x=-2000           

ta có \(1+\frac{x+5}{1995}+1+\frac{x+4}{1996}+1+\frac{x+3}{1997}=1+\frac{x+1995}{5}+1+\frac{x+1996}{4}+1+\frac{x+1997}{3}\)

        \(=\frac{x+2000}{1995}+\frac{x+2000}{1996}+\frac{x+2000}{1997}=\frac{x+2000}{5}+\frac{x+2000}{4}+\frac{x+2000}{3}\)

     \(=\left(x+2000\right)\left(\frac{1}{1995}+\frac{1}{1996}+\frac{1}{1997}\right)=\left(x+2000\right)\left(\frac{1}{5}+\frac{1}{4}+\frac{1}{3}\right)\)  (1)

                     Xét     \(\frac{1}{1995}+\frac{1}{1996}+\frac{1}{1997}\ne\frac{1}{5}+\frac{1}{4}+\frac{1}{3}vàx+2000=x+2000\) (2)

                                        từ \(\left(1\right)\Leftrightarrow x+2000=0\) ( để (1) là đúng )

                                                          \(\Rightarrow x=2000\)

a) \(\dfrac{1997x1996-1}{1995x1997+1996}=\dfrac{1997x\left(1995+1\right)-1}{1995x1997+1996}\)

\(=\dfrac{1997x1995+1997-1}{1995x1997+1996}=\dfrac{1997x1995+1996}{1995x1997+1996}=1\)

b) \(\dfrac{1997x1996-995}{1995x1997+1002}=\dfrac{1997x\left(1995+1\right)-995}{1995x1997+1002}\)

\(=\dfrac{1997x1995+1997-995}{1995x1997+1002}=\dfrac{1997x1995+1002}{1995x1997+1002}=1\)

\(...=\dfrac{1998x1996+1996+1+1996-1}{\left(1997-1995\right)x1996}\)

\(=\dfrac{1998x1996+2x1996}{2x1996}=\dfrac{1996\left(1998+2\right)}{2x1996}=\dfrac{2000}{2}=1000\)

KQ = 995 nha

995

KQ = 995

Mình mới giải xong, mất tiêu bài rồi KQ=1000

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Mình xin lỗi câu này mình ko biết

(x-5)(1995.1996+1997.1996)=1234.5678.(630-315.2):1996

VP=1234.5678(630-315.2):196

=0

=> (x-5)(1995.1996+1997.1996)=0

=> x-5=0  vì (1995.1996+1997.1996 khác 0)

=> x=5

( x - 5 ) x ( 1995 x 1996 + 1997 x 1996 ) = 1234 x 5678 x ( 630 - 315 x 2 ) : 1996

=( x - 5 ) x ( 1995 x 1996 + 1997 x 1996 ) = 0

=x-5=0:( 1995 x 1996 + 1997 x 1996 )

=x-5=0

x=0+5

x=5

x = 5 vì vế kia bằng 0 thì nếu x = 5 mà 5 - 5 bằng 0 nếu 0 nhân với bất kỳ số nào cũng bằng 0

ủng hộ mình nha

BANG 995 MK NHA BN

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