\(\frac{43}{30}=1+\frac{13}{30}\)

\(=1+\frac{1}{\frac{30}{13}}\)

\(=1+\frac{1}{2+\frac{4}{13}}\)

\(=1+\frac{1}{2+\frac{1}{\frac{13}{4}}}\)

\(=1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}=1+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}\)

Vậy (x; y; z) = (2; 3; 4).

ta có:

\(\frac{43}{30}=1+\frac{13}{30}=1+\frac{1}{\frac{30}{13}}=1+\frac{1}{2+\frac{4}{13}}\)\(=1+\frac{1}{2+\frac{1}{\frac{13}{4}}}=1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}=1+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}\)

=>x=2;y=3;z=4

Vậy (x;y;z)=(2;3;4)

1;2;3 mk ms gisi day

1;2;3 

\(\frac{43}{30}=1+\frac{13}{30}=1+\frac{1}{\frac{30}{13}}=1+\frac{1}{2+\frac{4}{13}}=1+\frac{1}{2+\frac{1}{\frac{13}{4}}}=1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}\)

Do đó ta có: \(1+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}\)

=>x=2;y=3;z=4

x = 1

y = 2

z = 3

An trần giải sai rồi 

\(\frac{43}{30}=1+\frac{13}{30}\)                               

hay \(\frac{1}{x+\frac{1}{y+\frac{1}{z}}}\)= \(\frac{13}{30}\)

=> \(x+\frac{1}{y+\frac{1}{z}}\) = \(\frac{30}{13}=2+\frac{4}{13}\) => x = 2.

=> \(\frac{1}{y+\frac{1}{z}}\) = \(\frac{4}{13}\) =>  \(y+\frac{1}{z}\) = \(\frac{13}{4}\) = \(3+\frac{1}{4}\) => y = 3, z = 4.

Vậy x = 2, y = 3, z = 4.

mk nha =))

Ta có:

\(\frac{43}{30}=1+\frac{13}{30}\)

\(\Rightarrow\frac{1}{x+\frac{1}{y\frac{1}{x}}}=\frac{13}{30}\)

hay \(x+\frac{1}{y+\frac{1}{x}}=\frac{30}{13}\)

mà \(\frac{30}{13}=2+\frac{4}{13}\Rightarrow x=2\)

\(\Rightarrow\frac{1}{y+\frac{1}{z}}=\frac{4}{13}\)

hay \(y+\frac{1}{z}=\frac{13}{4}=3+\frac{1}{4}\Rightarrow y=3\)

\(\Rightarrow z=4\)

Vậy \(x=2;y=3;z=4\)

x=2;y=3;z=4

\(x=2\)

\(y=3\)

\(z=4\)

Đề bé tý: số hữu Tỷ: \(\frac{43}{30}=1+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}\)

\(\frac{43}{30}=1+\frac{13}{30}=1+\frac{1}{2+\frac{4}{13}}=1+\frac{1}{2+\frac{1}{\frac{13}{4}}}=1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}\)

Vậy (x,y,z)=(2,3,4)

x = 2; y = 3; z = 4, chính xác mình thử rồi!

Câu này tớ làm rồi.

kết quả:x=2;y=3;z=4

x=2;y=3;z=4
 

câu này là bằng x=2;y=3;z=4

\(1+\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=\frac{43}{30}\)

\(\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=\frac{43}{30}-1\)

\(\frac{1}{x+\frac{1}{y+\frac{1}{z}}}=\frac{13}{30}\)

Ta có:\(\frac{13}{30}=\frac{1}{\frac{30}{13}}=\frac{1}{2+\frac{4}{13}}=\frac{1}{2+\frac{1}{\frac{13}{4}}}=\frac{1}{2+\frac{1}{3+\frac{1}{4}}}\)

Vậy x=2; y=3; z=4