\(\frac{5}{8}-\frac{3}{8}.x=\left(-\frac{1}{2}\right)^4+\frac{5}{6}\)

\(\Leftrightarrow\frac{5}{8}-\frac{3}{8}.x=\frac{1}{16}+\frac{5}{6}\)

\(\Leftrightarrow\frac{3}{8}.x=\frac{5}{8}-\left(\frac{1}{16}+\frac{5}{6}\right)\)

\(\Leftrightarrow\frac{3}{8}.x=\frac{5}{8}-\frac{5}{96}\)

\(\Leftrightarrow\frac{3}{8}.x=\frac{55}{96}\)

\(\Leftrightarrow x=\frac{55}{96}:\frac{3}{8}\)

\(\Leftrightarrow x=\frac{55}{36}\)

Vậy : \(x=\frac{55}{36}\)

Chúc bạn học tốt nhé !

Điều kiện:  4 − x x + 2 ≥ 0 ⇔ x ∈ − 2 ; 4

x 2 − 2 x − 8 = 4 4 − x x + 2 ⇔ x 2 − 2 x − 8 = 4 − x 2 − 2 x − 8

Đặt t = − x 2 − 2 x − 8 ,   t ≥ 0

⇔ t 2 = − x 2 − 2 x − 8 ⇔ x 2 − 2 x − 8 = − t 2

1 ⇔ − t 2 = 4 t ⇔ t 2 + 4 t = 0 ⇔ t = 0    ( n ) t = − 4    ( l ) ⇔ − x 2 − 2 x − 8 = 0

⇔ − x 2 − 2 x − 8 = 0 ⇔ x = − 2    ( T M ) x = 4    ( T M )

Vậy phương trình đã cho có hai nghiệm

Đáp án cần chọn là: D

a, \(x + 1/6 = -3/8 \)

\(x = -3/8 - 1/6\)

\(x = -13/24\)

Vậy \(x = -13/24\)

b, \(-3/7 - x = 4/5 - 2/3\)

\(-3/7 - x = 2/15\)

\(x = -3/7 - 2/15\)

\(x = -59/105.\)

Vậy \(x = -59/105\)

x+1/6=-3/8

x=-3/8-1/6

x=-13/24

-3/7-x=4/5+-2/3
-3/7-x=2/15

x=-3/7-2/15

x=-59/105

tham khảo

Nhanh lên nhé các bạn ai nhanh nhất mình sẽ cho 1 k

Giúp mình nha mình đang cần gấp

\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\\ \Rightarrow\left(x+1\right)^2\left(x+1\right)=8\cdot8\\ \left(x+1\right)^3=64\\ \left(x+1\right)^3=4^3\\ \Rightarrow x+1=4\\ x=3\)

\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\)

\(\Leftrightarrow\left(x+1\right)^3=64=4^3\)

\(\Leftrightarrow x+4=1\Rightarrow x=3\)

\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\)

=>\(\left(x+1\right)^2\left(x+1\right)=8.8\)

=>\(\left(x+1\right)^3=64\)

=>\(\left(x+1\right)^3=4^3\)

=>\(x+1=4\)

=>\(x=3\)

62 nhé

tra loi dung thi  h

phai giai doang hoang thi moi tin

`x xx 6/7=5/14`

`=>x=5/14:6/7`

`=>x=5/14xx7/6`

`=>x=35/84`

`=>x=5/12`

Vậy `x=5/12`

__

`x:2/3=4/9`

`=>x=4/9xx2/3`

`=>x=8/27`

Vậy `x=8/27`

__

`x-1/4=3/2`

`=>x=3/2+1/4`

`=>x=6/4+1/4`

`=>x=7/4`

Vậy `x=7/4`

__

`x+4/5=8/9`

`=>x=8/9-4/5`

`=>x=40/45-36/45`

`=>x=4/45`

Vậy `x=4/45`

\(x\cdot\dfrac{6}{7}=\dfrac{5}{14}\)

\(x\)         \(=\dfrac{5}{14}:\dfrac{6}{7}\)

\(x\)           \(=\dfrac{5}{12}\)

\(x:\dfrac{2}{3}=\dfrac{4}{9}\)

\(x\)        \(=\dfrac{4}{9}\cdot\dfrac{2}{3}\)

\(x\)          \(=\dfrac{8}{27}\)

\(x-\dfrac{1}{4}=\dfrac{3}{2}\)

\(x\)          \(=\dfrac{3}{2}+\dfrac{1}{4}\)

\(x\)            \(=\dfrac{7}{4}\)

\(x+\dfrac{4}{5}=\dfrac{8}{9}\)

\(x\)          \(=\dfrac{8}{9}-\dfrac{4}{5}\)

\(x\)            \(=\dfrac{4}{45}\)