\(\left[43-\left(56-x\right)\right]\times12=384\)

\(43-\left(56-x\right)=384:12\)

\(43-\left(56-x\right)=32\)

\(56-x=43-32\)

\(56-x=11\)

\(x=56-11\)

\(x=45\)

$\left[43-\left(56-x\right)\right]\times 12=384$

$43-\left(56-x\right)=384:12$

$43-\left(56-x\right)=32$

$56-x=43-32$

$56-x=11$

$x=56-11$

$x=45$

a) 15 x y - 2009 = 1201

 \(15.x.y=1201+2009\)

\(15.x.y=3210\)

\(x.y=3210:15\)

\(x.y=214\)

Tới đây bó tay

b)[(z + 32) - 15 ] . 2 = 60

\(\left(z+32\right)-15=60:2\)

\(\left(z+32\right)-15=30\)

\(\left(z+32\right)=30+15\)

\(z+32=45\)

\(z=45-32\)

\(z=13\)

c)[161 + (153-z)] .18 = 3870

\(161+\left(153-z\right)=3870:18\)

\(161+\left(153-z\right)=215\)

\(153-z=215-161\)

\(153-z=54\)

\(-z=54-153\)

\(-z=-99\)

\(z=99\)

d)[43 - (56 - z)] . 12 = 384

\(43-\left(56-z\right)=384:12\)

\(43-\left(56-z\right)=32\)

\(-\left(56-z\right)=32-43\)

\(56+z=-11\)

\(z=-11-56\)

\(z=-11-56\)

\(z=-67\)

Mình có thể sai đâu đó

Mong bạn thông cảm

Chúc bạn học giỏi

\(a,\)\(\left(5x-15\right)\div5=0\)

\(\Rightarrow x-3=0\)

\(\Rightarrow x=3\)

\(b,\)\(84-4\left(2x+1\right)=48\)

\(\Rightarrow84-8x-4=48\)

\(\Rightarrow8x=32\)

\(\Rightarrow x=4\)

\(\left(5\times x-15\right):5=0\)

=> \(5\times x-15=0\)

=> \(5\times x=15\)

=> \(x=3\)

\(84-4\times\left(2\times x+1\right)=48\)

=> \(4\times\left(2\times x+1\right)=84-48\)

=> \(4\times\left(2\times x+1\right)=36\)

=> \(2\times x+1=9\)

=> \(2\times x=9-1\)

=>  \(2\times x=8\)

=> \(x=4\)

[44-(56-x)].12=384

44-(56-x)=32

56-x=12

x=44

[44- (56-x) ] . 12 = 384

<=> (44-56+x) . 12 = 384

<=> (-12 + x) . 12  = 384

<=> 12x - 144       = 384

<=> 12x               = 384 + 144

<=> 12x               = 528

<=>    x                = 528 : 12

<=>    x                = 44

Vậy x = 44

[44-(56-x)]=384:12=32

       56-x  =44-32=12

            x  =56-12=44

a) 3x – 2 = 19

3x = 19 + 2

3x = 21

x = 21:3

x = 7

b) [43 - (56 - x)].12 = 384

43 – (56 – x) = 384:12

43 – (56 – x) = 32

56 – x = 43 – 32

56 – x = 11

x = 56 – 11

x = 45

c) 3^x.2 + 15 = 33

3^x.2 = 33 - 15

3^x.2 = 18

3^x = 18 : 2

3^x = 9

3^x = 33

x = 2.

a) 3x – 2 = 19

3x = 19 + 2

3x = 21

x = 21:3

x = 7

b) [43 - (56 - x)].12 = 384

43 – (56 – x) = 384:12

43 – (56 – x) = 32

56 – x = 43 – 32

56 – x = 11

x = 56 – 11

x = 45

c) 3^x.2 + 15 = 33

3^x.2 = 33 - 15

3^x.2 = 18

3^x = 18 : 2

3^x = 9

3^x = 33

x = 2.

a) 1 < x < 10 3  = > x ∈ {2;3}

b) 2 5 < x ≤ 23 6  = > x ∈ {1;2;3}

\(2x+1+\frac{1}{6}+1+\frac{1}{12}+..+1+\frac{1}{90}=10\)

=> 2x + 8 + \(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}=10\)

=> 2x + \(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}=10-8\)

\(2x+1-\frac{1}{10}=2\)

=> 2x + \(\frac{9}{10}=2\)

=> 2x          = 2 - 9/10

=>2x           = 11/10 

=> x              = 11/10 : 2

x                  =  11/20 

thang Tran ơi,2x+1-1/10 ở đâu vậy

Phải là 2x+1/2-1/10 chứ

mk giải cho nè nhớ tích nha

2x+7/6+13/12+21/20+31/30+43/42+57/56+73/72+91/90=10

2x+(1/6+1)+(1/12+1)+(1/20+1)+(1/30+1)+(1/42+1)+(1/56+1)+(1/72+1)+(1/90+1)=10

2x+(1+1+1+1+1+1+1+1)+(1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90)=10

2x+8+(1/2+3+1/3+4+1/4+5+1/5+6+1/6+7+1/7+8+1/8+9+1/9+10)=10

2x+8+(1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)=10

2x+8+(1/2-1/10)=10

2x+8+2/5=10

2x=10-8-2/5

2x=1,6

x=1,6:2

x=0,8

Mk thấy đề bài hơi dư nên x mk tìm ra là số thập phân còn đổi lại ra phân số là 4/5

\(\frac{-21}{5}\)

x= -127/30 .

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