10/

\(CaCO_3\underrightarrow{t^o}CaO+CO_2\)

__________(A₁)____(B₁)

\(CaO+CO_2\rightarrow CaCO_3\)

\(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)

________________(A₂)

\(CO_2+NaOH\rightarrow NaHCO_3\)

__________________(B₂)

\(Ca\left(OH\right)_2+2NaHCO_3\rightarrow CaCO_3+Na_2CO_3+2H_2O\)

\(Ca\left(OH\right)_2+Mg\left(NO_3\right)_2\rightarrow Ca\left(NO_3\right)_2+Mg\left(OH\right)_{2\downarrow}\)

_________________________(A₃)

\(NaHCO_3+NaOH\rightarrow Na_2CO_3+H_2O\)

______________________(B₃)

\(Ca\left(NO_3\right)_2+Na_2CO_3\rightarrow CaCO_3+2NaNO_3\)

Bạn tham khảo nhé!

11/

a, (1) \(Fe_2\left(SO_4\right)_3+3BaCl_2\rightarrow2FeCl_3+3BaSO_{4\downarrow}\)

(2) \(FeCl_3+3NaOH\rightarrow3NaCl+Fe\left(OH\right)_{3\downarrow}\)

(3) \(Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+3H_2O\)

(4) \(Fe_2\left(SO_4\right)_3+6NaOH\rightarrow3Na_2SO_4+2Fe\left(OH\right)_{3\downarrow}\)

(5) \(2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)

(6) \(Fe_2O_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+3H_2O\)

b, (1) \(2Cu+O_2\underrightarrow{t^o}2CuO\)

(2) \(CuO+H_2\underrightarrow{t^o}Cu+H_2O\)

(3) \(CuO+2HCl\rightarrow CuCl_2+H_2O\)

(4) \(CuCl_2+2NaOH\rightarrow Cu\left(OH\right)_{2\downarrow}+2NaCl\)

(5) \(Cu\left(OH\right)_2+2HCl\rightarrow CuCl_2+2H_2O\)

(6) \(Cu\left(OH\right)_2\underrightarrow{t^o}CuO+H_2O\)

Bạn tham khảo nhé!

11b)

(1) \(Cu+\dfrac{1}{2}O_2\xrightarrow[]{t^o}CuO\)

(2) \(CuO+H_2\xrightarrow[]{t^o}Cu+H_2O\)

(3) \(CuO+2HCl\rightarrow CuCl_2+H_2O\)

(4) \(CuCl_2+2KOH\rightarrow Cu\left(OH\right)_2\downarrow+2KCl\)

(5) \(Cu\left(OH\right)_2+2HCl\rightarrow CuCl_2+2H_2O\)

(6) \(Cu\left(OH\right)_2\xrightarrow[]{t^o}CuO+H_2O\)

1 If you don't finish your homework, you can't go out with your friend

2 They are not sure how to operate the new system

3 I spent 4 hours reading the first chapter of the book

4 Tennis is not as dangerous as snowboarding

X

1 to go to school by bike when they were young

2 teaching her children to play the piano 4 years ago

3 I could cook as well as my mom

4 using Perfume Pagoda as the theme of the presentation

Tổng tiền mua cây bút và hộp bút:

4000 x 5 + 50000 = 70000(đồng)

Số tiền còn lại:

250000 - 70000= 180000(đồng)

Nam có thể mua được nhiều nhất số quyển vở là:

180000: 8000 = 22 (quyển) (Thừa 4000 đồng)

Bài em cần đâu em?

Sửa đề là : 4.6 (g) 

\(n_{H_2}=\dfrac{2.24}{22.4}=0.1\left(mol\right)\)

\(A+H_2O\rightarrow AOH+\dfrac{1}{2}H_2\)

\(0.2...............................0.1\)

\(M_A=\dfrac{4.6}{0.2}=23\left(\dfrac{g}{mol}\right)\)

\(A:Na\)

Đề này C1 em sửa thành 4,6 gam kim loại như bạn dưới, C2 em sửa thành 22,4 lít H₂