Bài 1:

a. $(-20)+x=-30$

$x-20=-30$

$x=-30+20=-(30-20)=-10$

b.

$(-10)-x=-20$

$x=(-10)-(-20)=-10+20=20-10=10$

c. Đề sai. Bạn xem lại.

d.

$x+(-3)=-7$

$x=-7-(-3)=-7+3=-(7-3)=-4$

e.

$x-(-5)=-9$

$x=(-9)+(-5)=-14$

f.

$x(-11)=12$

$x=\frac{12}{-11}=\frac{-12}{11}$

h.

$2x-10=20$

$2x=20+10=30$

$x=30:2=15$

l.

$4x-8=-8$
$4x=-8+8=0$

$x=0:4=0$

k.

$-12-(-2)x=-8$

$(-2)x=-12-(-8)=-12+8=-(12-8)=-4$

$x=(-4):(-2)=2$

Bài 2:

a. $-20-(10-x)=-3$

$10-x=-20-(-3)=-20+3=-(20-3)=-17$

$x=10-(-17)=10+17=27$

b.

$14+(14-x)=-2$
$14-x=-2-14=-16$

$x=14-(-16)=14+16=30$

c.

$-15-(x-3)=-7$

$x-3=-15-(-7)=-15+7=-8$

x=-8+3=-5$

d.

$(x+4)+(-20)=-8$

$x+4=-8-(-20)=-8+20=12$
$x=12-4=8$

e.

$-2x-2=-4$

$-2x=-4+2=-2$

$x=(-2):(-2)=1$

f.

$-2x+4=-4$

$-2x=-4-4=-8$

$x=(-8):(-2)=4$

l.

$-12-(-2)x=-2-4=-6$

$(-2)x=-12-(-6)=-12+6=-6$

$x=(-6):(-2)=3$

2: x=3

3: x=18

1) \(x=51\)

2) \(x=3\)

3) \(x=18\)

4) \(x=2\)

5) \(x=7\)

a) 3x - 10 = 2x + 13

<=> 3x - 2x = 13+10

<=> x = 23

      Vậy x = 23

b) x + 12 = -5 - x

<=> x + x = -5 - 12

<=> 2x = -17

<=> x = -17 : 2

<=> x = -8,5

      Vậy x = -8,5

c) x + 5 = 10 - x

<=> x + x = 10 - 5

<=> 2x = 5

<=> x = 5 : 2

<=> x = 2,5

      Vậy x = 2,5

d) 6x + 2 ^ 3 = 2x - 12

<=> 6x + 8 = 2x - 12

<=> 6x - 2x = -12 - 8

<=> 4x = -20

<=> x = -20 : 4

<=> x = -5

     Vậy x = -5

e) 12 - x = x + 1

<=> -x - x = 1 - 12

<=> -2x = -11

<=> x = -11 : (-2)

<=> x = 5,5

     Vậy x= 5,5

f) 14 - 4x = 3x + 20

<=> -4x - 3x = 20 - 14

<=> -7x = 6

<=> x = 6 : (-7)

<=> x = \(-\frac{6}{7}\)

a, ta có : X*20=5*(-12)

             20X=-60

             X=-60/20

             X=-3

a, \(\frac{x}{5}=\frac{-12}{20}\)

\(x=\frac{5.\left(-20\right)}{20}\)

\(x=-5\)

b, 3x - 35 = -45 - 2x

3x + 2x = -45 + 35

5x = -10

x = (-10) : 5

x = -2

c, \(\frac{-1}{6}-x=\frac{5}{12}+\frac{-2}{3}\)

\(\frac{-1}{6}-x=\frac{-1}{4}\)

\(-x=\frac{-1}{6}-\frac{-1}{4}\)

\(-x=\frac{1}{12}\)

\(x=\frac{-1}{12}\)

Mọi người giúp em với ạ

Bài tập này em chưa hiểu nên hỏi

Mong mọi người giúp:((

1) x/5 = -12/10

\(x.10=5.\left(-12\right)\)

\(10x=\left(-60\right)\)

\(x=-6\)

2) (x + 1)/2 = x/3

\(3\left(x+1\right)=2x\)

\(3x+3=2x\)

\(3x-2x=3\)

\(x=3\)

3) (1 - 2x)/9 = 1/ (1- 2x)

\(\left(1-2x\right).\left(1-2x\right)=9.1\)

\(\left(1-2x\right)^2=\left(\pm3\right)^2\)

\(\Rightarrow\orbr{\begin{cases}1-2x=3\\1-2x=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=-2\\2x=4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=1\\x=2\end{cases}}}\)

4) 4/5 = 12/x = y/20 = 8.(y -x)/z

\(\frac{4}{5}=\frac{12}{x}\Leftrightarrow4x=60\Leftrightarrow x=15\)

\(\frac{4}{5}=\frac{y}{20}\Leftrightarrow y5=80\Leftrightarrow y=16\)

\(\frac{4}{5}=\frac{8.\left(y-x\right)}{z}\Leftrightarrow\frac{4}{5}=\frac{8}{z}\Leftrightarrow4z=40\Leftrightarrow z=10\)

Vậy \(x=15;y=16;z=10\)

chúc bạn học tốt

a) x - 8 - (12 - 2x) = -20

=> x - 8 - 12 + 2x = -20

=> (x + 2x) + (-8 - 12) = -20

=> 3x - 20 = -20

=> 3x = 0 => x = 0

b) -27 + (x + 8) - ( +11) = 2

=> -27 + x + 8 - 11 = 2

=> -27 + x = 2 + 11 - 8

=> -27 + x = 5

=> x = 5 - (-27) = 32

c) -2x - 16 = -2 - (3x + 9)

=> -2x - 16 = -2 - 3x - 9

=> -2x - 16 + 2 + 3x + 9 = 0

=> (-2x + 3x) + (-16 + 2 + 9) = 0

=> x - 5 = 0

=> x = 5

\(a,x-8-\left(12-2x\right)=-20\)

\(x-8-12+2x=-20\)

\(x+2x-8-12=-20\)

\(3x-20=-20\)

\(3x=-20+20\)

\(3x=0\)

\(x=0\)

\(b,-27+\left(x+8\right)-\left(+11\right)=2\)

\(-27+x+8-11=2\)

\(x-27+8-11=2\)

\(x-30=2\)

\(x=2+30\)

\(x=32\)

\(c,-2x-16=2-\left(3x+9\right)\)

\(-2x-16=2-3x-9\)

\(-2x+3x=2-9+16\)

\(x=9\)

Học tốt

a) x - 8 - ( 12 - 2x ) = -20

x - 8 - 12 + 2x = -20

x + 2x = -20 + 8 + 12

3x = 0

x = 0 \(\left(x\in Z,tm\right)\)

Vậy x=0

b) -27 + ( x + 8 ) - ( +11 ) = 2

-27 + x + 8 - 11 = 2

x = 2 + 27 - 8 + 11

x = 32 \(\left(x\in Z,tm\right)\) 

Vậy x = 32

c) -2x - 16 = 2 - ( 3x + 9 )

-2x - 16 = 2 - 3x - 9

-2x + 3x = 2 - 9 +16

x = 9 \(\left(x\in Z,tm\right)\)

Vậy x = 9

a: =>x/27+1=-2/3

=>x/27=-5/3

=>x=-45

b: \(\Leftrightarrow x-4=\dfrac{2}{5}:\dfrac{20}{21}=\dfrac{2}{5}\cdot\dfrac{21}{20}=\dfrac{42}{100}=\dfrac{21}{50}\)

=>x=221/50

c: \(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)

=>x=1/15-2/3=1/15-10/15=-9/15=-3/5

d: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{15}{14}\cdot\dfrac{21}{20}\)

=>\(x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{3}{2}\cdot\dfrac{3}{4}=\dfrac{1}{5}-\dfrac{9}{8}=\dfrac{-37}{40}\)

=>x=-37/24

e: =>-3/7x=84/45

=>x=-196/45

f: =>11/10x=-2/3

=>x=-20/33

mình cx có câu hỏi như bạn luôn đau lòng hức hức