Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=
Question 8: Find four integer numbers a,b,c,d such that a + b + c + d = 1 a + c + d = 2 a + b + d = 3 a + b + c = 4 Answer: (a;b;c;d)=(
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
a = 7 ; b = -1 ; c = -2 ; d = -3
Mình mới thi toán tiếng anh về nên biết !Bạn đang thi cấp huyện à !
Đây có phải là vòng 8 TO TA cấp TP đúng ko
a=7;b=-1;c=-2;d=-3
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Question 8:
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Ai trả lời nhanh mình tick cho @@
Dịch đề :
Tìm 4 ẳn số a,b,c,d biết
a+b+c+d = 1
a+c+d =2
a+b+d =3
a+b+c = 4
=>b= (a+b+c+d)-(a+c+d) =1 - 2 =-1
=>c= (a+b+c+d)-(a+b+d) =1 - 3 =-2
=>d= (a+b+c+d)-(a+b+c) =1 - 4 =-3
=>a= (a+b+c+d)-(b+c+d) =1 - [(-1)+(-2)+(-3)]=1-(-6) =7
Vậy (a,b,c,d) = 7,-1,-2,-3
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=(............)
Tìm bốn số nguyên a, b, c, d mà
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Trả lời: (a; b; c; d) = (...................)
Theo đầu bài ta có:
( a + b + c + d ) - ( a + c + d ) = b => b = 1 - 2 = -1
( a + b + c + d ) - ( a + b + d ) = c => c = 1 - 3 = -2
( a + b + c + d ) - ( a + b + c ) = d => d = 1 - 4 = -3
1 - ( b + c + d ) = a => a = 1 - ( -1 + -2 + -3 ) = 7
a + b + c + d = 1
a + c + d = 2
=>(a + b + c + d)-(a + c + d)=b=1-2=-1
a + b + c + d = 1
a + b + d = 3
=> (a + b + c + d)-(a + b + d)=c=1-3=-2
a + b + c + d = 1
a + b + c = 4
=>(a + b + c + d)-(a + b + c)=d=1-4=-3
a + b + c + d = 1
b+c+d=-1+(-2)+(-3)=-6
=>(a + b + c + d )-(b+c+d)=1-(-6)=7=a
Question 1:
The least common multiple of 330; 65; 15 is
Question 2:
Given seven numbers: 25; 17; 39; 43; 239; 1021; 1023.
The composite numbers are
(Write numbers in order from the least to the greatest and use ";")
Question 3:
The common factors of 18 and 27 are
(Write numbers in order from the least to the greatest and use ";")
Question 4:
Given the set of even numbers: {2; 4; 6; …; 100}.The number of elements is
Question 5:
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Question 6:
Find a four-digit natural number that is less than 2015.If the thousands digit is erased,the number will be decreased by 9 times.
Answer:The number is
Question 7:
Calculate: 1×2+2×3+⋯+100×101=
Question 8:
The term of the expression A=1-7+13-19+25-31+⋯ is
Question 9:
Given the expression A= ...
Find the value of n such that 2A+3=
Answer: n=
Question 10:
A natural number has six digits and the units digit is 4.If the units digit is moved to the first row then the number will be increasedby 4 times.The number is
1A gủard B wake C look D prevent
2A to B with C on D at
3A bring B pass C send D take
4 A away B above C for D ảround
Đề bài SGK tiếng anh tập 2 trang 69 bạn nhé
Question 2:
The number of factors of 120 is
Question 5:
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Question 6:
The 215th term of the expression A=1-7+13-19+25-31+⋯ is
Question 7:
A natural number will be increased by 9 times ifthe digit 0 is written between tens digit and units digit.The number is
Question 8:
Calculate: 1×2+2×3+⋯+100×101=
Question 9:
The root of the equation (x+1)+(x+2)+(x+3)+⋯+(x+100)=5750 is x=
Question 10:
The sum of digits of 31000 is A,the sum of digits of A is B,and the sum of digits of B is C.The value of C is
2: Ước của 120 là:
{1;2;3;4;5;6;8;10;12;15;20;24;30;40;60;120}
9: x+ (1+2+3+4+...+100) = 5750
x + 5050= 5750
x = 5750 - 5050 = 700
6. Chữ số thứ 215 là 1285
cau 2 la co 16 uoc
cau 5 a=7 b=-1 c=-2 d=-3
cho a/b = c/d .Chứng minh
a) 3a-c/3b-d = 2a+3c/2b+3d
b) 3a-b/3a+d = 3c-a/3c+d
c) a^2 - b^2/c^2-d^2 = 2ab + b^2/2cd + d^2
Đặt a/b=c/d=k
=>a=bk; c=dk
a: \(\dfrac{3a-c}{3b-d}=\dfrac{3bk-dk}{3b-d}=k\)
\(\dfrac{2a+3c}{2b+3d}=\dfrac{2bk+3dk}{2b+3d}=k\)
Do đó: \(\dfrac{3a-c}{3b-d}=\dfrac{2a+3c}{2b+3d}\)
c: \(\dfrac{a^2-b^2}{c^2-d^2}=\dfrac{b^2k^2-b^2}{d^2k^2-d^2}=\dfrac{b^2}{d^2}\)
\(\dfrac{2ab+b^2}{2cd+d^2}=\dfrac{2\cdot bk\cdot b+b^2}{2\cdot dk\cdot d+d^2}=\dfrac{b^2}{d^2}\)
Do đó: \(\dfrac{a^2-b^2}{c^2-d^2}=\dfrac{2ab+b^2}{2cd+d^2}\)