[ 324 + x : 2 : 4 ] x 4 = 1304
tính nhanh (324 x 6 + 4 x 324 ) : (162 x 2)
(324 x 6 + 4 x 324 ) : (162 x 2)
= 324 x (6+4) : 324
= 324 x 10 : 324
= (324:324) x 10
= 1 x 10
= 10
\(\text{(324 x 6 + 4 x 324 ) : (162 x 2)}.\)
\(=\left[\left(6+4\right)\times324\right]:324.\\ =\left(10\times324\right):324.\\ =10.\)
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+4}{324}+\frac{x+324}{5}=0\)
Tìm x
a) (5457 + X : 2) :7 =1075
= 5457 + X :2 =1075 x 7
=5457 + X :2 = 7525
= X:2 =7525-5457
=X : 2 = 2068
= X =2068 x 2
= X = 4136
b) (324 +X :2 :4 ) x4 = 1304
= 324+X:2:4 = 1304 :4
= 324+X:2:4 = 326
= X:2:4 =326-324
=X:2:4 = 2
=X:2 =2 x 4
=X:2 =8
=X =8 x 2
= X = 16
1 Tìm x
a) ( 5457 + x: 2 ) : 7 = 1075 b) ( 324 + x : 2 : 4 ) x 4 = 1304
5457 + x : 2 = 1075 x 7 324 + x : 2 : 4 ) = 1304 : 4
5457 + x ; 2 = 7525 324 + x : 2 : 4 = 326
x : 2 = 7525 - 5457 x : 2 : 4 = 326 - 324
x : 2 = 2068 x : 2 : 4 = 2
x = 2068 x 2 x :2 = 2 x 4
x = 4136 x : 2 = 8
x = 8 x 2
x 16
2. Tính giá trị biểu thức sau a) 423 : 4 x 9 - 69 = 1059 x 9 - 69 b) 32 + 15 : 3 x 4 x ( 18 - 9 x 2 ) - 15
= 9531 -69 = 32 + 5 x 4 x 0 - 15
= 9462 = 37 x 4 x 0 -15
= 148 x 0 - 15
= 0 - 15
= -15
Rồi giải tiếp
8^x+3 + 2^x*3 - 3*2^x+4 * 4^x+1 = 324
x+2/327+x+3/326+x+4/325+x+5/324+x+349/5=4
tìm x biết x+2/327+x+3/326+x+4/325+x+5/324=-4
tc tỉ lệ thức,ta có (ra số hơi to thông cảm )
\(\Leftrightarrow\frac{22990993x+80556557}{1870865100}=-\frac{4}{1}\Rightarrow\left(22990993x+80556557\right)1=-1870865100.4\)
\(\frac{\left(22990993x+80556557\right)1}{22990933x}=-\frac{1870865100.4}{22990993x}\)( chia 2 vế cho 2290933x)
\(\Rightarrow\frac{22990933x+80556557}{22990933x}=-\frac{1870865100.4}{22990933x}\)
=>x=-329
tìm x biết x+2/327+x+3/326+x+4/325+x+5/324=-4 vậy x=
324 x 0,25........324 x 4
điền dấu < nhé bn
dễ thôi vì:
0,25<4
thanks
tìm x, biết :
(x+2)/327 + (x+3)/326 + (x+4)/325 + (x+5)/324 = -4
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}=-4\)
<=>\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)=0\)
<=>\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)
<=>\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)
Vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\ne0\Rightarrow x+329=0\Leftrightarrow x=-329\)