x=\frac{3}{7}\)
\(\Leftrightarrow x=\frac{5}{7}:\frac{3}{7}\)
\(\Leftrightarrow x=\frac{5}{3}\)
Vậy : \(x=\frac{5}{3}\)
c) \(-\frac{12}{7}.\left(\frac{3}{4}-x\right).\frac{1}{4}=-1\)
\(\Leftrightarrow\frac{-12.1}{7.4}.\left(\frac{3}{4}-x\right)=-1\)
\(\Leftrightarrow-\frac{3}{7}.\left(\frac{3}{4}-x\right)=-1\)
\(\Leftrightarrow\frac{3}{4}-x=-1:\left(-\frac{3}{7}\right)\)
\(\Leftrightarrow\frac{3}{4}-x=\frac{7}{3}\)
\(\Leftrightarrow x=\frac{3}{4}-\frac{7}{3}=-\frac{19}{12}\)
Vậy : \(x=-\frac{19}{12}\)
d) \(x:\frac{17}{8}=-\frac{2}{5}.-\frac{9}{17}+3\)
\(\Leftrightarrow x:\frac{17}{8}=\frac{273}{85}\)
\(\Leftrightarrow x=\frac{273}{85}.\frac{17}{8}\)
\(\Leftrightarrow x=\frac{273}{40}\)
Vậy : \(x=\frac{273}{40}\)
\(\)
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\(Tìm\)\(x\)\(\in\)\(ℤ\)biết :a) -1\(1\frac{4}{12}-1\frac{3}{12}\le x\le\frac{4}{3}.\frac{13}{4}\)
b)\(\left(\frac{x}{-5}+\frac{2}{3}\right):2\frac{1}{5}-1,4.\frac{15}{49}=|\frac{-5}{21}|\)
ai nhanh mk tick
Bài 1 : Tính C (frac{2}{3}- frac{1}{4}+ frac{5}{11}) div( frac{5}{12}+ 1 - frac{7}{11}) F 12frac{1}{3}- frac{5}{7}div( 24 - 23frac{5}{7}) Bài 2 : Tìm x biếtfrac{1}{4}+ frac{1}{3}div3x -5( frac{3}{5}x - 0,75 ) divfrac{3}{7} 2frac{4}{5}2frac{1}{4}div( x - 7frac{1}{3}) -1,5
Đọc tiếp
Bài 1 : Tính
C = (\(\frac{2}{3}\)- \(\frac{1}{4}\)+ \(\frac{5}{11}\)) \(\div\)( \(\frac{5}{12}\)+ 1 - \(\frac{7}{11}\))
F = 12\(\frac{1}{3}\)- \(\frac{5}{7}\)\(\div\)( 24 - 23\(\frac{5}{7}\))
Bài 2 : Tìm x biết
\(\frac{1}{4}\)+ \(\frac{1}{3}\)\(\div\)3x = -5
( \(\frac{3}{5}\)x - 0,75 ) \(\div\)\(\frac{3}{7}\)= 2\(\frac{4}{5}\)
2\(\frac{1}{4}\)\(\div\)( x - 7\(\frac{1}{3}\)) = -1,5
tìm x biết
1, \(x\cdot\frac{6}{25}=\frac{15}{-13}\)
2, \(x\div\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\)
3, \(\frac{3}{8}-\frac{1}{6}\cdot x=\frac{1}{4}\)
4, \(\frac{1}{3}+\frac{1}{2}\div x=-4\)
5, \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
\(x\times\frac{6}{25}=\frac{15}{-13}\)
x=\(\frac{15}{-13}\div\frac{6}{25}\)
x=\(-\frac{125}{26}\)
các câu còn lại làm tương tự nha!!!
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\(1.x.\frac{6}{25}=\frac{15}{-13}\\ x=\frac{15}{-13}:\frac{6}{25}\\ x=-\frac{125}{26}\)
\(2.x:\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\\ x:\frac{4}{10}=\frac{11}{45}\\ x=\frac{11}{45}.\frac{4}{10}\\ x=\frac{22}{225}\)
\(3.\frac{3}{8}-\frac{1}{6}.x=\frac{1}{4}\\ \frac{1}{6}.x=\frac{3}{8}-\frac{1}{4}\\ \frac{1}{6}.x=\frac{1}{8}\\ x=\frac{1}{8}:\frac{1}{6}\\ x=\frac{3}{4}\)
\(4.\frac{1}{3}+\frac{1}{2}:x=-4\\ \frac{1}{2}:x=-4-\frac{1}{3}=-\frac{13}{3}\\ x=\frac{1}{2}:\left(-\frac{13}{3}\right)=-\frac{3}{26}\)
\(5.x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}=\frac{5}{6}\\ x=\frac{5}{6}-\frac{7}{12}\\ x=\frac{1}{4}\)
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tìm x biết
1, \(x\cdot\frac{6}{25}=\frac{15}{-13}\)
2, \(x\div\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\)
3, \(\frac{3}{8}-\frac{1}{6}\cdot x=\frac{1}{4}\)
4, \(\frac{1}{3}+\frac{1}{2}\div x=-4\)
5, \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
Tìm x : \(\frac{\left(x-3\right)^2}{2}-1\frac{1}{3}\left(x+2\right)^2-\frac{5}{4}\left(x-1\right)\left(x+1\right)=1\frac{1}{2}x\left(x-2\right)-x-4\)
\(\frac{2}{3}-\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\hept{\begin{cases}\\\end{cases}2\frac{2}{5}+\frac{3}{5}x=\frac{3}{4}}\)
3/x-5 = -4/x+2
=> 3(x+2) = -4(x-5)
=> 3x + 6 = -4x + 20
=> 3x + 4x = 20 - 6
=> 7x - 14
=> x = 2
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Bài trên dễ tự làm
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
\(\Rightarrow3\cdot(x+2)=-4\cdot(x-5)\)
\(\Rightarrow3x+6=-4x-20\)
\(\Rightarrow-4x-3x=6-20\)
\(\Rightarrow-7x=-14\Rightarrow x=2\)
\(2\frac{2}{5}+\frac{3}{5}x=\frac{3}{4}\)
\(\Rightarrow\frac{12}{5}+\frac{3}{5}x=\frac{3}{4}\)
Tự làm nốt
Mình bận một số công việc cho mk xin lỗi
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Tính nhanh
a) \(\frac{2}{3}\div\frac{4}{9}+\frac{1}{3}\div\frac{4}{9}=\)
b) \(\frac{9}{8}\div\frac{5}{7}-\frac{1}{8}\div\frac{5}{7}=\)
c) \(\frac{2}{5}\div\frac{7}{3}-\frac{2}{5}\div\frac{1}{3}=\)
d) \(\frac{3}{7}\div\frac{7}{3}+\frac{3}{7}\div\frac{9}{4}=\)
a)\(\frac{2}{3}:\frac{4}{9}+\frac{1}{3}:\frac{4}{9}\)
=\(\frac{4}{9}:\left(\frac{2}{3}+\frac{1}{3}\right)\)
=\(\frac{4}{9}:1=\frac{4}{9}\)
b
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