= \(\frac{5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+2\frac{1}{8}\)

=> \(\frac{5}{8}.1+2\frac{1}{8}\)=> \(\frac{5}{8}+\frac{17}{8}=\frac{22}{8}=\frac{11}{4}\)

#Hk_tốt

#kEn'Z

\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}=\frac{-5}{8}.1+\frac{17}{8}=\frac{-5}{8}+\frac{17}{8}=\frac{12}{8}=\frac{3}{4}\)

\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)

\(=\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+\frac{17}{8}\)

\(=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)

\(=\frac{-5}{8}.1+\frac{17}{8}\)

\(=\frac{-5}{8}+\frac{17}{8}\)

\(=\frac{12}{8}=\frac{3}{2}\)

Có lẽ bạn viết đề sai.

Câu hỏi của Vũ Mai Linh - Toán lớp 7 - Học toán với OnlineMath

mik viết đề đúng mà sai chỗ nào vayh

\(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}x\frac{4}{5}=15\frac{33}{17}\)

a) \(\frac{5}{6}\)x - \(\frac{3}{8}\)x - 10 = 12

=> \(\left(\frac{5}{6}-\frac{3}{8}\right)\)x = 12 + 10

=> \(\frac{11}{24}\)x = 22

=> x = 22 : \(\frac{11}{24}\)

=> x = 48

Vậy x = 48.

b) (\(\left|x\right|\) - \(\frac{1}{8}\)) . \(\left(-\frac{1}{8}\right)^5\) = \(\left(-\frac{1}{8}\right)^7\)

=> \(\left|x\right|\) - \(\frac{1}{8}\) = \(\left(-\frac{1}{8}\right)^7\) : \(\left(-\frac{1}{8}\right)^5\)

=> \(\left|x\right|\) - \(\frac{1}{8}\) = \(\left(-\frac{1}{8}\right)^{7-5}\)

=> \(\left|x\right|\) - \(\frac{1}{8}\) = \(\frac{1}{64}\)

=> \(\left|x\right|\) = \(\frac{1}{64}\) + \(\frac{1}{8}\)

=> \(\left|x\right|\) = \(\frac{9}{64}\)

=> x = \(\frac{9}{64}\) hoặc x = \(\frac{-9}{64}\)

Vậy x = \(\frac{9}{64}\) hoặc x = \(\frac{-9}{64}\)

\(\frac{1}{3}x-1.2x-\frac{2}{23}.\left(\frac{-11}{12}+\frac{5}{6}-\frac{7}{8}\right)-\frac{1}{8}=-11\frac{2}{3}+12\frac{7}{8}\)

\(\Leftrightarrow\frac{1}{3}x-\frac{6}{5}x-\frac{2}{23}.\frac{-23}{24}-\frac{1}{8}=\frac{-35}{3}+\frac{103}{8}\)

\(\Leftrightarrow\frac{-13}{15}x+\frac{1}{12}-\frac{1}{8}=\frac{29}{24}\)

\(\Leftrightarrow\frac{-13}{15}x-\frac{1}{24}=\frac{29}{24}\)

\(\Leftrightarrow\frac{-13}{15}x=\frac{5}{4}\)

\(\Leftrightarrow x=\frac{-75}{52}\)

Vậy \(x=\frac{-75}{52}\)

1/3x-1/2x-2/23.(-11/12+5/6-7/8)-1/8=-31/3+103/8

1/3x-1,2x-2/23.(-11/12+5/6-7/8)-1/8=61/24

1/3x-1,2x-2/23.-23/24-1/8=61/24

1/3x-1,2x-1/12-1/8=61/24

1/3x-1,2x+1/24=61/24

x.(1/3-1,2)+1/24=61/24

x.-13/15+1/24=61/24

x.-33/40=61/24

x=61/24:-33/40

x=61/24×-40/33

x=-305/99

vậy x=-305/99

hai tk là 1 :vvv

ai quen thì kb cả 2 tk nhé

a) \(\frac{4x-7}{12}-x=\frac{3x}{8}\)

\(\Rightarrow\frac{4x-7-12x}{12}=\frac{3x}{8}\)

\(\Rightarrow\frac{-7-8x}{12}=\frac{3x}{8}\)

\(\Rightarrow-56-64x=36x\)

\(\Leftrightarrow100x=-56\Leftrightarrow x=\frac{-14}{25}\)

\(\frac{3x-7}{5}=\frac{2x-1}{3}\)

\(\Leftrightarrow9x-21=10x-5\)

\(\Leftrightarrow-x=16\Leftrightarrow x=-16\)

\(\frac{4x-7}{12}-x=\frac{3x}{8}\)

\(\Leftrightarrow\frac{4x-7-12x}{12}=\frac{3x}{8}\)

\(\Leftrightarrow\frac{-7-8x}{12}=\frac{3x}{8}\)

\(\Leftrightarrow-56-64x=36x\)

\(\Leftrightarrow-56=100x\Leftrightarrow x=\frac{-14}{25}\)

\(\frac{x-2009}{1234}+\frac{x-2009}{5678}-\frac{x-2009}{197}=0\)

\(\Leftrightarrow\left(x-2019\right)\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)=0\)

Vì \(\left(\frac{1}{1234}+\frac{1}{5678}-\frac{1}{197}\right)\ne0\)nên x - 2019 = 0

Vậy x = 2019

\(\frac{5x-8}{3}=\frac{1-3x}{2}\)

\(\Leftrightarrow10x-16=3-9x\)

\(\Leftrightarrow19x=19\Leftrightarrow x=1\)

\(\frac{x-5}{6}-\frac{x-9}{4}=\frac{5x-3}{8}+2\)

\(\Rightarrow\frac{4x-20-6x+54}{24}=\frac{5x-3+16}{8}\)

\(\Rightarrow\frac{-2x+34}{24}=\frac{5x+13}{8}\)

\(\Rightarrow-16x-272=120x+312\)

\(\Leftrightarrow-136x=584\Leftrightarrow x=\frac{-73}{17}\)

a) \(\frac{x-1}{8}=\frac{5}{4}\)

\(\frac{x-1}{8}=\frac{10}{8}\)

\(\Leftrightarrow x-1=10\)

\(x=10+1\)

\(x=11\)

vậy x =11

b)\(\frac{6}{2x-1}=\frac{12}{-8}\)

\(\frac{6}{2x-1}=\frac{6}{-4}\)

\(\Leftrightarrow2x-1=-4\)

\(2x=-4+1\)

\(2x=-3\)

\(x=\frac{-3}{2}\)

vậy \(x=\frac{-3}{2}\)

c) \(\frac{2x-5}{-12}=\frac{-6}{9}\)

\(\frac{2x-5}{-12}=\frac{-2}{3}\)

\(\frac{2x-5}{-12}=\frac{8}{-12}\)

\(\Leftrightarrow2x-5=8\)

\(2x=8+5\)

\(2x=13\)

\(x=\frac{13}{2}\)

vậy \(x=\frac{13}{2}\)

a) x−18 =54 

x−18 =108 

⇔x−1=10

x=10+1

x=11

vậy x =11

b) 62x−1 =12−8 

62x−1 =6−4 

⇔2x−1=−4

2x=−4+1

2x=−3

x=−32 

vậy x=−32 

c) 2x−5−12 =−69 

2x−5−12 =−23 

2x−5−12 =8−12 

⇔2x−5=8

2x=8+5

2x=13

x=132 

vậy x=132