=\(\frac{3\left(\frac{1}{1}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{2}{4}+\frac{2}{6}+\frac{2}{8}}{5\left(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\right)}\)

=\(\frac{3}{5}+\frac{2\left(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\right)}{5\left(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}\right)}\)=\(\frac{3}{5}+\frac{2}{5}=\frac{5}{5}=1\)

Bằng 2/5

a) \(=12y^2+3y+28-12y^2=3y+28\)

b) \(=x^2-4x+4-3x^2+8x+3=-2x^2+4x+7\)

\(\frac{2^5.7+2^5}{2^5.5^2-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(5^2-3\right)}=\frac{8}{25-3}=\frac{8}{22}=\frac{4}{11}\)

\(\frac{3^4.5-3^6}{3^4.13+3^4}=\frac{3^4.\left(5-3^2\right)}{3^4.\left(13+1\right)}=\frac{5-9}{14}=\frac{-4}{14}=\frac{-2}{7}\)

\(\frac{-2}{7}=\frac{-22}{77}\)

\(\frac{4}{11}=\frac{28}{77}\)

= 28/77 

=13-[5-(-1)+6]-[3-(-5)]

=13-12-8

=-7

Trả lời:

M = ( x - 3 )³ - ( x + 1 )³ - 12x ( x - 1 )

= x³ - 3.x².3 + 3.x.3² - 3³ - ( x³ + 3.x².1 + 3.x.1² + 1³ ) - 12x² - 12x

= x³ - 9x² + 27x - 27 - x³ - 3x² - 3x - 1 - 12x² - 12x

= - 24x² + 12x - 28

ĐAY NÈ BẠN

nhầm,  đây nhá

M= (x - 3)3 - (x + 1)3 + 12x (x -1)

= x3 -  9x2 + 27x - 27 - x3  - 3x2 - 3x - 1 + 12x2 - 12x

= 12x - 28

`1)(a^[1/4]-b^[1/4])(a^[1/4]+b^[1/4])(a^[1/2]+b^[1/2])`

`=[(a^[1/4])^2-(b^[1/4])^2](a^[1/2]+b^[1/2])`

`=(a^[1/2]-b^[1/2])(a^[1/2]+b^[1/2])`

`=a-b`

`2)(a^[1/3]-b^[2/3])(a^[2/3]+a^[1/3]b^[2/3]+b^[4/3])`

`=(a^[1/3]-b^[2/3])[(a^[1/3])^2+a^[1/3]b^[2/3]+(b^[2/3])^2]`

`=(a^[1/3])^3-(b^[2/3])^3`

`=a-b^2`