A/ (-215)+58:(-2)-(+12)
B/ [97+(-30):5+125].(-6)
C/ (-189)+(+55)=|-7|.(-3)-9
D/ {36+[96-(-2)*2-5.6]}-20
Giúp mik với
A, (25-5).(-2) mũ 2 -31.(-7-13)
B, 215+ (-38) -(-58) +90 - 85
C, 26.(-125) -125 . (-36)
D.4. (-3) mũ 3 +2 . (-2)-20
a, = 20.4-31.(-20)
= 80+620
= 700
a.700
b.240
c.1250
d.-132
a) 100 + 98 + 96 + ... + 2 - 97 - 95 - ... - 1
b) 1 + 2 - 3 - 4 + 5 + 6 - 7 - 8 + 9 + 10 - 11 - 12 + ... + 299 - 300 + 301 + 302
c) 2 . 31 . 12 + 4 .6 . 42 + 8 . 27 . 3
d) 36 . 28 + 36 . 82 + 64 . 69 + 64 . 41
e) 99 - 97 + 95 - 93 + 91 - 89 + ...+ 7 - 5 + 3 - 1
a, 100 + 98 + 96 + ... + 2 - 9 7 - 95 - .. -1
= 100 + (98 - 97) + (96-95) + ... + + ... + (2 - 1)
= 100 + 1 + 1 + 1 +.. +1
= 100 + 1 x49
= 100 + 49
= 149
b , 1 + 2 - 3 - 4 + 5 + 6 - .... -299 - 330 +301 + 302
=( 1 + 2 - 3) + ( -4 + 5 + 6 -7 ) +... +(298 - 299 -300 +301 ) + 302
= 0 + 0 + .. + 0 + 302
= 302
c) 2 . 31 . 12 + 4 . 6 . 42 + 8 . 27 . 3
=24.31+24.42+24.27
=24.(31+42+27)
=24.100
=2400
d)
=36x(28+82)+64x(69+41)
=36x110+64x110
=110x(26+64)
=110x100
=11000
d) dãy tính trên có số số tự nhiên là: (99-1):2+1=50(số)
99-97+95-93+91-89+...+7-5+3-1(50:2=25 cặp)
(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1) (25 cặp)
2+2+2+2+2+...+2+2(25 số 2)
2x25=50
Bài 1. Tính hợp lý
1) (–12) +6.(–3)
2) (36 -2020) + (2019 -136) – 27
3) (144 – 97) – (244 – 197)
4) (–24).13 – 24.( –3)
5) 54+55+56+57+58-(64+65+66+67+68)
6) 24(16 – 5) – 16(24 – 5)
7) 47.(23 + 50) – 23.(47 + 50)
8) (-31). 47 + (-31). 52 + (-31)
Bài 2: Tìm số nguyên x, biết:
1)-17-(2x-5)=-6
2) 10-2(4-3x)=-4
3)-12+3(-x+7)=-18
4)-45:[5.(-3-2x)]=3
5) x.(x+3)=0
6) (x-2).(x+4)=0
7) x.(x+1).(x-3)=0
Bài 1:
1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)
\(=-12-18\)
=-30
2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)
\(=36-2020+2019-136-27\)
\(=1-100-27\)
\(=-126\)
3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)
\(=144-97-244+197\)
\(=-100+100=0\)
4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)
\(=-24\cdot13+24\cdot3\)
\(=24\cdot\left(-13+3\right)\)
\(=24\cdot\left(-10\right)=-240\)
5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)
\(=54+55+56+57+58-64-65-66-67-68\)
\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)
\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)
=-50
6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)
\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)
\(=-24\cdot5+16\cdot5\)
\(=5\cdot\left(-24+16\right)\)
\(=-5\cdot8=-40\)
7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)
\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)
\(=47\cdot50-23\cdot50\)
\(=50\cdot\left(47-23\right)\)
\(=50\cdot24=1200\)
8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)
\(=-31\cdot\left(47+52+1\right)\)
\(=-31\cdot100=-3100\)
Bài 2:
1) Ta có: \(-17-\left(2x-5\right)=-6\)
\(\Leftrightarrow-17-2x+5+6=0\)
\(\Leftrightarrow-2x-6=0\)
\(\Leftrightarrow-2x=6\)
hay x=-3
Vậy: x=-3
2) Ta có: \(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x+4=0\)
\(\Leftrightarrow6x+6=0\)
\(\Leftrightarrow6x=-6\)
hay x=-1
Vậy: x=-1
3) Ta có: \(-12+3\left(-x+7\right)=-18\)
\(\Leftrightarrow-12-3x+21+18=0\)
\(\Leftrightarrow-3x+27=0\)
\(\Leftrightarrow-3x=-27\)
hay x=9
Vậy: x=9
4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)
\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)
\(\Leftrightarrow-2x-3=-3\)
\(\Leftrightarrow-2x=0\)
hay x=0
Vậy: x=0
5) Ta có: x(x+3)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-3\right\}\)
6) Ta có: (x-2)(x+4)=0
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)
Vậy: \(x\in\left\{2;-4\right\}\)
7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)
Vậy: \(x\in\left\{0;-1;3\right\}\)
Bài 1:
1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)
=−12−18=−12−18
=-30
2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27
=36−2020+2019−136−27=36−2020+2019−136−27
=1−100−27=1−100−27
=−126
Tớ chcs cậu học thật giỏi nha !
Bài 1: (2,25 điểm) Thực hiện phép tính:
a/ 58 . 32 + 58 . 68 – 800
b/ 12020+ 280 : [ 55 – (7 – 4)3 ]
c/ Bỏ ngoặc rồi tính: (96 – 19 – 45) – (55 + 96-119)
Bài 2: (1,5 điểm) Tìm x, biết:
a/ 7 x – 70 = 105
b/ 85 – 5 ( 4 + x ) = 15
c/ (-44). (x + 20) = -440
Bài 1:
a, 58.32 + 58.68 - 800
= 58.(32 + 68) - 800
= 58.100 - 800
= 5800 - 800
= 5000
b, 12020 + 280 : [55 - (7 - 4)3]
= 12020 + 280 : [ 55 - 33 ]
= 12020 + 280 : [ 28]
= 12020 + 10
= 12030
c, (96 - 19 - 45) - (55 + 96 - 119)
= 96 - 19 - 45 - 55 - 96 + 119
= (96 - 96) + (119 - 19) - (45 + 55)
= 0 + 100 - 100
= 0
Bài 2:
a,7\(x\) - 70 = 105
7\(x\) = 105 + 70
7\(x\) = 175
\(x\) = 175 : 7
\(x\) = 25
1 tìm x
a, -12(x-15)+7.(3-x)=5
b, 30(x+2)-6.(x-5)-24.x=100
2 tìm x,y thuộc Z
a, (x-3).(2y+1)=7
b, (2x+1).(3y-2)=-55
3 tính hợp lí
a 125.(-61).(-2)^3.(-1)^2n (n thuộc N*)
b, 136.(-47)+36.47
c, (-48).72+36.(-304)
Tính nhanh
A.996+44
B.37+198
C.4×55×25×2×5
D.97×36+64×97
E.125+360+75+40
G.10^12÷10^10
a, = 996 + 4 + 40 = 1000 + 40 = 1040
b, = 198 + 2 + 35 = 200 + 35 = 235
c, = ( 4 *25 )*(2 * 5)*55=100 * 10 * 55 = 55000
d, = 97*(36+64) = 97 * 100 = 9700
e, = (125+75)+(360+40)= 200 + 400 = 600
g, =10^2=100
a) \(996+44\)
\(=1040\)
b) \(37+198\)
\(=230\)
\(a,996+44=1040\)
\(d,97.36+64.97=97.\left(36+64\right)=97.100=9700\)
\(b,37+198=235\)
\(c,4.55.25.2.5=220.50.5=11000.5=55000\)
\(e,125+360+75+40=485+115=600\)
\(g,10^{12}:10^{10}=10^2=100\)
a) A=1-2+3-4+5-6+.........+99-100+101
b) B=1+4+5+9+14+......+60+97
c) C=100+98+96+....+2-97-95-.......-1
d) D=1+2-3-4+5+6-7-8+9+10-11-12+.......+299-300+301+302
a) A=1-2+3-4+5-6+.........+99-100+101
=> A = (1-2)+(3-4)+(5-6)+...+(99-100)+101
=> Có 50 cặp và 101
=>A= (-1)+(-1)+(-1)+...+(-1)+101
=>A= (-1).50 + 101
A= -50 + 101
A= 51
bạn có viết rõ đc ko Bastkoo dòng số 3 câu giải đấy
a,6/7 - 5/7 + 4/7 - 3/7 + 2/7 - 1/7 ( B3: Tính = cách thuận tiện nhất )
b, 3/4- 3/5 + 1/4 - 2/5
B4 : so sánh 2 phân số [ >,<,= ]
a, 12/36...1/3 b, 5/4...6/7 c, 7/9...8/9
d,11/15...1/13 1/2...5/10
B5: Đặt tính rồi tính
a, 5/15 + 2/5 b, 2/7 + 12/21 c,16/24 + 5/12 d,1/3 + 1/4 + 5/6
d, 19/24 - 3/8 e,8/9 - 1/3 g,3+1/3 k, 5/8 + 7/4 + 7/12
Bài 5:
a: =1/3+2/5
=5/15+6/15
=11/15
b: =6/21+12/21=18/21=6/7
c: =16/24+10/24
=26/24
=13/12
d: =4/12+3/12+10/12
=17/12
e: =19/24-9/24
=10/24
=5/12
f: =8/9-3/9=5/9
g: =9/3+1/3=10/3
k: =15/24+42/24+14/24
=71/24
Bai 7 : tinh
a) (-7) + (-12) +166
b) 120- (-24) +(-35)
c) (-264) + (-36) + 500
d)58 + 97 +(-58) + (- 47)
e) (-2) + 8 +(- 14) +20 +(-26) + 32 +(-38) + 44
k) 53 + (-76) - (-76) + (-53)
l) [(-18) + 7]+ (-111)+66
h) - (138-63+17) + (-163 + 38) -(-17)
g) 215 + (-38) - (-58) +90 - 85
h) 31-26 -21- (-56)
j) (-34) +(-84) - (-134)+(-1)
cac ban giup duoc mik cau nao thi giup nhung ma het cang tot !!
ai giup mik het mik se tick va ket ban vs ban do !
a) (-7)+(-12)+166 = -(7+12)+166=-19+166=147
b) 120-(-24)+(-35) = 120+24-35=109
c) (-264)+(-36)+500=-300+500=200
d)58+97+(-58)+(-47) = [58+(-58)]+(97-47)=0+50=50
e) (-2)+8+(-14)+20+(-26)+32+(-38)+44 = (-2+8)+(-14+20)+(-26+32)+(-38+44) = 6+6+6+6=24
k) 53 + (-76) - (-76) + (-53) = [53+(-53)]+[(-76)+76] = 0+0=0
l) [(-18)+7] + (-111)+66 = -11 + (-45) = -66
h) -(138-63+17)+(-163+38)-(-17) = -138 + 63 - 17 + (-163)+38 + 17 = -138+38 + 63+(-163) -17+17 = -100+(-100) - 0 = -200
g) 215+(-38) - (-58) + 90 - 85 = 215 - 38 + 58 +90 - 85 = 215- 85 + 58 - 38 +90 = 130+20+90=240
j) (-34)+(-84)-(-134)+(-1) = -(34+84+1) + 134 = 15