\(x-2\frac{1}{4}=3\frac{1}{2}\)

\(x-\frac{9}{4}=\frac{7}{2}\)

\(x=\frac{7}{2}+\frac{9}{4}\)

\(x=\frac{14}{4}+\frac{9}{4}\)

\(x=\frac{23}{4}\)

\(\frac{2}{x-3}+\frac{x-5}{x-1}=1\)

\(ĐKXĐ:x\ne1;x\ne3\)

\(pt\Leftrightarrow\frac{2x-2}{x^2-4x+3}+\frac{x^2-8x+15}{x^2-4x+3}=1\)

\(\Leftrightarrow\frac{x^2-6x+13}{x^2-4x+3}=1\)

\(\Leftrightarrow x^2-6x+13=x^2-4x+3\)

\(\Leftrightarrow-2x+10=0\Leftrightarrow x=-5\left(t/mđkxđ\right)\)

Vậy pt có 1 nghiệm là -5

2/x - 3 + x - 5/x - 1 = 1

2(x - 1) + (x - 5)(x - 3) = (x - 3)(x - 1)

-6x + 13 + x^2 = x^2 - 4x + 3

-6x + 13 = -4x + 3

13 = -4x + 3 + 6x

13 = 2x + 3

13 - 3 = 3x

10 = 2x

5 = x

=> x = 5

Xem lại dòng 6 đi ๖²⁴ʱℳąɾąкąเ ༉ :))

\(\frac{x}{3}=\frac{2}{3}-\frac{1}{7}\)

\(\Leftrightarrow\frac{x}{3}=\frac{11}{21}\)

\(\Leftrightarrow21x=33\)

\(\Leftrightarrow x=\frac{33}{21}=\frac{11}{7}\)

\(\frac{x}{3}=\frac{11}{21}\)

=>x.21=33

=>x=\(\frac{33}{21}\)

\(\frac{x}{3}=\frac{2}{3}+\left(-\frac{1}{7}\right)\)

\(\frac{x}{3}=\frac{11}{21}\)

\(x.21=33\)

\(x=\frac{11}{7}\)

(1/2-3/4) x - 7/3 = -5/9

-1/4 x  =16/9

x= -64/9

từ đề bài: ta có:  1 -  x/17 - 2/17 + x/15 - 4/15 + x/13 - 6/13   =   x/11 - 8/11 + x/9 - 10/9 + x/7 - 12/7

    Tới đây thì tự giải nha

a) \(\left(\frac{2}{3}x-\frac{4}{9}\right)\left(\frac{1}{2}-\frac{3}{7}:x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}x-\frac{4}{9}=0\\\frac{1}{2}-\frac{3}{7}:x=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{2}{3}\\x=\frac{6}{7}\end{cases}}\)

Vậy \(x\in\left\{\frac{2}{3};\frac{6}{7}\right\}\)

b) 

 \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

        \(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+329}{5}+4=4\)

         \(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

          \(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

Mà \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\ne0\)

\(\Rightarrow x+329=0\)

\(\Rightarrow x=-329\)

Vậy \(x=-329\)

Để M là số nguyên

Thì (x²–5) chia hết cho (x²–2)

==>(x²–2–3) chia hết cho (x²–2)

==>[(x²–2)—3] chia hết cho (x²–2)

Vì (x²–2) chia hết cho (x²–2)

Nên 3 chia hết cho (x²–2)

==> (x²–2)€ Ư(3)

==> (x²–2) €{1;-1;3;-3}

TH1: x²–2=1

x²=1+2

x²=3

==> ko tìm được giá trị của x

TH2: x²–2=-1

x²=-1+2

x²=1

1²=1

==>x=1

TH3: x²–2=3

x²=3+2

x²=5

==> không tìm được giá trị của x

TH4: x²–2=-3

x²=-3+2

x²=-1

(-1)²=1

==> x=-1

Vậy x € {1;—1)

-13/6 nha bạn

TL

-13/6

HT nha bn

\(A=\left(3+\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}-\frac{4}{5}\right)\)

\(A=\left(3-5-6\right)+\left(\frac{1}{4}+\frac{7}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{6}{5}+\frac{4}{5}\right)\)

\(A=-8+2+1+3\)

\(A=-3\)

Ta có: \(\frac{x}{2}=\frac{15}{20}\Leftrightarrow\frac{10x}{20}=\frac{15}{20}\Leftrightarrow10x=15\Leftrightarrow x=\frac{3}{2}\)

Vậy \(x=\frac{3}{2}\)

\(\Rightarrow\)\(\frac{x}{2}\)=\(\frac{3}{4}\)

x.4=2.3

x.4=6

x   =6:4

\(\Rightarrow\)x=\(\frac{6}{4}\)=\(\frac{3}{2}\)

\(\Rightarrow\)x=3

Ta có : \(\frac{15}{20}\)\(=\)\(\frac{15:5}{20:5}\)\(=\)\(\frac{3}{4}\)

Vì  \(\frac{x}{2}\)\(=\)\(\frac{15}{20}\)\(\Rightarrow\)\(\frac{x}{2}\)\(=\)\(\frac{3}{4}\) 

\(\Rightarrow\)x . 4  \(=\)3 . 2 \(\Rightarrow\)x.4  \(=\)6

\(\Rightarrow\)x \(=\)6 : 4 \(\Rightarrow\)x \(=\)\(\frac{6}{4}\)\(=\)\(\frac{3}{2}\)

Vậy   x \(=\)\(\frac{3}{2}\)