Giải chi tiết bài lm ra nha m.n ;-;

b) Ta có: \(1-\dfrac{530}{570}=\dfrac{40}{570}\)

\(1-\dfrac{531}{571}=\dfrac{40}{571}\)

mà \(\dfrac{40}{570}>\dfrac{40}{571}\)

nên \(1-\dfrac{530}{570}>1-\dfrac{531}{571}\)

\(\Leftrightarrow\dfrac{530}{570}< \dfrac{531}{571}\)

Tương tự như bài trên:

\(\dfrac{33}{131}=1-\dfrac{98}{131}< 1-\dfrac{98}{151}=\dfrac{53}{151}\)

a, vì 33<53

       131<151

=>\(\dfrac{33}{131}< \dfrac{53}{151}\)

b, Vì 530<531

       570<571

\(\Rightarrow\dfrac{530}{570}< \dfrac{531}{571}\)

a) n_CuCl2 = 0,15.2 = 0,3 (mol)

PTHH: 2Al + 3CuCl₂ --> 2AlCl₃ + 3Cu

____0,2<------0,3--------->0,2---->0,3

=> m = 0,3.64 - 0,2.27 = 13,8 (g)

b) \(C_{M\left(AlCl_3\right)}=\dfrac{0,2}{0,15}=1,3333M\)

\(\left|1-2x\right|< 5-x\)

\(\Leftrightarrow-\left(5-x\right)< 1-2x< 5-x\)

\(\Leftrightarrow x-5< 1-2x< 5-x\)

\(\Leftrightarrow-4< x< 2\)

Ta có : | 1 − 2 x | < 5 − x

=> − ( 5 − x ) < 1 − 2 x < 5 − x

=>  x − 5 < 1 − 2 x < 5 − x

=> − 4 < x < 2