Tìm tập hợp các số x thuộc Z, biết rằng:
\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)
Tìm tập hợp các số x thuộc z, biết rằng:
\(\frac{-5}{6}\)+\(\frac{8}{3}\)+\(\frac{29}{-6}\)\(\le\)x\(\le\)\(\frac{-1}{2}\)+2+\(\frac{5}{2}\)
Nhớ ghi cách làm giùm mình nhé
Ta có : \(-\frac{5}{6}+\frac{8}{3}+\frac{29}{-6}=-3\) và \(\frac{1}{2}+2+\frac{5}{2}=5\)
Vậy -3 < x < 5. Do x \(\in\) Z nên x \(\in\) {-2; -1; 0; 1; 2; 3; 4}
Tìm x biết
\(\frac{-5}{6}+\frac{8}{3}+\frac{-29}{6}\le X\le-\frac{1}{2}+2+\frac{5}{2}\)
Các bạn cố gắng giúp mk vs nha
Tìm x biết:
\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)
=> -3</ x </ 4
=> x thuộc { -3; -2; -1; 0; 1; 2; 3; 4}
Tìm x
\(\frac{-5}{6}+\frac{8}{3}+\frac{-29}{6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)
Đề bài thiếu : \(x\inℤ\)
Ta có :
\(\frac{-5}{6}+\frac{8}{3}+\frac{-29}{6}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)
\(\Leftrightarrow\)\(\frac{-5+16-29}{6}\le x\le\frac{-1+4+5}{2}\)
\(\Leftrightarrow\)\(\frac{-18}{6}\le x\le\frac{8}{2}\)
\(\Leftrightarrow\)\(-3\le x\le4\)
\(\Rightarrow\)\(x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)
Vậy \(x\in\left\{-3;-2;-1;0;1;2;3;4\right\}\)
Chúc bạn học tốt ~
Tìm x thuộc z ;
a, \(\left(\frac{31}{20}-\frac{26}{45}\right).\frac{-36}{35}< x< \left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right).\frac{8}{13}\)
b,\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}\le x\le\frac{-1}{2}+2+\frac{5}{2}\)
GIÚP MIK VS Ạ, MIK CẦN GẤP LẮM
\(a,\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)< x< \left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}\)
\(taco:\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)=\frac{35}{36}\cdot\frac{-36}{35}=-1\)
\(\left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}=\frac{13}{8}\cdot\frac{8}{13}=1\)
\(=>x=0\)
\(b,\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}< x< \frac{-1}{2}+2+\frac{5}{2}\)(dau <co dau gach ngang o duoi nha)
\(taco:\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}=\frac{-5}{6}+\frac{8}{3}+\frac{-29}{3}=\frac{-5}{6}+\frac{16}{6}+\frac{-58}{6}=\frac{-47}{6}=-7,8\)
\(\frac{-1}{2}+2+\frac{5}{2}=\frac{3}{2}+\frac{5}{2}=4\)
tu do \(=>x=-7,8;...;0;1;2;3;4\)
Tìm x, biết x \(\in\)Z:
\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\)\(\frac{-1}{2}+2+\frac{5}{12}\)
Giải:
Theo bài ra ta có:
\(\frac{-5}{6}+\frac{8}{3}+\frac{29}{-6}\le x\le\frac{-1}{2}+2+\frac{5}{12}\)
\(\Rightarrow-3\le x\le\frac{23}{12}\)
\(\Rightarrow x\varepsilon\left\{-2;-1;0;1\right\}\)
\(\frac{-5}{6}+\frac{16}{6}+-\frac{29}{6}\le x\le\frac{-6}{12}+\frac{24}{12}+\frac{5}{12}\)
=>-3\(\le\) x\(\le\) 23/12
=> x thuộc{-2-1;0;1}
Tìm số nguyên x thuộc z biết:
a) \(\frac{1}{2}-\left(\frac{3}{3}+\frac{4}{4}\right)\le x\le\frac{2}{24}-\left(\frac{1}{8}-\frac{3}{3}\right)\)
b) \(\frac{1}{2}-\frac{1}{6}\le\frac{x-2}{3}\le\frac{1}{3}-\frac{1}{2}-\frac{3}{4}\)
Tìm số nguyên x, biết rằng: \(\frac{3}{7}.15\frac{1}{3}+\frac{3}{7}.5\frac{2}{5}\le x\le\left(3\frac{1}{2}:7-6\frac{1}{2}\right).\left(-2\frac{1}{3}\right)\)
\(\frac{3}{7}\cdot15\cdot\frac{1}{3}+\frac{3}{7}\cdot5\cdot\frac{2}{5}\le x\le\left(3\frac{1}{2}:7-6\frac{1}{2}\right)\cdot\left(-2\frac{1}{3}\right)\)
\(\Leftrightarrow\frac{15}{7}+\frac{6}{7}\le x\le-6\cdot\frac{-5}{3}\)
\(\Leftrightarrow3\le x\le10\)
Mà \(x\in Z\)
\(\Rightarrow x\in\left\{4;5;6;7;8;9\right\}\)
bn Quân sai rồi, hỗn số \(15\frac{1}{3}\)chứ có phải \(15.\frac{1}{3}\)đâu???
\(\frac{3}{7}\cdot15\frac{1}{3}+\frac{3}{7}\cdot5\frac{2}{5}\le x\le\left(3\frac{1}{2}:7-6\frac{1}{2}\right)\cdot\left(-2\frac{1}{3}\right)\)
\(\Rightarrow\frac{3}{7}\left(15\frac{1}{3}+5\frac{2}{5}\right)\le x\le\left(\frac{7}{2}:7-\frac{13}{2}\right)\cdot\left(-\frac{7}{3}\right)\)
\(\Rightarrow\frac{3}{7}\left(\frac{46}{3}+\frac{27}{5}\right)\le x\le\left(\frac{7}{14}-\frac{13}{2}\right)\cdot\left(-\frac{7}{3}\right)\)
\(\Rightarrow\frac{311}{35}\le x\le14\)
\(\Rightarrow8,8...\le x\le14\)
Đến đây là tìm x :))