\(b)\)\(x\div\left(-5\right)+10=-60\)

\(x\div\left(-5\right)=-60-10\)

\(x\div\left(-5\right)=-70\)

\(x=-70\times\left(-5\right)\)

\(x=350\)

\(a)\)\(3\div x-10=-12\)

\(3\div x=-12+10\)

\(3\div x=-2\)

\(x=3\div-2\)

\(x=-\frac{3}{2}=-1,5\)

\(\left(2-x\right)\div\left(-4\right)-5=-11\)

\(\left(2-x\right)\div\left(-9\right)=-11\)

\(\left(2-x\right)=-11\times\left(-9\right)\)

\(2-x=99\)

\(x=2-99\)

\(x=-97\)

\(\text{a)}3:x-10=-12\)

\(3:x\)         \(=\left(-12\right)+10=-2\)

    \(x\)          \(=3:\left(-2\right)=-1,5\)

\(\text{b)}\left(2-x\right):\left(-4\right)-5=11\)

    \(\left(2-x\right):\left(-4\right)\)      \(=11+5=16\)

    \(\left(2-x\right)\)                     \(=16x\left(-4\right)=-64\)

                \(x\)                        \(=2-\left(-64\right)=66\)

\(\text{c)}x:\left(-5\right)+10=-60\)

    \(x:\left(-5\right)\)          \(=\left(-60\right)-10=-70\)

    \(x\)                        \(=\left(-70\right)x\left(-5\right)=350\)

\(\left(3-2x\right)^2=16\)

\(\left(3-2x\right)^2=\pm\left(4\right)^2\)

\(\text{Vậy 3-2x=4 hoặc }\)                             \(3-2x=-4\)

             \(2x=3-4=-1\)                    \(2x=3-\left(-4\right)=7\)

                \(x=\left(-1\right):2=-0,5\)             \(x=7:2=3,5\)

\(\text{Câu b với c mik lỡ làm ngược lại rồi bạn thông cảm}\)

\(\text{Hok tốt!}\)

\(\text{@Kaito Kid}\)

\(a,\Leftrightarrow\left[{}\begin{matrix}x-8=0\\x^3+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x^3=-8\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\\ b,\Leftrightarrow4x-3-x-5=30-3x\\ \Leftrightarrow4x-x+3x=30+5+3\\ \Leftrightarrow6x=38\\ \Leftrightarrow x=\dfrac{19}{3}\)

9/11 x 10/13 + 9/13 x 12/11 - 7/11

= 9/13 x 10/11 + 9/13 x 12/11 - 7/11

= 9/13 x (10/11 + 12/11) - 7/11

= 9/13 x 22/11 - 7/11

= 9/13 x 2 - 7/11

= 18/13 - 7/11

= 198/143 - 91/143

= 107/143

\(\dfrac{9}{11}\times\dfrac{10}{13}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\dfrac{10}{11}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\left(\dfrac{10}{11}+\dfrac{12}{11}\right)-\dfrac{7}{11}=\dfrac{9}{13}\times2-\dfrac{7}{11}=\dfrac{18}{13}-\dfrac{7}{11}=\dfrac{107}{143}\)

(1+x)+(2+x)+(3+x)+(4+x)+(5+x)=10*5

(1+2+3+4+5)+ (x+x+x+x+x)=50

15+5*x=50

5*x=50-15

5*x=35

x=35:5=7

(1+x)+(2+x)+(3+x)+(4+x)+(5+x)=10*5

1+x+2+x+3+x+4+x+5+x=50

(1+2+3+4+5)+(x+x+x+x+x)=50

15+5x=50

5x=50-15

5x=35

x=35:5

x=7

câu a+b dùng quy tắc chuyển vế

c, 3.(1/2-x)-5.(x-1/10)=-7/4

=>(3.1/2-3x)-(5x-5.1/10)=-7/4

=>3/2-3x-5x+1/2=-7/4

=>(3/2+1/2)-(3x+5x)=-7/4

=> 2-8x=-7/4

=>8x=15/4

=>x=15/4:8

=>x=15/32

a) 2.(1/4 - 3x) = 1/5 - 4x
=> 1/2 - 6x = 1/5 -4x
=> -6x + 4x = 1/5 - 1/2
=> -2x         = -3/10 = 3/20
b) 4.(1/3 - x) + 1/2 = 5/6 +x 
=> 4/3 - 4x + 1/2 = 5/6 +x
=> -4x - x = 5/6 - 4/3 - 1/2
=> -5x = -1
=> x= 1/5
c) 3. (1/2 - x) -5. ( x - 1/10) = -7/4
=> 3/2 - 3x - 5x + 1/2 = -7/4
=> -3x - 5x = -7/4 - 3/2 - 1/2 
=> -8x = -15/4
=> x = 15/32

mình chịu

Bài 1:

a) \(x.\dfrac{3}{4}=\dfrac{9}{14}\)

\(\Rightarrow x=\dfrac{9}{14}:\dfrac{3}{4}\)

\(\Rightarrow x=\dfrac{6}{7}\)

b) \(x:\dfrac{5}{9}=\dfrac{3}{10}\)

\(\Rightarrow x=\dfrac{3}{10}.\dfrac{5}{9}\)

\(\Rightarrow x=\dfrac{1}{6}\)

help me

Bài 2:

a) \(\dfrac{3}{10}+\dfrac{2}{5}:\dfrac{4}{15}=\dfrac{3}{10}+\dfrac{3}{2}=\dfrac{9}{5}\)

b) \(\dfrac{4}{7}.3+\dfrac{2}{3}.2=\dfrac{12}{7}+\dfrac{4}{3}=\dfrac{64}{21}\)