(x-2345)x 5= 2550 giup minh nha
tim x ( x-2345)*5=2550
(x-2345)*5=2550
(x-2345) = 2550 : 5
(x-2345) = 510
x = 510 + 2345
x = 2.855
Vậy......
Tim x
a) 456 + ( x - 357) = 1362
b) ( 2345 - x ) - 183 = 2014
c) ( x - 2005 ) * 2006 = 0
d) 480 + 45 * 4 = ( x + 125 ) : 5 + 260
e) 2005 * ( x - 2006 ) 2005
g) [ ( x + 50 )* 50 - 50 ] : 50 = 50
Cac ban giup minh nhe
Dau * la dau nhan day nhe
x - 7 = -5 tim x giup minh nha minh can gap
X - 7 = 5
X =7+5
X = 12
784 x 8 = ?
157 x 25 = ?
giup minh nha. minh tick 5 ban va ket ban voi 5 ban nha
nhanh len nao. chi 5 ban thoi nha
toan lop 4 nhe cac bn
Giup minh giai bai nay nha
3-x/5-x=x/x+1
Trinh bay voi nha neu dung thi minh tick
\(3-\frac{x}{5}-x=\frac{x}{x-1}\)
\(\Rightarrow\frac{15\left(x-1\right)}{5\left(x-1\right)}-\frac{x\left(x-1\right)}{5\left(x-1\right)}-\frac{5x\left(x-1\right)}{5\left(x-1\right)}=\frac{5x}{5\left(x-1\right)}\)
\(\Rightarrow15\left(x+1\right)-x\left(x-1\right)-5x\left(x-1\right)=5x\)
\(\Rightarrow15x+15-x^2+x-5x^2+5x=5x\)
Bạn tự làm tiếp theo ha
\(\frac{3-x}{5-x}=\frac{x}{x+1}\)
\(\left(3-x\right)\left(x+1\right)=\left(5-x\right)x\)
\(3\left(x+1\right)-x\left(x+1\right)=5x-x^2\)
\(3x+3-x^2-x=5x-x^2\)
\(2x+3-x^2=5x-x^2\)
\(2x+3=5x\)
\(3=5x-2x\)
\(3x=3\)
\(x=1\)
Vậy x = 1
tính giá trị của biểu thức:
x5-2345 x4 +2345 x3-2345 x2+2345 x-2345 tại x+=2344
x^5-(x+1)x^4+(x+1)x^3-(x+1)x^2+(x+1)x-(x+1)
tự làm tiếp đi
1234567890-12345
tính giá trị biểu thức sau
A=x5-2345.x4+2345.x3-2345.x2+2345.x-2345
tại x=2344
giup minh nha
-5:(1-x)=7:(-3)
THANK
Từ -5:(1-x)=7:(-3)
=>\(\dfrac{-5}{1-x}=\dfrac{7}{-3}\)=>7.(1-x)=-5.(-3)
=>7-7x=15
=>7x=7-15=-8
=>x=\(\dfrac{-8}{7}\)
(x+1)+(x+3)+(x+5)+(x+7)=32
Giup minh nha minh dang can gap
Ta có : \(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+\left(x+7\right)=32\)
\(\Leftrightarrow x+x+x+x+1+3+5+7=32\)
\(\Leftrightarrow4x+16=32\Leftrightarrow4x=16\Leftrightarrow x=4.\)
\(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+\left(x+7\right)=32\)
\(\left(x+x+x+x\right)+\left(1+3+5+7\right)=32\)
\(4x+16=32\)
\(4x=16\)
\(\Leftrightarrow x=4\)
(x+1)+(x+3)+(x+5)+(x+7)=32
=> x+1+x+3+x+5+x+7 =32
=> 4x + 16 = 32
=> 4x = 32-16
=> 4x = 16
=> x = 4
Vậy x=4