\(\left(-3,2\right).\dfrac{15}{64}-\left(0,8-2\dfrac{4}{15}\right):3\dfrac{2}{3}\\ =-\dfrac{16}{5}.\dfrac{15}{64}-\left(\dfrac{4}{5}-\dfrac{34}{15}\right):\dfrac{11}{3}\\ =-\dfrac{3}{4}-\left(-\dfrac{22}{15}\right).\dfrac{3}{11}\\ =-\dfrac{3}{4}-\left(-\dfrac{2}{5}\right)=-\dfrac{3}{4}+\dfrac{2}{5}=-\dfrac{7}{20}\)

\(\left(-3,2\right).\dfrac{-15}{64}+\left(0,8-2\dfrac{4}{15}\right):3\dfrac{2}{3}\)

\(=\left(\dfrac{-16}{5}\right).\dfrac{-15}{64}+\left(\dfrac{4}{5}-\dfrac{34}{15}\right):\dfrac{11}{3}\)

\(=\left(\dfrac{-16}{5}\right).\dfrac{-15}{64}+\left(\dfrac{-22}{15}\right).\dfrac{3}{11}\)

\(=\dfrac{3}{4}+\left(\dfrac{-2}{5}\right)\)

\(=\dfrac{7}{20}\)

\(-3,2\cdot\left(-\dfrac{15}{64}\right)+0,8-\dfrac{2}{\dfrac{4}{15}}:\dfrac{3}{\dfrac{2}{3}}\)

\(=\dfrac{3}{4}+\dfrac{4}{5}-\dfrac{15}{2}:\dfrac{9}{2}\)

\(=\dfrac{31}{20}-\dfrac{5}{3}\)

\(=-\dfrac{7}{60}\)

Đề bài như này đúng không nhỉ bạn?

\(\dfrac{-3}{2}\times\dfrac{-15}{64}+\left(0,8-2\dfrac{4}{5}\right):3\dfrac{2}{3}\\ =\dfrac{45}{128}+\left(-2\right)\times\dfrac{3}{11}\\ =\dfrac{45}{128}-\dfrac{6}{11}\\ =-\dfrac{273}{1408}\)

\(\left(-3,2\right).\frac{-15}{64}+\left(0,8-2\frac{4}{15}\right):3\frac{2}{3}\)

\(=\frac{3}{4}+\frac{-22}{15}:\frac{11}{3}\)

\(=\frac{3}{4}+\frac{-2}{5}=\frac{7}{20}\)

\(\left(-3,2\right).\left(\frac{-15}{64}\right)+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)

đúng đề bài này ko

\(\left(-3,2\right).\left(\frac{-15}{64}\right)+\left(0,8-2\frac{4}{15}\right):3\frac{1}{2}\)

\(=\frac{-16}{5}.\left(\frac{-15}{64}\right)+\left(\frac{4}{5}-\frac{34}{15}\right):\frac{7}{2}\)

\(=\frac{3}{4}+\left(\frac{-22}{15}\right):\frac{7}{2}\)

\(=\frac{3}{4}-\frac{44}{105}\)

\(=\frac{139}{420}\)

( - 3,2 ) . \(\frac{-15}{64}\)+ ( 0,8 - \(2\frac{4}{15}\)) : \(3\frac{1}{2}\)

= \(\frac{3}{4}+\frac{-22}{15}:\frac{7}{2}\)

= \(\frac{3}{4}+\frac{-44}{105}\)

= \(\frac{139}{420}\)