Bài 1

a) \(x=x^5\)

\(x^5-x=0\)

\(x\left(x^4-1\right)=0\)

\(x=0\) hoặc \(x^4-1=0\)

* \(x^4-1=0\)

\(x^4=1\)

\(x=1\)

Vậy x = 0; x = 1

b) \(x^4=x^2\)

\(x^4-x^2=0\)

\(x^2\left(x^2-1\right)=0\)

\(x^2=0\) hoặc \(x^2-1=0\)

*) \(x^2=0\)

\(x=0\)

*) \(x^2-1=0\)

\(x^2=1\)

\(x=1\)

Vậy \(x=0\); \(x=1\)

c) \(\left(x-1\right)^3=x-1\)

\(\left(x-1\right)^3-\left(x-1\right)=0\)

\(\left(x-1\right)\left[\left(x-1\right)^2-1\right]=0\)

\(x-1=0\) hoặc \(\left(x-1\right)^2-1=0\)

*) \(x-1=0\)

\(x=1\)

*) \(\left(x-1\right)^2-1=0\)

\(\left(x-1\right)^2=1\)

\(x-1=1\) hoặc \(x-1=-1\)

**) \(x-1=1\)

\(x=2\)

**) \(x-1=-1\)

\(x=0\)

Vậy \(x=0\); \(x=1\); \(x=2\)

a: \(\Leftrightarrow73-x=67\)

hay x=6

\(a,\Rightarrow x=30-18=12\\ b,\Rightarrow x+6=45:5=9\\ \Rightarrow x=9-6=3\\ c,\Rightarrow38-3x=4^2=16\\ \Rightarrow3x=38-16=22\\ \Rightarrow x=\dfrac{22}{3}\)

  Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

a)     4^x  = 8^12

    (2^2)^x = (2^3)^12

     2^2x   = 2^36

=> 2x = 36

=>   x = 36 : 2 = 18

a) 4^x=8^12

4^x=(2^3)^12

4^x=2^36

4^x=4^18

=> x=18 hoặc -18

Các phần khác tương tự nha

a) 4^x=8¹²

(2²)^x=(2³)¹²

2^2x=2³⁶

2x=36

  x=36:2

  x=18

vậy x=18

b) 3^2x+2=9¹⁰

3^2x+2=(3²)¹⁰

3^2x+2=3²⁰

2x+2=20

2x=20-2

2x=18

  x=18:2

  x=9

vậy x=9

c)2^x=4³:2⁵

2^x=(2²)³:2⁵

2^x=2⁶:2⁵

2^x=2^6-5

2^x=2¹

x=1

vậy x=1

   2^x + 2^x + 2 = 8² - 6² + 2² . 3

= 2^x + 2^x + 2 = 64 - 36 + 4 . 3

= 2^x + 2^x + 2 = 64 - 36 + 12

= 2^x + 2^x + 2 = 28 + 12

= 2^x + 2^x + 2 = 40

= 2^x + 2^x = 40 - 2

= 2^x + 2^x = 38

= 2^x . 2 = 38

= 2^x = 38 : 2

= 2^x = 19

=> x không có giá trị

\(\dfrac{1}{6}+x=\dfrac{5}{12}\)
\(=>x=\dfrac{5}{12}-\dfrac{2}{12}=\dfrac{1}{4}\)
\(\dfrac{3}{4}+\dfrac{1}{4}x=-\dfrac{1}{2}\)
\(=>\dfrac{1}{4}x=-\dfrac{5}{4}\)
\(=>x=-\dfrac{5}{4}.4=-5\)
\(7^{2x}+7^{2x+3}=344\)
\(< =>49^x+49^x.343=344\)
\(=>x=?\)

8^x=2¹¹¹

=>(2³)^x=2¹¹¹

=>2^3x=2¹¹¹

=>3x=111

=>x=37

2^x+5.2^x=48

=>2^x.6=48

=>2^x=8=2³

=>x=3

Câu cuối ko làm đc nha

a. 8^x = 2¹¹¹

    2^3x = 2¹¹¹

    3x  = 111

      x  = 111:3

     x  = 37

b. 2^x + 5.2^x = 48

    2^x(5 + 1 )= 48

    2^x.6        = 48

    2^x           = 48 : 6

    2^x           = 8

    2^x            = 2³

      x            = 3

c. 2^x + 3.2^x-1 = 40

   2^x(3:2 +1 )     = 40

   2^x . \(\frac{5}{2}\)      = 40

    2^x                  = 40 : \(\frac{5}{2}\)

    2^x                  = 16

    2^x                   = 2⁴

      x                   = 4

+) \(8^x=2^{111}\)

\(\Rightarrow\left(2^3\right)^x=2^{111}\)

\(\Rightarrow2^{3x}=2^{111}\)

\(\Rightarrow3x=111\)

\(\Rightarrow x=111:3\)

\(\Rightarrow x=37\)

Vậy x = 37

+) \(2^x+5\times2^x=48\)

\(\Rightarrow2^x\times\left(1+5\right)=48\)

\(\Rightarrow2^x\times6=48\)

\(\Rightarrow2^x=48:6\)

\(\Rightarrow2^x=8\)

\(\Rightarrow2^x=2^3\)

\(\Rightarrow x=3\)

Vậy x = 3

+) \(2^x+3\times2^{x-1}=40\)

\(\Rightarrow2^x+3\times2^x:2=40\)

\(\Rightarrow2^x+3\times2^x\times\frac{1}{2}=40\)

\(\Rightarrow2^x+2^x\times\left(3\times\frac{1}{2}\right)=40\)

\(\Rightarrow2^x+2^x\times\frac{3}{2}=40\)

\(\Rightarrow2^x\times\left(1+\frac{3}{2}\right)=40\)

\(\Rightarrow2^x\times\frac{5}{2}=40\)

\(\Rightarrow2^x=40:\frac{5}{2}\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

Vậy x = 4

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