26.17+83.26-40=?
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13.12+26.17 chia hết cho 13.23
\(13.12+26.17\)
\(=13.12+13.34\)
\(=13\left(12+34\right)\)
\(=13.46\)\(\Leftrightarrow\left(13.23.2\right)⋮13.23\)
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Tính B:
B= 1/10.9 + 1/18.13 + 1/26.17 + ..... + 1/802.405
Tính nhanh
17^2+13^2+26.17
76^2-24^2
\(17^2+13^2+26.17\)
\(=13^2+2.13.17+17^2\)
\(=\left(13+17\right)^2\)
\(=20^2\)
\(=400\)
\(76^2-24^2\)
\(=\left(76-24\right)\left(76+24\right)\)
\(=52.100\)
\(=5200\)
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1/10.9+1/18*.13+1/26.17+...+1/802.405
giúp mk với nhé
Tính B:
B=1/10.9 + 1/18.13 + 1/26.17 + ... + 1/802.405
. là dấu nhân nha
\(\frac{1}{10.9}+\frac{1}{18.13}+\frac{1}{26.17}+...+\frac{1}{802.405}\)
Tính
Đặt Biểu thức trên là A
\(A=\frac{1}{2.5.9}+\frac{1}{2.9.13}+\frac{1}{2.13.17}+...+\frac{1}{2.397.401}+\frac{1}{2.401.405}\)
\(A=\frac{1}{2}\left(\frac{1}{5.9}+\frac{1}{9.13}+\frac{1}{13.17}+...+\frac{1}{397.401}+\frac{1}{401.405}\right)\)
\(4A=\frac{1}{2}\left(\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{397.401}+\frac{4}{401.405}\right)\)
\(4A=\frac{1}{2}\left(\frac{9-5}{5.9}+\frac{13-9}{9.13}+\frac{17-13}{13.17}+...+\frac{401-397}{397.401}+\frac{405-401}{401.405}\right)\)
\(4A=\frac{1}{2}\left(\frac{1}{5}-\frac{1}{405}\right)=\frac{1}{2}.\frac{80}{405}=\frac{40}{405}\Rightarrow A=\frac{40}{4.405}=\frac{2}{81}\)
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Tính
a) A dfrac{1}{2.9}+dfrac{1}{9.7}+dfrac{1}{7.19}+...+dfrac{1}{252.509}
b) B dfrac{1}{10.9}+dfrac{1}{18.13}+dfrac{1}{26.17}+...+dfrac{1}{802.405}
c) C dfrac{2}{4.7}-dfrac{3}{5.9}+dfrac{2}{7.10}-dfrac{3}{9.13}+...+dfrac{2}{301.304}-dfrac{3}{401.405}
giúp mk với
Đọc tiếp
Tính
a) A = \(\dfrac{1}{2.9}+\dfrac{1}{9.7}+\dfrac{1}{7.19}+...+\dfrac{1}{252.509}\)
b) B =\(\dfrac{1}{10.9}+\dfrac{1}{18.13}+\dfrac{1}{26.17}+...+\dfrac{1}{802.405}\)
c) C = \(\dfrac{2}{4.7}-\dfrac{3}{5.9}+\dfrac{2}{7.10}-\dfrac{3}{9.13}+...+\dfrac{2}{301.304}-\dfrac{3}{401.405}\)
giúp mk với
b)\(\dfrac{1}{7}B=\dfrac{1}{10.18}+\dfrac{1}{18.26}+\dfrac{1}{26.34}+...+\dfrac{1}{802.810}\)
\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{8}{10.18}+\dfrac{8}{18.26}+\dfrac{8}{26.34}+...+\dfrac{8}{802.810}\right)\)
\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{1}{10}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{34}+...+\dfrac{1}{802}-\dfrac{1}{810}\right)\)
\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{1}{10}-\dfrac{1}{810}\right)\)
\(\dfrac{1}{7}B=\dfrac{1}{8}.\dfrac{8}{81}\)
\(\dfrac{1}{7}B=\dfrac{1.8}{8.81}\)
\(\dfrac{1}{7}B=\dfrac{1}{81}\)
\(B=\dfrac{1}{81}:\dfrac{1}{7}\)
\(B=\dfrac{7}{81}\)
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Tính tổng:\(\frac{1}{10.9}+\frac{1}{18.13}+\frac{1}{26.17}+...+\frac{1}{802.405}\)
Tính
a) A= 1/2.9 + 1/9.7 + 1/7.19 +....+ 1/252.509
b) B= 1/10.9 + 1/18.13 + 1/26.17+.... + 1/802.405
Nhanh nhaaa iuuu
a)Ta có:
A= 1/2.9 + 1/9.7 +...+1/252.509
= 2/5.(5/4.9 + 5/9.14 + 5/14.19 +...+ 1/504.509)
= 2/5.(1/4 - 1/9 + 1/9 - 1/14 + 1/14 - 1/19 +...+ 1/504 - 1/509)
= 2/5.(1/4 - 1/509)
= 101/1018
Vậy A = 101/1018
b)Ta có:
B= 1/10.9 +1/18.13 + 1/26.17 +...+ 1/802.405)
= 1/4.(8/10.18 + 8/18.26 + 8/26.34 +...+ 8/802.810)
= 1/4.(1/10 - 1/18 + 1/18 - 1/26 + 1/26 - 1/34 +...+ 1/802 - 1/810)
= 1/4.(1/10 - 1/810)
= 2/81
Vậy B= 2/81
Tk mình nha!!!
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