x2_x+6
x[x2_y]_x2[x+y]+y[x2_x]
GTNN:
A= x2+2x+5
B= x2_x+1
C= 5x2+5x+1
D= 3x2+4x+2
E= 1/2x2+x_1
F= 1/9x2+3x+2
\(A=x^2+2x+5=\left(x^2+2x+1\right)+4=\left(x+1\right)^2+4\ge4\)
Kl: MinA = 4
\(B=x^2-x+1=\left(x^2-2\cdot\dfrac{1}{2}x+\dfrac{1}{4}\right)+\dfrac{3}{4}=\left(x-\dfrac{1}{2}\right)^2+\dfrac{3}{4}\ge\dfrac{3}{4}\)
kl:.......
\(C=5x^2+5x+1=5\left(x^2+2\cdot\dfrac{1}{2}x+\dfrac{1}{4}\right)+1-\dfrac{5}{4}=5\left(x+\dfrac{1}{2}\right)^2-\dfrac{1}{4}\ge-\dfrac{1}{4}\)
kl:.......
\(D=3x^2+4x+2=3\left(x^2+2\cdot\dfrac{2}{3}x+\dfrac{4}{9}\right)+2-\dfrac{4}{3}=3\left(x+\dfrac{2}{3}\right)^2+\dfrac{2}{3}\ge\dfrac{2}{3}\)
kl:......
\(E=\dfrac{1}{2}\cdot x^2+x-1=\dfrac{1}{2}\left(x^2+2x+1\right)-1-\dfrac{1}{2}=\dfrac{1}{2}\left(x+1\right)^2+\dfrac{3}{2}\ge\dfrac{3}{2}\)
kl:............
\(F=\dfrac{1}{9}x^2+3x+2=\dfrac{1}{3}\left(x^2+2\cdot\dfrac{1}{2}x+\dfrac{1}{4}\right)+2-\dfrac{1}{12}=\dfrac{1}{3}\left(x+\dfrac{1}{2}\right)^2+\dfrac{23}{12}\ge\dfrac{23}{12}\)
kl:..........
15+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+
\(15+\left(6\times24\right)=15+144\)
\(=159\)
ko tính dc lổi r thừa dấu cộng kìa oh my chuối
6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6=?
6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6+6=?
=114
^_^
6-6-6-6-6++6+6+6+6+6+6+6+6+6=x
6-6+6-6+6-6+6-6-6+6-6-6
6-6+6-6+6-6+6-6-6+6-6-6
=6-6-6+6-6-6
=0-0-6=-6
Tính nhẩm
6 + 1 = ..... 6 + 6 = .....
6 + 0 = ..... 6 + 2 = .....
6 + 7 = ..... 7 + 6 = .....
6 + 3 = ..... 6 + 8 = .....
8 + 6 = ..... 6 + 4 = .....
6 + 9 = ..... 9 + 6 = .....
6 + 5 = ..... 6 + 10 = .....
10 + 6 = .....
Phương pháp giải:
Thực hiện phép cộng các số rồi điền kết quả vào chỗ trống.
Lời giải chi tiết:
6 + 1 = 7 6 + 6 = 12
6 + 0 = 6 6 + 2 = 8
6 + 7 = 13 7 + 6 = 13
6 + 3 = 9 6 + 8 = 14
8 + 6 = 14 6 + 4 = 10
6 + 9 = 15 9 + 6 = 15
6 + 5 = 11 6 + 10 = 16
10 + 6 = 16
6+1=7 6+0=6
6+2=8
6+3=9
6+4=10
6+5=11
6+6=12
6+7=13
6+8=14
6+9=15
6+10=16
6 mũ 6 + 6 mũ 6 + 6 mũ 6 + 6 mũ 6 + 6 mũ 6 + 6 mũ 6
\(6^6+6^6+6^6+6^6+6^6+6^6\)
\(=\left(1+1+1+1+1+1\right)\cdot6^6\)
\(=6\cdot6^6\)
\(=6^7\)
6^6+6^6+6^6+6^6+6^6+6^6= cho minh cach giai biet dap an bang 6^7
\(6^6+6^6+6^6+6^6+6^6+6^6=6^6.6=6^7\)
Mình rút ra được công thức sau
\(a^n.a^n.a^n.......a^n=a^{n+1}\)
n số an
6+6+6+6+6+6+6+6+6+6