2. Số tự nhiên x:
a, 12+2x=6^3:6^2
b, 48:x+17=33
c, (9x+2).5+28=83
d, 187-2(x+5)=125
Giúp mìnk zớii
Những câu hỏi liên quan
Tìm x:a) 3xleft(3x-8right)-9x^2+80b)6x-15-xleft(5-2xright)0c) x^3-16x0d) 2x^2+3x-50e) 3x^2-xleft(3x-6right)36f) left(x+2right)^2-left(x-5right)left(x+1right)17g) left(x-4right)^2-xleft(x+6right)9h) 4xleft(x-1000right)-x+10000i) x^2-360j) x^2y-2+x+x^2-2y+xy0k) xleft(x+1right)-left(x-1right).left(2x-3right)0l) 3x^3-27x0
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Tìm x:
a) \(3x\left(3x-8\right)-9x^2+8=0\)
b)\(6x-15-x\left(5-2x\right)=0\)
c) \(x^3-16x=0\)
d) \(2x^2+3x-5=0\)
e) \(3x^2-x\left(3x-6\right)=36\)
f) \(\left(x+2\right)^2-\left(x-5\right)\left(x+1\right)=17\)
g) \(\left(x-4\right)^2-x\left(x+6\right)=9\)
h) \(4x\left(x-1000\right)-x+1000=0\)
i) \(x^2-36=0\)
j) \(x^2y-2+x+x^2-2y+xy=0\)
k) \(x\left(x+1\right)-\left(x-1\right).\left(2x-3\right)=0\)
l) \(3x^3-27x=0\)
Tìm số tự nhiên x:
e, 96-5(2x-1)=41
f, 2x^2-15=17
g,(3x-2)^2+15=64
h, 3(x+5)-2.3^2=21
i, 5^x+9=134.1^2010
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e) 96-5(2x-1)=41
5(2x-1)= 96-41
5(2x-1)=55
2x-1=55:5
2x-1=11
2x=11+1
2x=12
x=12:2
x=6
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tìm số tự nhiên x , bt 1 ) 65 - 5( 2x+6)= 25 2) 265 :[12-(x+3)] = 64 3) ( 2x - 1 )^4 = 81 4) 3^x+2013 : 27 = 3 ^ 2012 5) 28 x 2 ^ x+1 - 22.2^x+1 = 96 6) 2^3.(x-1)^3 = 512 7) 20 chia hết ( x-3) và 42 chia hết cho ( x-3) 8) (x-5) chia hết cho 6 ,( x-5) chia hết cho 8 , (x+5) chia hết cho 20 và 0 x 150 9) ( x+ 2) + (x+12) + ( x + 42 ) + ( x + 47) =655 10 ) x+ ( x+1) +(x+2) +...+ ( x+2008) = 2008.2009 11) 1+2+3+...+x=820
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1: =>5(2x+6)=40
=>2x+6=8
=>2x=2
=>x=1
2: =>12-(x+3)=256:64=4
=>(x+3)=8
=>x=5
3: =>2x-1=3 hoặc 2x-1=-3
=>x=2 hoặc x=-1
4: \(\Leftrightarrow3^{x+2017}=3^{2015}\)
=>x+2017=2015
=>x=-2
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1: =>5(2x+6)=40
=>2x+6=8
=>2x=2
=>x=1
2: =>12-(x+3)=256:64=4
=>(x+3)=8
=>x=5
3: =>2x-1=3 hoặc 2x-1=-3
=>x=2 hoặc x=-1
4:
=>x+2017=2015
=>x=-2
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tìm x , biết
a) 17/6- x( x-7/6)= 7/4
b) 3/35 - ( 3/5-x)= 2/7
tìm x thuộc Z , biết
3/4-5/6 < x/12 < 1 -( 2/3-1/4)
tìm x biết
a ) 2x-3=x + 1/2
b) 4x- ( x+ 1/2) = 2x - ( 1/2 - 5 )
Bài 1:
a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)
\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)
\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)
\(\Leftrightarrow-12x^2+14x+13=0\)
\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)
b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)
\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)
hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)
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Bài 3:
a) Ta có: \(2x-3=x+\dfrac{1}{2}\)
\(\Leftrightarrow2x-x=\dfrac{1}{2}+3\)
\(\Leftrightarrow x=\dfrac{7}{2}\)
b) Ta có: \(4x-\left(x+\dfrac{1}{2}\right)=2x-\left(\dfrac{1}{2}-5\right)\)
\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{1}{2}-5=0\)
\(\Leftrightarrow x=5\)
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Tìm x:a) (2x - 3)(6 - 2x) 0b) 5dfrac{4}{7}:x13 c) 2x - dfrac{3}{7} 6dfrac{2}{7}d) dfrac{x}{5} + dfrac{1}{2} dfrac{6}{10}e) dfrac{x+3}{15}dfrac{1}{3}f) dfrac{x-12}{4}dfrac{1}{2}g) 2dfrac{1}{4}.left(x-7dfrac{1}{3}right)1,5h) left(4,5-2xright).1dfrac{4}{7}dfrac{11}{14}i) dfrac{2}{3}left(x-25%right)dfrac{1}{6}k) dfrac{3}{2}x-1dfrac{1}{2}x-dfrac{3}{4}
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Tìm x:
a) (2x - 3)(6 - 2x) = 0
b) \(5\dfrac{4}{7}:x=13\)
c) 2x - \(\dfrac{3}{7}\) = \(6\dfrac{2}{7}\)
d) \(\dfrac{x}{5}\) + \(\dfrac{1}{2}\) = \(\dfrac{6}{10}\)
e) \(\dfrac{x+3}{15}=\dfrac{1}{3}\)
f) \(\dfrac{x-12}{4}=\dfrac{1}{2}\)
g) \(2\dfrac{1}{4}\).\(\left(x-7\dfrac{1}{3}\right)=1,5\)
h) \(\left(4,5-2x\right).1\dfrac{4}{7}=\dfrac{11}{14}\)
i) \(\dfrac{2}{3}\left(x-25\%\right)=\dfrac{1}{6}\)
k) \(\dfrac{3}{2}x-1\dfrac{1}{2}=x-\dfrac{3}{4}\)
a) (2x - 3)(6 - 2x) = 0
=> \(\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.=>\left[{}\begin{matrix}2x=3\\2x=6\end{matrix}\right.=>\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)
b) \(5\dfrac{4}{7}:x=13=>\dfrac{39}{7}:x=13=>x=\dfrac{39}{7}:13=>x=\dfrac{3}{7}\)
c) \(2x-\dfrac{3}{7}=6\dfrac{2}{7}=>2x-\dfrac{3}{7}=\dfrac{44}{7}=>2x=\dfrac{47}{7}=>x=\dfrac{47}{14}\)
d) \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}=>\dfrac{x}{5}=\dfrac{6}{10}-\dfrac{1}{2}=>\dfrac{x}{5}=\dfrac{1}{10}=>x.10=5=>x=\dfrac{1}{2}\)
e) \(\dfrac{x+3}{15}=\dfrac{1}{3}=>\left(x+3\right).3=15=>x+3=5=>x=2\)
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f)\(\dfrac{x-12}{4}=\dfrac{1}{2}=\dfrac{x-12}{4}=\dfrac{2}{4}\)
⇒\(x-12=2\)
\(x=2+12\)
x = 14
g)2\(\dfrac{1}{4}.\left(x-7\dfrac{1}{3}\right)=1,5\)
\(\dfrac{9}{4}.\left(x-\dfrac{22}{3}\right)=1,5\)
\(\left(x-\dfrac{22}{3}\right)=\dfrac{3}{2}:\dfrac{9}{4}\)
\(x-\dfrac{22}{3}=\dfrac{2}{3}\)
\(x=\dfrac{2}{3}+\dfrac{22}{3}\)
\(x=8\)
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Xem thêm câu trả lời
Giải bất phương trình bài toán sau :
1. 8x-1/9 +3x-2/4<43+8x/12 + 35x/36
2. 5x-17/14+x-3/26 > 29-9x/91
3. x-2/5+2(x+1)/3 > 13x-8/15
4. x/30+1/6-x/5 > 2x/45+16
5. 8x+5/6+4x+3/6<3(x-2)/30
6. x+7/10-x-5/5>x-9/3
7. 9(x-1)-2(3x+4)<3(x-1)
8. x+7/4-2x-3/7<2x+3/8-8x+5/28
Tìm x là số tự nhiên:
a, (x-6)^2=9
b,720:[41- (2x-5)]=2^3.5
c, [(4x+28).3+55] :5=35
a, vì : 32 = 9
=> x - 6 = 3
=> x = 9
b, 720 : [ 41 - ( 2x - 5 ) ] = 40
41 - ( 2x - 5 ) = 720 : 40 = 18
2x - 5 = 41 - 18 = 23
2x = 23 + 5 = 28
x = 28 : 2 = 14
c, ( 4x + 28 ) . 3 + 55 = 35 . 5 = 175
( 4x + 28 ) . 3 = 175 - 55 = 120
4x + 28 = 120 : 3 = 40
4x = 40 - 28 = 12
x = 12 : 4 = 3
**** GIÙM MK NHA , TKS
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Bài 1: Tìm số tự nhiên x, biết:
a,36 : [ 7(x - 3) + 4 ] = 24 :23
b,[(6x - 39) : 3 ] . 28 = 5628
c,(2x -7) - (x + 135)=0
d,24 .125 + 52 . 25
e,17 . 27 +17 . 25 + 17 . 48
g,122 + (37 - 3x) = 0
h,(14 - 3x) + (6+x) = 0
tìm x:
a)3(2x-3)+2(2-x)=-3
b)2x(x2-2)+x2(1-2x)-x2=-12
c)3x(2x+3)-(2x+5)(3x-2)=8
d)4x(x - 1) - 3(x2-5)-x2=(x-3)-(x+4)
e)2(3x-1)(2x+5)-6(2x-1)(x+2)=-6
a: Ta có: \(3\left(2x-3\right)+2\left(2-x\right)=-3\)
\(\Leftrightarrow6x-9+4-2x=-3\)
\(\Leftrightarrow4x=2\)
hay \(x=\dfrac{1}{2}\)
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