\(\frac{50^{15}\cdot13^{18}}{25^7\cdot26^{15}\cdot5^{16}}=\frac{5^{15}\cdot2^{15}\cdot13^{18}}{5^{14}\cdot13^{15}\cdot2^{15}\cdot5^{16}}=\frac{5^{15}\cdot2^{15}\cdot13^{18}}{5^{30}\cdot2^{15}\cdot13^5}=\frac{13^{13}}{5^{15}}\)

bạn Đào Trọng Luân ơi, hình như sai thì phải!

A=4/(7.31)+6/(7.41)+9/(10.41)+7/(10.51) 
=20/(35.31)+30/(35.41)+45/(50.41) 
+35/(50.51) 
=5[4/(35.31)+6/(35.41)+9/(50.41) 
+7/(50.51)] 
=5(1/31-1/35+1/35-1/41+1/41-1/50 
+1/50-1/57) 
=5(1/31-1/57) 
B=7/(19.31)+5/(19.43)+3/(23.43) 
+11/(23.57) 
tương tự ta nhân cả tử và mẫu của các phân số biểu thức B với 2 
=>B=2(1/31-1/57) 
=>A/B=5/2

\(\frac{60^8}{12^7.5^8}=\frac{2^{16}.3^8.5^8}{2^{14}.3^7.5^8}=\frac{2^2.3}{1}=12\)

\(\frac{50^{15}.13^{18}}{25^7.26^{15}.5^{16}}=\frac{2^{15}.5^{30}.13^{18}}{5^{30}.2^{15}.13^{15}}=2197\)

\(\frac{10^4}{5^3}=\frac{5^4.2^4}{5^3}=80\)

\(\frac{60^8}{12^7.5^8}=\frac{2^3.3}{1}=12\)

\(\frac{50^{15}.13^{18}}{25^7.26^{15}}=2197\)

\(10^4:5^3=10000:125=80\)

=4/217+6/287+9/410+7/570

=130/1767

\(y=\frac{50^{15}.13^{18}}{25^7.26^{15}.5^{16}}=\frac{\left(2.5\right)^{15}.13^{18}}{\left(5^2\right)^7.\left(2.13\right)^{15}.5^{16}}=\frac{2^{15}.5^{15}.13^{18}}{5^{14}.5^{16}.2^{15}.13^{15}}=\frac{2^{15}.5^{15}.13^{18}}{5^{30}.2^{15}.13^{15}}=\frac{13^3}{15^{15}}\)

7.26 - 2.5 * (a-1,4) 

= 128 - 10*(2,8 - 1,4)

= 128 - 10*1.4

= 114

Thay a=2,8 vào biểu thức 7,26-2,5(a-1,4) ta được:

\(7,26-2,5\cdot1,4=3,76\)

A= 

7.31

4

​

 + 

7.41

6

​

 + 

10.41

9

​

 + 

10.57

7

​

 ⇒ 

5

A

​

 = 

35.31

4

​

 + 

35.41

6

​

 + 

50.41

9

​

 + 

50.57

7

​

\dfrac{A}{5}=\dfrac{1}{31}-\dfrac{1}{35}+\dfrac{1}{35}-\dfrac{1}{41}+\dfrac{1}{41}-\dfrac{1}{50}+\dfrac{1}{50}-\dfrac{1}{57} 

5

A

​

 = 

31

1

​

 − 

35

1

​

 + 

35

1

​

 − 

41

1

​

 + 

41

1

​

 − 

50

1

​

 + 

50

1

​

 − 

57

1

​

\dfrac{A}{5}=\dfrac{1}{31}-\dfrac{1}{57}=\dfrac{26}{31.57}\Rightarrow A=\dfrac{130}{31.57} 

5

A

​

 = 

31

1

​

 − 

57

1

​

 = 

31.57

26

​

 ⇒A= 

31.57

130

​

T viết nhầm

Hơhow

\(\frac{A}{5}=\frac{4}{35.31}+\frac{6}{35.41}+\frac{9}{50.41}+\frac{7}{50.57}=\frac{35-31}{35.31}+\frac{41-35}{35.41}+\frac{50-41}{50.41}+\frac{57-50}{50.57}\)

\(\frac{A}{5}=\frac{1}{31}-\frac{1}{35}+\frac{1}{35}-\frac{1}{41}+\frac{1}{41}-\frac{1}{50}+\frac{1}{50}-\frac{1}{57}=\frac{1}{31}-\frac{1}{57}\)=> A = 5. \(\left(\frac{1}{31}-\frac{1}{57}\right)\)

\(\frac{B}{2}=\frac{7}{38.31}+\frac{5}{38.43}+\frac{3}{43.46}+\frac{11}{46.57}=\frac{38-31}{31.38}+\frac{43-38}{38.43}+\frac{46-43}{43.46}+\frac{57-46}{46.57}\)

\(\frac{B}{2}=\frac{1}{31}-\frac{1}{38}+\frac{1}{38}-\frac{1}{43}+\frac{1}{43}-\frac{1}{46}+\frac{1}{46}-\frac{1}{57}=\frac{1}{31}-\frac{1}{57}\)=> B = 2.\(\left(\frac{1}{31}-\frac{1}{57}\right)\)

A/B = 5/2