Làm ơn giúp mk!!

\(\frac{b-2011}{c-2010}:\frac{2011-b}{2010-c}=\frac{b-2011}{c-2010}\cdot\frac{-\left(c-2010\right)}{-\left(b-2011\right)}=1\)

\(\frac{a-2009}{b-2011}=\frac{2010-c}{2009-a}=\frac{-\left(c-2010\right)}{-\left(a-2009\right)}=\frac{c-2010}{a-2009}=1\Rightarrow a-2009=c-2010=b-2011\)

\(\Rightarrow a=c-1=b-2\Rightarrow c=b-1\Rightarrow\frac{b}{c}=\frac{b}{b-1}\)=.=' ko chắc lăm

Thanks!!! Nhưng xin lỗi mặc dù phải là -1. Cảm ơn bạn

ta có : \(a^2+b^2+c^2=ab+bc+ca\Leftrightarrow2a^2+2b^2+2c^2=2ab+2bc+2ca\)

\(\Leftrightarrow a^2-2ab+b^2+b^2-2bc+c^2+c^2-2ca+a^2=0\)

\(\Leftrightarrow\left(a-b\right)^2+\left(b-c\right)^2+\left(c-a\right)^2=0\) \(\Leftrightarrow a=b=c\)

\(\Rightarrow C=\dfrac{a^{2010}+b^{2010}}{c^{2010}}+\dfrac{b^{2010}+c^{2010}}{a^{2010}}+\dfrac{c^{2010}+a^{2010}}{b^{2010}}=3\dfrac{a^{2010}+a^{2010}}{a^{2010}}\)

\(=3\dfrac{2a^{2010}}{a^{2010}}=3.2=6\)

=> (a+b+c)(1/a+b +a/b+c +1/c+a)=2010 . 1/2010 

=>(a+b+c) /(a+b) +(a+b+c)/(b+c) + (a+b+c)/(a+c)=1

=> 1 +c/a+b  + 1 +a/b+c + 1 +b/a+c=1

=>a/b+c +b/a+c +c/a+b =-2

bạn vào link dưới đây nhé

https://olm.vn/hoi-dap/question/826167.html

nhớ tick cho mk nhé!!! :))

\(\frac{a}{b}=\frac{b}{c}=\frac{c}{2010}=\frac{2010}{a}=\frac{a+b+c+2010}{b+c+2010+a}=1\)

=>c=2010.1=2010, a=2010:1=2010, b=c=2010

Mik nghĩ là C

Chúc bạn hok tốt

Chọn D

D