Question

Tính

a) A = \(\dfrac{1}{2.9}+\dfrac{1}{9.7}+\dfrac{1}{7.19}+...+\dfrac{1}{252.509}\)

b) B =\(\dfrac{1}{10.9}+\dfrac{1}{18.13}+\dfrac{1}{26.17}+...+\dfrac{1}{802.405}\)

c) C = \(\dfrac{2}{4.7}-\dfrac{3}{5.9}+\dfrac{2}{7.10}-\dfrac{3}{9.13}+...+\dfrac{2}{301.304}-\dfrac{3}{401.405}\)

giúp mk với

Answer 1

b)\(\dfrac{1}{7}B=\dfrac{1}{10.18}+\dfrac{1}{18.26}+\dfrac{1}{26.34}+...+\dfrac{1}{802.810}\)

\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{8}{10.18}+\dfrac{8}{18.26}+\dfrac{8}{26.34}+...+\dfrac{8}{802.810}\right)\)

\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{1}{10}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{34}+...+\dfrac{1}{802}-\dfrac{1}{810}\right)\)

\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{1}{10}-\dfrac{1}{810}\right)\)

\(\dfrac{1}{7}B=\dfrac{1}{8}.\dfrac{8}{81}\)

\(\dfrac{1}{7}B=\dfrac{1.8}{8.81}\)

\(\dfrac{1}{7}B=\dfrac{1}{81}\)

\(B=\dfrac{1}{81}:\dfrac{1}{7}\)

\(B=\dfrac{7}{81}\)