c: =(x-3-2y)(x-3+2y)

\(=\left(3a-a^2\right)-\left(3b-ab\right)=\left(a-b\right)\left(3-a\right)\)

3a+3b-a²-ab

= 3a - a² + 3b - ab

= a( 3-a ) +b( 3- a)

= ( a+b)(3 - a )

3a + 3b - a² - ab

= 3a - a² + 3b - ab

= a( 3 - a ) + b( 3 - a )

= ( a + b )( 3 - a )

Ta có

a,    x²-x-y²-y

=x²-y²-(x+y)

=(x-y)(x+y) - (x+y)

=(x+y)(x-y-1)

b,   x²-2xy+y²-z²

=(x-y)²-z²

=(x-y-z)(x-y+z)

con bai 32, 33 neu ban tra loi duoc minh h them

nhanh nha

ab(a+b)+bc(b+c)=a²b+ab²+b²c+bc²=(.................không phân tích đc nhé

de tren kia sai ban a

de dung day giup minh di ab(a+b)+bc(b+c)+ca(c+a)+3abc please

\(=6x^2+5x-3xy\)

\(=x\left(6x+5-3y\right)\)

\(x^2-4x+4-y^2\)

\(=\left(x-2\right)^2-y^2\)

\(=\left(x-2-y\right)\left(x-2+y\right)\)

(x - 2)² - y² = (x - 2 - y)(x - 2 + y)

\(x^2-4x-y^2+4=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)

\(x^2-4x+4-y^2\)

\(=\left(x-2\right)^2-y^2\)

\(=\left(x-2-y\right)\left(x-2+y\right)\)

(x - 2)² - y² = (x - 2 - y)(x - 2 + y)

\(=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)