a) \(5^{x-1}+5^{x-3}=650\)

\(\Rightarrow5^x\left(\frac{1}{5}+\frac{1}{125}\right)=650\)

\(\Rightarrow5^x=650:\frac{26}{125}\)

\(\Rightarrow5^x=3125\)

\(\Rightarrow5^x=5^5\)

\(\Rightarrow x=5\)

suy ra3.(5x-1) - 4.(5x-1) + 6(5x-1) =15

suy ra 5.(5x-1) = 15

suy ra 5x-1=3 

suy ra x=4/5

\(\Leftrightarrow3\left(5x-1\right)-4\left(5x-1\right)+6\left(5x-1\right)=15\)

\(\Leftrightarrow\left(3-4+6\right)\left(5x-1\right)=15\)

\(\Leftrightarrow5\left(5x-1\right)=15\)

\(\Leftrightarrow5x-1=\frac{15}{5}=3\)

\(\Leftrightarrow5x=3+1=4\)

\(\Leftrightarrow x=\frac{4}{5}\)

Vậy \(x=\frac{4}{5}\)

\(\sqrt{9\left(5x-1\right)}-\sqrt{16\left(5x-1\right)}+\sqrt{36\left(5x-1\right)}=15\)

<=> \(3\sqrt{5x-1}-4\sqrt{5x-1}+6\sqrt{5x-1}=15\)

<=> \(5\sqrt{5x-1}=15\)

<=>  \(25\left(5x-1\right)=225\) (bình phương 2 vế)

<=> 5x - 1 = 225 : 25

<=> 5x - 1 = 9

<=> 5x = 9 + 1

<=> 5x = 10

<=> x = 2

bài 1 câu a)

x/5=5/x suy ra x.x=5.5

x^2=25=5^2

x=5

1a) \(\frac{x}{5}\) = \(\frac{5}{x}\)

Vì\(\frac{x}{5}\) = \(\frac{5}{x}\) nên x. x= 5. 5

x\(^2\) = 25

x\(^2\) = 5\(^2\)

-> x\(^2\) = 5\(^2\) hoặc x= -5\(^2\)

=> x= 5 hoặc x= -5

Chúc bn học tốt!

\(a.\)

Ta có : \(\frac{x}{5}=\frac{5}{x}\)

\(\Rightarrow x^2=5^2\)

\(\Rightarrow x^2=25\)

\(\Rightarrow x\in\left\{\pm5\right\}\)

\(\left|2\dfrac{1}{5}-x\right|\)\(+\left|x-\dfrac{1}{5}\right|\)\(+8\dfrac{1}{5}\)\(=1,2\)

\(\Rightarrow\left|2\dfrac{1}{5}-x\right|+\left|x-\dfrac{1}{5}\right|=\dfrac{6}{5}-\dfrac{41}{5}\)

\(\Rightarrow\left|2\dfrac{1}{5}-x\right|+\left|x-\dfrac{1}{5}\right|=\dfrac{-36}{5}\) (vô lý vì \(\left|2\dfrac{1}{5}-x\right|+\left|x-\dfrac{1}{5}\right|\ge0\))

Vậy: Không tìm được giá trị x thoả mãn.

?

x-3/5=1

nên x=8/5

x:1/6=5

hay x=5/6

a.   2x+\(\dfrac{4}{5}\)=0 hoặc 3x-\(\dfrac{1}{2}\)=0

2x=- 4/5 hoặc 3x=1/2

x=-2/5 hoặc x=\(\dfrac{1}{6}\)

b. x-\(\dfrac{2}{5}\)=0 hoặc x+\(\dfrac{4}{7}\)=0

x=2/5 hoặc x=-\(\dfrac{4}{7}\)

d. x(1+5/8-12/16)=1

\(\dfrac{7}{8}\)x=1=> x=8/7